6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Water flows into a tank which is 200 m long and 150 m wide, through a pipe of cross-section (0.3m x 0.2m) at 20 km/h. In what time will the water level be 12m ?

A) 200 hrs	B) 240 hrs
C) 300 hrs	D) 270 hrs

Answer & Explanation Answer: C) 300 hrs

Explanation:

Volume of water collected in the tank in 1 hour

⇒ (0.3 × 0.2 × 20km × 1000mts) = 1200 m cubic

If after t hours, the water is at height of 12m,

1200t=200×150×12

⇒ t = 300 Hours.

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Filed Under: Pipes and Cistern
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25 12716

Q:

A bag contains 7 green and 5 black balls. Three balls are drawn one after the other. The probability of all three balls being green, if the balls drawn are not replaced will be:

A) 123/897	B) 23/67
C) 7/44	D) 12/45

Answer & Explanation Answer: C) 7/44

Explanation:

Here, n(E) = $7 C_{1} \times 5 C_{1} \times 5 C_{1}$

And, n(S) = $12 C_{1} * 11 C_{1} * 10 C_{1}$

P(S) = $\frac{7 * 6 * 5}{12 * 11 * 10}$ = 7/44

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Filed Under: Probability

13 12712

Q:

A man invests some money partly in 9% stock at 96 and partly in 12% stock at 120. To obtain equal dividends from both, he must invest the money in the ratio:

A) 3:5	B) 2:1
C) 16:15	D) 4:5

Answer & Explanation Answer: C) 16:15

Explanation:

For an income of Re. 1 in 9% stock at 96, investment = Rs. 96/9 = Rs.32/3

For an income Re. 1 in 12% stock at 120, investment = Rs. 120/12 = Rs. 10.

Ratio of investments =(32/3) : 10 = 32 : 30 = 16 : 15.

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Filed Under: Stocks and Shares

5 12712

Q:

Rajeev start a business with Rs. 10000, Deepu joins him after 2 month with 20% more investment than Rajeev, after 2 month Shakti joins him with 40% less than Deepu. If the profit earned by them at the end of the year is equal to the twice of the difference between investment of Rajeev and ten times the investment of Shakti. Find the profit of Rajeev ?

A) 50000	B) 48000
C) 38000	D) 40000

Answer & Explanation Answer: C) 38000

Explanation:

Here from the given information,

The ratio of investments of Rajeev, Deepu & Shakti is

R : D : S = (10000 × 12) : (12000 × 10) : (7200 × 8)

= 25 : 25 : 12

Now the Profit = 2 × (72000-10000) = 124000

Share of Rajeev = 124000 x 25/62 = 48000

Profit of Rajeev = 48000 - 10000 = 38000

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Filed Under: Partnership
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21 12697

Q:

At an examination in which maximum marks are 500. P got 10% less than Q, Q got 25% more than R and R got 20% less than S. If P got 360 marks what percentage of marks was obtained by S ?

A) 77	B) 74
C) 80	D) 83

Answer & Explanation Answer: C) 80

Explanation:

Let marks obtained by S = M

R's marks = 0.80M

Q's marks = 1.25 (0.80M)

P's marks = (0.90) (1.25) (0.80M)

= 0.9M

But 0.9M = 360

M = ?

M = 400

Hence % of marks obtained by S

= 400/500 x 100 = 80%.

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Filed Under: Percentage
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11 12692

Q:

A trader marked the price of the T.V. 30% above the cost price of the T.V. and gave the purchaser 10% discount on the marked price, thereby gaining Rs.340. Find the cost price of the T.V ?

A) Rs. 2000	B) Rs. 1600
C) Rs. 2200	D) Rs. 2100

Answer & Explanation Answer: A) Rs. 2000

Explanation:

Let 'x' be the cost price.
Now Marked price = x + 30x/100 = 13x/10
10% discount = 10/100 x 13x/10 = 13x/100
Selling price = 13x/10 - 13x/100 = 117x/100
Given gain = 340
Here gain = 117x/100 - x = 17x/100 = 340 => x = Rs. 2000.

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT
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13 12683

Q:

Karthik read $\frac{6}{13}$ th of a book in 1st week and $\frac{5}{9}$ th of the remaining book in 2nd week. If there were 100 pages unread after 2nd week, how many pages were there in the book ?

A) 404	B) 415
C) 418	D) 420

Answer & Explanation Answer: C) 418

Explanation:

Let the total book be 1

Then, in the 1st week $\frac{6}{13}$ th of book is read

i.e remaining pages = $1 - \frac{6}{13} = \frac{7}{13}$

in 2nd week he read $\frac{5}{9}$ th of it

i.e $\frac{5}{9} \times \frac{7}{13} = \frac{35}{117}$
Remaining pages after 2nd week = $\frac{7}{13} - \frac{35}{117} = \frac{28}{117}$

But given remaining pages after 2nd week = 100

$\frac{28 x}{117} = 100$

--> x = 418

The total pages in the book are 418

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Filed Under: Decimal Fractions
Exam Prep: GATE , CAT , Bank Exams
Job Role: Bank PO , Bank Clerk

17 12670

Q:

The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. what is the age of the youngest child ?

A) 4	B) 8
C) 10	D) None

Answer & Explanation Answer: A) 4

Explanation:

Let x = the youngest child. Each of the other four children will then be x+3, x+6, x+9, x+12.

We know that the sum of their ages is 50 .

so, x+(x+3)+(x+6)+(x+9)+(x+12) = 50

=> x= 4

The youngest child is 4 years old.

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Filed Under: Problems on Ages

42 12630

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