A) 8% | B) 7.5% |

C) 9% | D) 8.5% |

Explanation:

From the given data,

3500x7xt/100 = 500

=> t = 100/49 years

Now, in the second case

The interest per year = 49/100 x 800 = 392

=> 4900 x 1 x r/100 = 392

=> **r = 8%**

A) 1.58 | B) 2.63 |

C) 3.87 | D) 4.02 |

Explanation:

Let the two different rates of interests be r1 and r2 respectively.

From the given data,

$\frac{\mathbf{2600}\mathbf{}\mathbf{x}\mathbf{}\mathbf{4}\mathbf{}\mathbf{x}\mathbf{}\left(\mathbf{r}\mathbf{1}\mathbf{}\mathbf{-}\mathbf{}\mathbf{r}\mathbf{2}\right)}{\mathbf{100}\mathbf{}}\mathbf{}\mathbf{=}\mathbf{}\mathbf{402}\mathbf{.}\mathbf{80}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\left(\mathrm{r}1-\mathrm{r}2\right)=\frac{402.80}{104}=\; 3.87$

Hence, the difference in the interest rates = **3.87**

A) 7.2% | B) 8% |

C) 8.5% | D) 9.3% |

Explanation:

We know,

**S.I = PTR/100** where P = principal amount, T = time, R = rate of interest

Here in the given data,

Interest for two years **S.I = 924 - 812 = Rs. 112**

Now, Principal amount **P = 812 - 112 = Rs. 700 **

Now,

**R = S.I x 100/PT**

R = 112 x 100/700 x 2

R = 11200/1400

R = 8%

Hence, the rate of interest **R = 8%**.

A) Rs. 800 | B) Rs. 620 |

C) Rs. 560 | D) Rs. 480 |

Explanation:

Let the principle amount be Rs. P

Interest rate = 12%

Total amount he paid after 5 years = Rs. 1280

ATQ,

$\mathbf{P}\mathbf{}\mathbf{+}\mathbf{}\mathbf{I}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{PTR}}{\mathbf{100}}\mathbf{}\mathbf{+}\mathbf{}\mathbf{P}\phantom{\rule{0ex}{0ex}}1280=\mathrm{P}\left[\frac{\mathrm{TR}}{100}+1\right]\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}1280=\mathrm{P}\left[\frac{5\mathrm{x}12}{100}+1\right]\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\frac{16\mathrm{P}}{10}=1280\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\mathbf{P}\mathbf{}\mathbf{=}\mathbf{}\mathbf{80}\mathbf{}\mathbf{x}\mathbf{}\mathbf{10}\mathbf{}\mathbf{=}\mathbf{}\mathbf{800}$

Hence, the amount he borrowed = **P = Rs. 800.**

A) 0.3 Paise | B) 1.2 Paise |

C) 30 Paise | D) 3 Paise |

Explanation:

Given Principal amount P = Rs. 10

Time T = 4 months

Rate of interest R = 3 ps

Interest **I = PTR/100 = 10 x 4 x 3/100 = 12/10** =** 1.2 paise.**

A) Rs. 364 | B) Rs. 432 |

C) Rs. 498 | D) Rs. 554 |

Explanation:

Here Avinash gave to Rajeev and Rajeev gave the same to Chanukya

Principal amount and Time is same but the only difference is Rate of interest.

Rajeev took @ 8% and gave it to Chanukya @ 6%

Here the difference in interest rate = 2%

2% of 5400 should be the extra amount paid by Rajeev to Avinash

Required amount = $\frac{\mathbf{2}\mathbf{}\mathbf{x}\mathbf{}\mathbf{5400}\mathbf{}\mathbf{x}\mathbf{}\mathbf{4}}{\mathbf{100}}\mathbf{}\mathbf{=}\mathbf{}\mathbf{432}$

Hence, **Rs. 432** is the extra amount has to be paid by Rajeev to Avinash after 4 years.

A) Rs. 2550 | B) Rs. 2424 |

C) Rs. 2224 | D) Rs. 2380 |

Explanation:

Now, the principal amount P = Rs. 1,45,440

Rate of interest R = 20%/annum

Now monthly income I = PTR/100 = 1,45,440 x 20 x 1/100 x 12

= 2908800/1200

= Rs. 2424.

Hence, her monthly income =** Rs. 2424.**

A) 2.9 years | B) 3.5 years |

C) 4.2 years | D) 4.7 years |

Explanation:

Given that Rs. 1860 will become Rs. 2641.20 at 12%

=> Simple Interest = 2641.20 - 1860 = Rs. 781.20

We know **I = PTR/100**

=> 781.20 x 100 = 1860 x T x 12

=> T = 78120/1860x12

=> T = 78120/22320

=> T = 3.5 years.

A) 30% | B) 25% |

C) 22% | D) 18% |