Quantitative Aptitude - Arithmetic Ability Questions

Q:

A bag contains 50 P, 25 P and 10 P coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type respectively.

A) 360, 160, 200 B) 160, 360, 200
C) 200, 360,160 D) 200,160,300
 
Answer & Explanation Answer: C) 200, 360,160

Explanation:

let ratio be x.

Hence no. of coins be 5x ,9x , 4x respectively

Now given total amount = Rs.206

=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206

we get x = 40

=> No. of 50p coins = 200

=> No. of 25p coins = 360

=> No. of 10p coins = 160

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Filed Under: Ratios and Proportions

2032 232085
Q:

Insert the missing number.

7, 26, 63, 124, 215, 342, (....)

A) 391 B) 421
C) 481 D) 511
 
Answer & Explanation Answer: D) 511

Explanation:

Numbers are (23 - 1), (33 - 1), (43 - 1), (53 - 1), (63 - 1), (73 - 1) etc.

So, the next number is (83 - 1) = (512 - 1) = 511.

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Filed Under: Odd Man Out

400 231219
Q:

Find the odd man out.

41, 43, 47, 53, 61, 71, 73, 81

A) 41 B) 61
C) 71 D) 81
 
Answer & Explanation Answer: D) 81

Explanation:

Each of the numbers except 81 is a prime number.

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Filed Under: Odd Man Out

167 226702
Q:

If the length of the diagonal of a square is 20cm,then its perimeter must be

a. 402cm     b. 302cm    c. 10cm    d. 152cm

A) a B) b
C) c D) d
 
Answer & Explanation Answer: A) a

Explanation:

We know that d=√2s 

Given diagonal = 20 cm 

=> s = 20/2 cm

Therefore, perimeter of the square is 4s = 4 x 20/2 = 402   cm.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

83 218245
Q:

A problem is given to three students whose chances of solving it are 1/2, 1/3 and 1/4 respectively. What is the probability that the problem will be solved?

A) 1/4 B) 1/2
C) 3/4 D) 7/12
 
Answer & Explanation Answer: C) 3/4

Explanation:

Let A, B, C be the respective events of solving the problem and A , B, C be the respective events of not solving the problem. Then A, B, C are independent event

A, B, C are independent events

Now,  P(A) = 1/2 , P(B) = 1/3 and P(C)=1/4

 PA=12, PB=23, PC= 34

 P( none  solves the problem) = P(not A) and (not B) and (not C)  

                  = PABC 

                  = PAPBPC          A, B, C are Independent                       

                  =  12×23×34  

                  = 14  

Hence, P(the problem will be solved) = 1 - P(none solves the problem) 

                = 1-14= 3/4

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Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

1017 207920
Q:

25% of 25% Is Equal To

 

A) 0.0625 B) 0.0210
C) 0.03145 D) 0.3210
 
Answer & Explanation Answer: A) 0.0625

Explanation:

25% of 25% means

 

 

 

25/100 of 25/100

 

 

 

i.e, 1/4 of 1/4

 

 

 

or in other words 1/4 x 1/4=1/16

 

 

 

Hence, the answer is 1/16 = 0.0625.

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Filed Under: Percentage
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

74 201743
Q:

Simplify  

1.53 + 4.73 + 3.83 - 3 x 1.5 x 4.7 x 3.81.52 + 4.72 + 3.82 - 1.5 x 4.7 - 4.7 x 3.8 - 1.5 x 3.8

A) 6 B) 8
C) 10 D) 12
 
Answer & Explanation Answer: C) 10

Explanation:

Apply a3 + b3 + c3 - 3abca2 + b2 + c2 - ab - bc - ca = a + b + c

 

Hence the answer is  1.5 + 4.7 + 3.8 = 10.

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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

34 199845
Q:

Find the odd man out?

396, 462, 572, 427, 671, 264.

A) 671 B) 462
C) 427 D) 264
 
Answer & Explanation Answer: C) 427

Explanation:

Here the given series is 396, 462, 572, 427, 671, 264.

In all the terms, the middle digit is the sum of first and third digit except 427.

 

So the Odd number in the given series is 427.

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Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

119 197526