Quantitative Aptitude - Arithmetic Ability Questions

Q:

When the two hands are at right angles, they are ---------- minute spaces apart,

A) 13 B) 14
C) 15 D) 16
 
Answer & Explanation Answer: C) 15

Explanation:

 

 

 

 

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Q:

A rectangular lawn of dimensions 80 m x 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m ?

A) Rs. 3600 B) Rs. 3800
C) Rs. 3900 D) Rs. 3700
 
Answer & Explanation Answer: C) Rs. 3900

Explanation:

Area = (l + b – d) d

= (80 + 60 – 10)10

=> 1300 sq.mts

=> 1300 x 3 = Rs.3900

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Q:

Rajitha invested 25% more than Santhosh. Santhosh invested 30% less than Raju, who invested Rs. 6,000. What is the ratio of the amount that Rajitha invested to the total amount invested by all of them together ?

A) 25 : 114 B) 35 : 103
C) 15 : 108 D) 41 : 94
 
Answer & Explanation Answer: B) 35 : 103

Explanation:

Santhosh's investment = 6000 x 70/100 = Rs.4200
Rajitha's investment = 4200 x 5/4 = Rs.5250
Therefore, total amount invested = 6000 + 4200 + 5250 = Rs.15450.
Required ratio = 5250 : 15450 = 35 : 103.

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Q:

A circular piece of thin wire is converted into a rhombus of side 11 cm. Find the diameter of the circular piece?

A) 28 cm B) 3.5 cm
C) 7 cm D) 14 cm
 
Answer & Explanation Answer: D) 14 cm

Explanation:

Circular piece is 4 x 11 = 44 cm long,

Then Circumference of circle is given by,

44 = pi x D, where D is the diameter

D = 44 / pi

Take pi = 22 / 7, then

D = 44 / (22/7) = (44 x 7) / 22

D = 14 cm.

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Q:

A mixture contains 25% milk and rest water. What percent of this mixture must taken out and replaced with milk so that in mixture milk and water may become equal. 

A) 31.8% B) 31%
C) 33.33% D) 29.85%
 
Answer & Explanation Answer: C) 33.33%

Explanation:

Now, take percentage of milk and applying mixture rule

25          100

       50

50            25  = 2 : 1

 

Hence required answer =  1/3 or 33.33%

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Q:

In a mixture of three varities of oils , the ratio of their weight is 4 : 5 : 8. If 5 kg of oils of the first variety, 10 kg of the second variety and some quantity of oils of the third variety are added to the mixture, the ratio of the weights of three varieties of oils becomes as 5 : 7 : 9 in the final mixture, find the quantity of third variety of oil was ? 

A) 15 kg B) 25 kg
C) 35 kg D) 45 kg
 
Answer & Explanation Answer: D) 45 kg

Explanation:

Let the ratio of initial quantity of oils be 'x' => 4x, 5x & 8x.
Let k be the quantity of third variety of oil in the final mixture.
Let the ratio of initial quantity of oils be 'y'
From given details,
4x + 5 = 5y ..... (1)
5x + 10 = 7y .....(2)
8x + k = 9y ......(3)

By solving (1) & (2), we get
x = 5 & y = 5

From (3) => k = 5

Therefore, quantity of third variety of oil was 9y = 9(5) = 45kg.

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Q:

What is the value of 4 in 475?

A) 4 B) 400
C) 475 D) 40
 
Answer & Explanation Answer: B) 400

Explanation:

The value of 4 in 475 means the place value of 4 in 475 and not its face value. Face value means the digit itself though it is at any place in the given number. But place value means the value of digit in its place in the given number.

 

Here the place value of 4 in 475 can be determined by as 4 is in 100's place in 475.

Hence, the place value of 4 in 475 is 4x100 = 400.

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Q:

In the following question, four number pairs are given. The number on left side of (–) is related to the number on the right side of (–) with some Logic/Rule/Relation. Three are similar on basis of same Logic/Rule/Relation. Select the odd one out from the given alternatives.

 

A) 7 – 49 B)  9 – 81
C)  11 – 121 D)  15 – 215
 
Answer & Explanation Answer: D)  15 – 215

Explanation:
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