6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

What was the day on 25th Jan,1981?

A) Monday	B) Friday
C) Sunday	D) Tuesday

Answer & Explanation Answer: C) Sunday

Explanation:

25 Jan, 1981 = (1980 years + Period from 1.1.1981 to 25.1.1981)

Odd days in 1600 years = 0

Odd days in 300 years = 1

80 years = (60 ordinary years + 20 leap year) = (60 x 1 + 20 x 2)= 2 odd days

Jan = 25 days = (3 weeks + 4 days) = 4 odd days.

Total number of odd days = (0 + 1 + 2 + 4) = 7= 0 odd day.

Given day is Sunday.

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Filed Under: Calendar

12 6973

Q:

The probability that a number selected at random from the first 100 natural numbers is a composite number is ?

A) 3/2	B) 2/3
C) 1/2	D) 34/7

Answer & Explanation Answer: A) 3/2

Explanation:

The number of exhaustive events = 100 C₁ = 100.

We have 25 primes from 1 to 100.

Number of favourable cases are 75.

Required probability = 75/50 = 3/2.

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Filed Under: Probability
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13 6970

Q:

The ratio of K’s and M’s ages is 4: 5. If the difference between the present age of M and the age of K, 5 years hence is 3 years, then what is the difference and total of present ages of K and M?

A) 8, 72 yrs	B) 16, 65 yrs
C) 12, 84 yrs	D) 10, 60 yrs

Answer & Explanation Answer: A) 8, 72 yrs

Explanation:

Let the present ages be K,M

Given K/M = 4/5

5K - 4M = 0 ......(1)

Also given that,

M - (K + 5) = 3

M - K = 8 .........(2)

Then, by solving (1) & (2)

M = 40 yrs and K = 32 yrs

Hence, Total of ages = 40 + 32 = 72 yrs

Difference of ages = 40 - 32 = 8 yrs.

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Filed Under: Problems on Ages
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3 6964

Q:

When Dr. Ram arrives in his dispensary, he finds 12 patients waiting to see him. If he can see only one patients at a time,find the number of ways, he can schedule his patients if 3 leave in disgust before Dr. Ram gets around to seeing them.

A) 479001600	B) 79833600
C) 34879012	D) 67800983

Answer & Explanation Answer: B) 79833600

Explanation:

There are 12 - 3 = 9 patients.They can be seen in $12 P_{9}$ = 79833600 ways

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Filed Under: Permutations and Combinations

3 6957

Q:

The Value of $[\log (\tan (1^{0})) + \log (\tan (2^{0})) + \dots \dots + \log (\tan (89^{0}))]$ is

A) -1	B) 0
C) 1/2	D) 1

Answer & Explanation Answer: B) 0

Explanation:

$= [\log \tan (1^{0}) + \log \tan (89^{0})] + [\log \tan (2^{0}) + \log \tan (88^{0})] + \dots \dots + [\log \tan (45^{0})]$

$= \log [\tan (1^{0}) \times \tan (89^{0})] + \log [\tan (2^{0}) \times \tan (88^{0})] + \dots \dots + \log (1)$

$[∵ \tan (90 - θ) = c o t θ a n d \tan (45^{0}) = 1]$

= log 1 + log 1 +.....+log 1

= 0.

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Filed Under: Logarithms
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27 6955

Q:

A chartered bank offers a five-year Escalator Guaranteed Investment Certificate.In successive years it pays annual interest rates of 4%, 4.5%, 5%, 5.5%, and 6%, respectively, compounded at the end of each year. The bank also offers regular five-year GICs paying a fixed rate of 5% compounded annually. Calculate and compare the maturity values of $1000 invested in each type of GIC. (Note that 5% is the average of the five successive one-year rates paid on the Escalator GIC.)

A) 1276.28	B) 1234
C) 1278	D) 1256

Answer & Explanation Answer: A) 1276.28

Explanation:

FV = $1000(1.04)(1.045)(1.05)(1.055)(1.06) = $1276.14

the maturity value of the regular GIC is

FV = $ 1000 x ${(1.05)}^{5}$ = $1276.28

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

4 6953

Q:

A man sold two flats for Rs. 4.15 lakhs each. On one he gained 2% and on the other he lost 2%. What percent is the effect of the sale on the whole ?

A) 0.25 %	B) 0.04 %
C) 0.5 %	D) 0 %

Answer & Explanation Answer: B) 0.04 %

Explanation:

In this type cases we always have loss only.

Loss% = ${(\frac{C o m m o n G a i n o r L o s s}{10})}^{2}$ = ${(\frac{2}{10})}^{2}$ = 1/25 = 0.04 %

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Filed Under: Profit and Loss
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11 6952

Q:

A train is moving and crossing a man who is running on a platform of 100 m at a speed of 8 kmph in the direction of the train, in 9 sec. If the speed of the train is 74 kmph. Find the length of the train ?

A) 202 mts	B) 188 mts
C) 165 mts	D) 156 mts

Answer & Explanation Answer: C) 165 mts

Explanation:

Let the length of the train = L mts

Relative speed of train and man = 74 - 8 = 66 kmph = 66 x 5/18 m/s

=> 66 x 5/18 = L/9

=> L = 165 mts.

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Filed Under: Problems on Trains
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22 6938

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