6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A typist uses a sheet measuring 20cm by 30cm lengthwise.If a margin of 2 cm is left on each side and a 3 cm margin on top and bottom, then percent of the page used for typing is

A) 64%	B) 74%
C) 84%	D) 94%

Answer & Explanation Answer: A) 64%

Explanation:

Area of the sheet = $(20 \times 30) c m^{2}$

Area used for typing = $[(20 - 4) \times (30 - 6)] c m^{2}$

required % = $\frac{384}{600} \times 100$ =64%

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Filed Under: Area
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21 18648

Q:

Three cats are roaming in a zoo n such a way that when cat A takes 5 steps, B takes 6 steps and C takes 7 steps.But the 6 steps of A are equal to the 7 steps of B and 8 steps of C. what is the ratio of their speeds?

A) 140:144:147	B) 40:44:47
C) 15:21:28	D) 252:245:240

Answer & Explanation Answer: A) 140:144:147

Explanation:

Frequency of step of A:B:C = 5 : 6 : 7

But in terms of size of step, 6A = 7B = 8C

Therefore, Ratio of speeds of A, B and C = 5/6 : 6/7 : 7/8 = 140 : 144 : 147

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Filed Under: Ratios and Proportions

45 18622

Q:

Four pipes P,Q, R and S can fill a cistern in 20,25, 40 and 50 hours respectively.The first pipe P was opened at 6:00 am, Q at 8:00 am, R at 9:00 am and S at 10:00 am. when will the Cistern be full?

A) 4:18 pm	B) 3:09 pm
C) 12:15 pm	D) 11:09 am

Answer & Explanation Answer: B) 3:09 pm

Explanation:

Efficiency of P= 100/20= 5% per hour

Efficiency of Q= 100/25= 4% per hour

Efficiency of R= 100/40= 2.5% per hour

Efficiency of S=100/50= 2% per hour

Cistern filled till 10 am by P, Q and R

$\begin{matrix} Till 10.00 am Pipe P filled 20 % \\ Till 10.00 am Pipe Q filled 8 % \\ Till 10.00 am Pipe R filled 2.5 % \end{matrix}\} 30.5 %$

Thus, at 10 am pipe P,Q and R filled 30.5% of the cistern.

Rest of cistern to be filled = 100 - 30.5 = 69.5%

Now, the time taken by P,Q,R and S together to fill the remaining capacity of the cistern

= 69.5 / (5+4+2.5+2) = 5 Hours and 9 minutes(approx).

Therefore, total time =4 hrs + 5hrs 9 mins = 9 hrs and 9 mins

It means cistern will be filled up at 3:09 pm

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Filed Under: Time and Work

21 18586

Q:

If two dice are thrown together, the probability of getting an even number on one die and an odd number on the other is ?

A) 1	B) 1/2
C) 0	D) 3/5

Answer & Explanation Answer: B) 1/2

Explanation:

The number of exhaustive outcomes is 36.
Let E be the event of getting an even number on one die and an odd number on the other. Let the event of getting either both even or both odd then = 18/36 = 1/2
P(E) = 1 - 1/2 = 1/2.

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Filed Under: Probability
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17 18571

Q:

How many times do the hands of a clock coincide in a day?

A) 20	B) 21
C) 22	D) 23

Answer & Explanation Answer: C) 22

Explanation:

The hands of a clock coincide 11 times in every 12 hours (Since between 11 and 1, they
coincide only once, i.e., at 12 o'clock).

The hands overlap about every 65 minutes, not every 60 minutes.
The hands coincide 22 times in a day.

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Filed Under: Clocks
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23 18571

Q:

If log 64 = 1.8061, then the value of log 16 will be (approx)?

A) 1.9048	B) 1.2040
C) 0.9840	D) 1.4521

Answer & Explanation Answer: B) 1.2040

Explanation:

Given that, log 64 = 1.8061

i.e $\log (4^{3}) = 1.8061$

--> 3 log 4 = 1.8061

--> log 4 = 0.6020

--> 2 log 4 = 1.2040

$\Rightarrow \log (4^{2}) = 1.2040$

Therefore, log 16 = 1.2040

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Filed Under: Logarithms
Exam Prep: CAT
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51 18564

Q:

Ratio of the ages of Mahesh and Nilesh is 5 : x. Mahesh is 18 years younger to Ramesh. After nine years Ramesh will be 47 years old. If the difference between the ages of Mahesh and Nilesh is same as the age of Ramesh, what is the value of x ?

A) 11.8	B) 12.9
C) 13.7	D) 14.5

Answer & Explanation Answer: D) 14.5

Explanation:

Let the present ages of Mahesh, Nilesh and Ramesh be k, l and m respectively.
k/l = 5/x ------ (1)
k = m - 18 ------ (2)
m + 9 = 47 ------ (3)
k - l = m ----- (4)
(3) => m = 47 - 9 = 38 years
(2) => k = 38 -18 = 20 years
(1) => 20/l = 5/x => l = 4x
(4) => 4x - 20 = 38
=> 4x = 58 => x = 14.5

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Filed Under: Problems on Ages
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27 18546

Q:

The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq.cm. Find the length of the rectangle?

A) 10cm	B) 20cm
C) 30cm	D) 40cm

Answer & Explanation Answer: B) 20cm

Explanation:

Let the breadth of the given rectangle be x then length is 2x.
thus area of the given rect is $2 x^{2}$

after dec 5cm from length and inc 5cm breadth , new lenght becomes 2x-5 and breadth is x+5.thus new area =(2x-5)(x+5)= $2 x^{2} + 5 x - 25$

since new area is 75 units greater than original area thus
$2 x^{2} + 75 = 2 x + 5 x - 25$
5x=75+25
5x=100
therefore x=20
hence length of the rectangle is 40 cm.

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Filed Under: Area
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29 18540

Quantitative Aptitude - Arithmetic Ability Questions

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