6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

What smallest number of 6 digit is divisible by 111?

Answer

Smallest number of 6 digits is 100000

on dividing 100000 by 111 we get 100 as remainder

$\inline \fn_jvn \therefore$ Number to be added = (111 -100) = 11

$\inline \fn_jvn \therefore$ Required Number = 100011

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Subject: Numbers

44 11709

Q:

The average of 9 results is 50. The average of first four results is 52 and average of last four results is 49 . what is the fifth result?

Answer

Total of results = 50 x 9 = 450

Total of first four results = 52 x 4 = 208

Total of Last four results = 49 x 4 = 196

Hence the fifth result = 450 - (208 + 196) = 46

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Subject: Average

22 11707

Q:

The average age of a couple is 24 years when they were married five years ago but now the average age of the husband, wife and child is 20 years(the child was born during the interval). What is the present age of the child ?

A) 2 yrs	B) 4 yrs
C) 3 yrs	D) 5 yrs

Answer & Explanation Answer: A) 2 yrs

Explanation:

29 x 2 = 58
20 x 3 = 60
-----------
2 years

Therefore, the age of child is 2 years.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

18 11700

Q:

Four dice are thrown simultaneously. Find the probability that two of them show the same face and remaining two show the different faces.

A) 4/9	B) 5/9
C) 11/18	D) 7/9

Answer & Explanation Answer: B) 5/9

Explanation:

Select a number which ocurs on two dice out of six numbers (1, 2, 3, 4, 5, 6). This can be done in ${}^{6}C_{1}$ , ways.

Now select two distinct number out of remaining 5 numbers which can be done in ${}^{5}C_{2}$ ways. Thus these 4 numbers can be arranged in 4!/2! ways.

So, the number of ways in which two dice show the same face and the remaining two show different faces is

${}^{6}C_{1} \times {}^{5}C_{2} \times \frac{4!}{2!} = 720$

=> n(E) = 720

$∴ P (E) = \frac{720}{6^{4}} = \frac{5}{9}$

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Filed Under: Probability

8 11672

Q:

If $3^{x - y} = 27$ , $3^{x + y} = 243$ then find the x value

A) 2	B) 8
C) 4	D) 1

Answer & Explanation Answer: C) 4

Explanation:

Given that $3^{x - y} = 27$ , $3^{x + y} = 243$

$\Rightarrow 3^{x - y} = 3^{3}, 3^{x + y} = 3^{5}$

=> x-y=3, x+y=5

=> x = 4

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Filed Under: Simplification
Exam Prep: CAT
Job Role: Bank Clerk

15 11663

Q:

At a certain rate of interest the compound interest of 3 years and simple interest of 5 years for certain sum of money is respectively Rs. 1513.2 and Rs. 2400. Find the common rate of interest per annum ?

A) 5%	B) 6%
C) 4%	D) 3%

Answer & Explanation Answer: A) 5%

Explanation:

Given compound interest for 3 years = Rs. 1513.2

and simple interest for 5 years = Rs. 2400

Now, we know that C.I = $[P {(1 + \frac{R}{100})}^{n} - 1]$

=> 1513.2 = $[P {(1 + \frac{R}{100})}^{3} - 1]$ ...........(A)

And S.I = PTR/100

=> 2400 = P5R/100 ..................(B)

By solving (A) & (B), we get

R = 5%.

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Filed Under: Compound Interest
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

18 11622

Q:

The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles ?

A) 2413 sq.m	B) 1234 sq.m
C) 4312 sq.m	D) 2143 sq.m

Answer & Explanation Answer: C) 4312 sq.m

Explanation:

Let the radii of the smaller and the larger circles be 's' m and 'l' m respectively.

$2 πs$ = 264 and $2 πl$ = 352

s = $\frac{264}{2 π}$ and l = $\frac{352}{2 π}$

Difference between the areas = $π l^{2} - π s^{2}$

= $π (\frac{176^{2}}{π^{2}} - \frac{132^{2}}{π^{2}})$

= $\frac{1762}{π} - \frac{1322}{π}$

= (176 - 132)(176 + 132) / $π$

= (44 x 308) / (22/7) = 4312 sq.m

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Filed Under: Volume and Surface Area
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

18 11619

Q:

Rs 1000 is being charged at 50% per annum. what is the interest for 3rd year at compound interest?

A) 1122	B) 1025
C) 1125	D) 625

Answer & Explanation Answer: C) 1125

Explanation:

Total amount for two years = $1000 \times {(1.5)}^{2} = 2250$

Now , interest for third year = $\frac{2250 \times 50 \times 1}{100} = 1125$

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Filed Under: Compound Interest

16 11615

Quantitative Aptitude - Arithmetic Ability Questions

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