6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Karthik walks at 5 km/hr and reaches his destination 8 min late. If he walks at 6 km/hr, he reaches his destination on time. What distance he will cover in given time ?

A) 10 kms	B) 8 kms
C) 6 kms	D) 4 kms

Answer & Explanation Answer: D) 4 kms

Explanation:

Let the actual distance be t kms

Now, According to the data,

$5 (t + \frac{8}{60}) = 6 t = > 5 (\frac{60 t + 8}{60}) = 6 t = > 60 t + 8 = 72 t = > 8 = 12 t = > t = 8 / 12 = 2 / 3 hrs$

Now, the total distance = 6t = 6 x 2/3 = 2 x 2 = 4 kms.

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Filed Under: Time and Distance
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Q:

The true discount on a bill due 9 months hence at 12% per annum is Rs 540. Find the amount of the bill and its present worth?

A) 1600	B) 7000
C) 6000	D) 6500

Answer & Explanation Answer: C) 6000

Explanation:

Let amount be Rs.x then,

[X * R * T] / [100 + (R * T)] = T.D

=> [x * 12 * (3/4)] / [100+(12 * 3/4)] =540

=> x = 6540

Amount = Rs.6540

P.W = Rs.(6540 -540) = Rs.6000

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Filed Under: True Discount

0 6180

Q:

How many seconds will a 600 m long train take to cross a man walking with a speed of 7 km/hr in the direction of the moving train if the speed of the train is 67 km/hr ?

A) 29 sec	B) 58 sec
C) 36 sec	D) 44 sec

Answer & Explanation Answer: C) 36 sec

Explanation:

Speed of train relative to man = 67 - 7 = 60 km/hr.
= 60 x 5/18 = 50/3 m/sec.

Time taken to pass the man = 600 x 3/50 = 36 sec.

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Filed Under: Problems on Trains
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3 6179

Q:

A and B entered in a business by making investment of Rs. 4000 & Rs. 5500 respectively. After six months A & B withdrew Rs. 1000 and Rs. 1500 respectively and C joined them with capital of Rs. 4x. If after one year and three months C received Rs. 2250 as profit share out of total profit of Rs. 12250, then find investment of C?

A) Rs. 3600	B) Rs. 3200
C) Rs. 4400	D) Rs. 3000

Answer & Explanation Answer: D) Rs. 3000

Explanation:

Investment ratio of A, B & C = (4000 ×6+3000×9):(5500 ×6+4000×9):4

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Filed Under: Partnership
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8 6177

Q:

Find the area of the square whose side is equal to the diagonal of a rectangle of length 3 cm and breadth 4 cm.

A) 25 sq.cm	B) 16 sq.cm
C) 9 sq.cm	D) 4 sq.cm

Answer & Explanation Answer: A) 25 sq.cm

Explanation:

Given length of the rectangle = 3 cm

Breadth of the rectangle = 4 cm

Then, the diagonal of the rectangle $D = \sqrt{3^{2} + 4^{2}} = \sqrt{25} = 5$

Then, it implies side of square = 5 cm

We know that Area of square = S x S = 5 x 5 = 25 sq.cm.

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Filed Under: Area
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18 6169

Q:

The probabiltiy that throw of two dice yields a total of 5 or 6 is:

A) 2/14	B) 5/18
C) 3/4	D) 1/4

Answer & Explanation Answer: B) 5/18

Explanation:

Total number of cases=36

Number of favourable cases(sum 5 or 6)=10

P(getting total of 5 or 6)=10/36=5/18

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Filed Under: Probability

5 6166

Q:

Ratio between heights of two cylinder in the ratio 3:5. Their volumes are in the ratio 27:80. Find ratio between their radius ?

A) 1:3	B) 2:1
C) 3:4	D) 4:7

Answer & Explanation Answer: C) 3:4

Explanation:

bank

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Filed Under: Volume and Surface Area
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14 6160

Q:

There are 5 consecutive odd numbers. If the difference between square of the average of first two odd number and the of the average last two odd numbers is 396, what is the smallest odd number?

A) 29	B) 27
C) 31	D) 33

Answer & Explanation Answer: A) 29

Explanation:

Let the five consecutive odd numbers be x-4, x-2, x, x+2, x+4

According to the question,

Difference between square of the average of first two odd number and the of the average last

two odd numbers is 396

i.e, x+3 and x-3

$\Rightarrow {(x + 3)}^{2} - {(x - 3)}^{2} = 396 \Rightarrow x^{2} + 9 + 6 x - x^{2} + 6 x - 9 = 396 \Rightarrow 12 x = 396 \Rightarrow x = 33$

Hence, the smallest odd number is 33 - 4 = 29.

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Filed Under: Problems on Numbers
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Quantitative Aptitude - Arithmetic Ability Questions

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