6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

If a person having Rs. 2000 and he want to distribute this to his five children in the manner that each son having Rs. 30 more than the younger one , what will be the share of youngest child ?

A) Rs. 175	B) Rs. 325
C) Rs. 340	D) Rs. 260

Answer & Explanation Answer: C) Rs. 340

Explanation:

Assume first child (the youngest) get = Rs. x

According to the question ;
each son having Rs. 30 more than the younger one

Second child will get = Rs. x + 30
Third child will get = Rs. x + 30 + 30 = x + 60
Forth child will get = Rs. x + 30 + 30 + 30 = x + 90
Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120

Total amount they got = Rs. 2000

x + (x+30) + (x+60) + (x+90) + (x+120) = 2000
5x + 300 = 2000
5x = 1700
x = Rs. 340
So the youngest child will get Rs. 340.

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Filed Under: Chain Rule
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22 6180

Q:

Rondell's parents borrow $6,300 from the bank for a new car. The interest rate is 6% per year. How much simple interest will they pay if they take 2 years to repay the loan?

A) 556	B) 665
C) 756	D) 856

Answer & Explanation Answer: C) 756

Explanation:

I=prt

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Filed Under: Simple Interest
Exam Prep: Bank Exams
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3 6176

Q:

74.99% of 1299 + 8.98% of 1899 = ?

A) 1378	B) 1301
C) 1212	D) 1197

Answer & Explanation Answer: C) 1212

Explanation:

74.99% of 1299 + 8.98% of 1899 = ?

$? = \frac{75 x 1400}{100} + \frac{9 x 1800}{100} ? = 1050 + 162 ? = 1212 .$

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Filed Under: Percentage
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9 6175

Q:

On Rs. 3500 invested at a simple interest rate of 7 per cent per annum, Rs. 500 is obtained as interest in certain years. In order to earn Rs. 800 as interest on Rs. 4900 in the same number of years, what should be the rate of simple interest?

A) 8%	B) 7.5%
C) 9%	D) 8.5%

Answer & Explanation Answer: A) 8%

Explanation:

From the given data,

3500x7xt/100 = 500

=> t = 100/49 years

Now, in the second case

The interest per year = 49/100 x 800 = 392

=> 4900 x 1 x r/100 = 392

=> r = 8%

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Filed Under: Simple Interest
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10 6174

Q:

Two equal sums were lent, one at the rate of 11% per annum for five years and the other at the rate of 8% per annum for six years, both under simple interest. If the difference in interest accrued in the two cases is Rs 1008. Find the sum?

A) Rs. 14,400	B) Rs. 15,600
C) Rs. 14,850	D) Rs. 15,220

Answer & Explanation Answer: A) Rs. 14,400

Explanation:

Let the required Sum = Rs.S

From the given data,

1008 = [(S x 11 x 5)/100] - [(S x 8 x 6)/100]

=> S = Rs. 14,400.

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Filed Under: Simple Interest
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18 6173

Q:

A jar can 20 litre milk. From the jar, 4 litres milk was taken out and replaced with an equal quantity of water. If 4 litres of the newly formed mixture is taken out of the can, then what is the final quantity of milk left in the can?

A) 14.5 lit	B) 12.8 lit
C) 11.6 lit	D) 10.46 lit

Answer & Explanation Answer: B) 12.8 lit

Explanation:

This can be solved as

$20 {(1 - \frac{4}{20})}^{2} = 20 {(1 - \frac{1}{5})}^{2} = 20 {(\frac{4}{5})}^{2} = 20 (\frac{16}{25}) = \frac{64}{5} = 12.8$

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Filed Under: Percentage
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11 6172

Q:

What is the rate of compound interest?
I. The principal was invested for 4 years.
II. The earned interest was Rs. 1491.

A) I alone sufficient while II alone not sufficient to answer	B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer	D) Either I or II alone sufficient to answer

Answer & Explanation Answer: D) Either I or II alone sufficient to answer

Explanation:

Let Principal = Rs. P and Rate = R% p.a. Then,

Amount= $R s . [P {(1 + \frac{R}{100})}^{4}]$

C.I = $P [{(1 + \frac{R}{100})}^{4} - 1]$

$P [{(1 + \frac{R}{100})}^{4} - 1] = 1491$

Clearly, it does not give the answer

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Filed Under: Compound Interest
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0 6168

Q:

If a student walks at the rate of 4 mts/min from his home, he is 4 minutes late for school, if he walks at the rate of 6 mts/min he reaches half an hour earlier. How far is his school from his home ?

A) 100 mts	B) 96 mts
C) 98 mts	D) 120 mts

Answer & Explanation Answer: C) 98 mts

Explanation:

Let the distance between home and school is 'x'.
Let actual time to reach be 't'.
Thus, x/4 = t + 4 ---- (1)
and x/6 = t - 30 -----(2)
Solving equation (1) and (2)
=> x = 98 mts.

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Filed Under: Time and Distance
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