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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

The calendar for the year 2020 will be the same for the year

A) 2040 B) 2076
C) 2096 D) 2044
 
Answer & Explanation Answer: D) 2044

Explanation:
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Filed Under: Calendar
Exam Prep: Bank Exams

63 10301
Q:

Sheila works 8 hours per day on Monday, Wednesday and Friday, and 6 hours per day on Tuesday and Thursday. She does not work on Saturday and Sunday. She earns $324 per week. How much does she earn in dollars per hour?

A) 11 B) 10
C) 9 D) 8
 
Answer & Explanation Answer: C) 9

Explanation:

Total hours worked = 8 x 3 + 6 x 2 = 36

Total earned = 324. Hourly wage = 324 / 36 = 9

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: GRE

2 10292
Q:

In how many ways the letters of the word 'DESIGN' can be arranged so that no consonant appears at either of the two ends?

A) 240 B) 72
C) 48 D) 36
 
Answer & Explanation Answer: C) 48

Explanation:

DESIGN = 6 letters

 

No consonants appear at either of the two ends. 

= 2 x 4P4 =  2 x 4 x 3 x 2 x 1=  48

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Filed Under: Permutations and Combinations
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

10 10291
Q:

A single reservoir supplies the petrol to the whole city, while the reservoir is fed by a single pipeline filling the reservoir with the stream of uniform volume. When the reservoir is full and if 40,000 liters of petrol is used daily, the suply fails in 90 days.If 32,000 liters of petrol is used daily, it fails in 60 days. How much petrol can be used daily with out the supply ever failing? 

A) 64000 liters B) 56000 liters
C) 78000 liters D) 60000 liters
 
Answer & Explanation Answer: B) 56000 liters

Explanation:

Let x liter be the per day filling and v litr be the capacity of the reservoir, then 

      90x + v = 40000 * 90     -----(1)

      60x + v= 32000 * 60     ------(2)

solving eq.(1) and (2) , we get

      x = 56000

Hence , 56000 liters per day can be used without the failure of supply.

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Filed Under: Time and Work

8 10288
Q:

If you deposit $8000 into an account paying 7% annual interest compounded quarterly, how long until there is $12400 in the account?

A) 2.3 B) 3.3
C) 4.3 D) 6.3
 
Answer & Explanation Answer: D) 6.3

Explanation:

 

 

FV=P(1+r/n)^nt

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

7 10283
Q:

Rajan's present age is three times his daughter's and nine-thirteenth of his mother's present age. The sum of the present ages of all three of them is 125 years. What is the difference between the present ages of Rajan's daughter and Rajan's mather ?

A) 32 years B) 48 years
C) 62 years D) 50 years
 
Answer & Explanation Answer: D) 50 years

Explanation:

Let Rajan's present age be 'x' years.
=> Then his daughter's present age is = x/3 years.
His mother's present age = 13x/9 years
Now, according to the question,
x + x/3 + 13x/9 = 125
=> x = 125x9/25 = 45
Therefore, required difference = 13x/9 - x/3 = 13x - 3x/9 = 10x/9
=> 10 x 45/9 = 50 years.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

10 10272
Q:

Train X crosses a stationary train Y in 60 seconds and a pole in 25 seconds with the same speed. The length of the train X is 300 m. What is the length of the stationary train Y ?

A) 360 m B) 420 m
C) 460 m D) 320 m
 
Answer & Explanation Answer: B) 420 m

Explanation:

Let the length of the stationary train Y be LY
Given that length of train X, LX = 300 m
Let the speed of Train X be V.
Since the train X crosses train Y and a pole in 60 seconds and 25 seconds respectively.
=> 300/V = 25 ---> ( 1 )
(300 + LY) / V = 60 ---> ( 2 )
From (1) V = 300/25 = 12 m/sec.
From (2) (300 + LY)/12 = 60
=> 300 + LY = 60 (12) = 720
=> LY = 720 - 300 = 420 m
Length of the stationary train = 420 m

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

7 10266
Q:

The probability that z lies between 0 and 3.01

A) 0.4987 B) 0.5
C) 0.9987 D) 0.1217
 
Answer & Explanation Answer: A) 0.4987

Explanation:

Probability between z = 0 and z = 3.01 is given by

P(0<z<3.01) = P(z<3.01) - P(z<0)

Reading from the z-table, we have

P(z<0) = 0.5

P(z<3.01) = 0.9987

Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987.

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Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

37 10252