Quantitative Aptitude - Arithmetic Ability Questions

Q:

If (1 / 2.315) = 0.4319, find the value of (1 / 0.0002315).

 

A) 4319 B) 2315
C) 431.9 D) 231.5
 
Answer & Explanation Answer: A) 4319

Explanation:
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Filed Under: Decimal Fractions
Exam Prep: Bank Exams

2 10559
Q:

A group of men can complete a job in K hours. After every 4 hours, half the number of men working at that point of time leave the job. Continuing this way if the job is finished in 16 hours, what is the value of K ?

A) 7 hrs B) 7.5 hrs
C) 8 hrs D) 8.25 hrs
 
Answer & Explanation Answer: B) 7.5 hrs

Explanation:

Let there are L men

job requires LK man hours.

 

job completed in first 4 hrs = L x 4 = 4L

job completed in next 4 hrs = 4 x L/2 = 2L

job completed in next 4 hrs = 4 x L/4 = L

job completed in last 4 hrs = 4 x L/8 = L/2

4L + 2L + L + L/2 = KL

K = 7+1/2 = 7.5 hours.

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Filed Under: Time and Work
Exam Prep: TOEFL , GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

5 10555
Q:

How many ways are there to select a subcommittee of 7 members from among a committee of 17?

A) 19000 B) 19448
C) 19821 D) 19340
 
Answer & Explanation Answer: B) 19448

Explanation:

Since it does not matter what order the committee members are chosen in, the combination formula is used.

 

Committees are always a combination unless the problem states that someone like a president has higher hierarchy over another person. If the committee is ordered, then it is a permutation.

 

C(17,7)= 19,448

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1 10552
Q:

Rajan's present age is three times his daughter's and nine-thirteenth of his mother's present age. The sum of the present ages of all three of them is 125 years. What is the difference between the present ages of Rajan's daughter and Rajan's mather ?

A) 32 years B) 48 years
C) 62 years D) 50 years
 
Answer & Explanation Answer: D) 50 years

Explanation:

Let Rajan's present age be 'x' years.
=> Then his daughter's present age is = x/3 years.
His mother's present age = 13x/9 years
Now, according to the question,
x + x/3 + 13x/9 = 125
=> x = 125x9/25 = 45
Therefore, required difference = 13x/9 - x/3 = 13x - 3x/9 = 10x/9
=> 10 x 45/9 = 50 years.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

10 10525
Q:

R enter into a partnership in the ratio 2 : 3 : 5 . After 2 months, P increases his share 20% and Q by 10%. If the total profit at the end of one year is Rs 1,90,500, what amount will 'R' receive at the end of year as share in profit ?

A) Rs. 90500 B) Rs. 87500
C) Rs. 88900 D) Rs. 90000
 
Answer & Explanation Answer: D) Rs. 90000

Explanation:

Ratio of investments for 1 year

=> (P : Q : R) = (2x2 + 2.4x10) : (3x2 + 3.3x10) : (5x12)

=> (P : Q : R) = 28 : 39 : 60

Now R share = 190500 x 60/127 = Rs. 90000.

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Filed Under: Partnership
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

10 10519
Q:

An item is sold at a loss of 10%. Had it sold for Rs. 9 more, a profit of 25/2% would have gained. What is the cost price of the item?

A) Rs. 90 B) Rs. 75
C) Rs. 55 D) Rs. 40
 
Answer & Explanation Answer: D) Rs. 40

Explanation:

Let the cost price of the item = Rs. 50

Sold at 10% loss => for Rs. 50 loss  S.P = Rs. 45

From the  given data,

25/2 % gain if it is sold at Rs. 9 more

56.25 - 45 = 9

=> 11.25 = 9

=> 22.5 = 18

=> 45 = 36

=> 50 = ?

=> C.P = 50 x 3645 = 40

 

Hence, the Cost price of the item = Rs. 40.

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

15 10517
Q:

On 19th June, 1984 Monday falls. What day of the week was it on 19th June, 1985?

A) Sunday B) Monday
C) Tuesday D) Wednesday
 
Answer & Explanation Answer: C) Tuesday

Explanation:

The year 1985 is an ordinary year. So, it has 1 odd day.

So, the day on 19th June, 1985 will be 1 day after the day on 19th June, 1984.

But, 19th June,1984 is Monday

S0, 19th June, 1985 is Tuesday.

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Filed Under: Calendar

25 10510
Q:

A single reservoir supplies the petrol to the whole city, while the reservoir is fed by a single pipeline filling the reservoir with the stream of uniform volume. When the reservoir is full and if 40,000 liters of petrol is used daily, the suply fails in 90 days.If 32,000 liters of petrol is used daily, it fails in 60 days. How much petrol can be used daily with out the supply ever failing? 

A) 64000 liters B) 56000 liters
C) 78000 liters D) 60000 liters
 
Answer & Explanation Answer: B) 56000 liters

Explanation:

Let x liter be the per day filling and v litr be the capacity of the reservoir, then 

      90x + v = 40000 * 90     -----(1)

      60x + v= 32000 * 60     ------(2)

solving eq.(1) and (2) , we get

      x = 56000

Hence , 56000 liters per day can be used without the failure of supply.

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Filed Under: Time and Work

8 10509