6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Find the compound interest on Rs.16,000 at 20% per annum for 9 months, compounded quartely.

A) Rs.2522	B) Rs.2422
C) Rs.3522	D) Rs.2322

Answer & Explanation Answer: A) Rs.2522

Explanation:

Principal = Rs.16,000;

Time=9 months = 3 quarters;

Amount

=Rs.[16000x(1+5/100)³] =[16000x21/20x21/20x21/20]

= Rs.18522.

C.I

= Rs.(18522 - 16000)

= Rs.2522.

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

0 5934

Q:

$2660 o f \frac{1}{7} o f \frac{1}{2} o f \frac{1}{9.5} o f \frac{1}{2} = ?$

A) 1	B) 10
C) 0.1	D) 100

Answer & Explanation Answer: B) 10

Explanation:

$\frac{1}{7} x \frac{1}{2} x \frac{1}{9.5} x \frac{1}{2} x 2660 = \frac{2660}{266} = 10$

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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

3 5934

Q:

In what time a debt of Rs.7920 due may be cleared by immediate cash down payment of Rs.3600 at 1/2% per month

A) 10years	B) 20years
C) 30years	D) 40years

Answer & Explanation Answer: B) 20years

Explanation:

PW = $\frac{100 \times A m o u n t}{100 + (R \times T)}$

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Filed Under: True Discount
Exam Prep: Bank Exams
Job Role: Bank PO

6 5917

Q:

Sandeep got Rs. 6000 as his share out of the total profit of Rs. 9000 which he and Saketh earned at the end of one year. If Sandeep invested Rs. 20000 for 6 months, whereas Saketh invested his amount for the whole year, the amount invested by Saketh?

A) Rs. 5000	B) Rs. 6200
C) Rs. 8100	D) R. 7600

Answer & Explanation Answer: A) Rs. 5000

Explanation:

Let the amount invested by saketh = RS. p

Now, that of sandeep = 20,000 x 6

saketh = 12 x p

Ratio of their earnings = 120000 : 12p = 6000 : (9000 - 6000)

=> $\frac{120000}{12 p} = \frac{6000}{3000} = > p = Rs . 5000$

Hence, the amount investe by saketh = Rs. p = Rs. 5000.

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Filed Under: Partnership
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , IT Trainer

13 5916

Q:

Find value of $\frac{\log \sqrt{27} + \log 8 + l o g \sqrt{1000}}{\log 120}$

A) 1/2	B) 3/2
C) 2	D) 2/3

Answer & Explanation Answer: B) 3/2

Explanation:

$= \frac{\log \sqrt{3^{3}} + \log 2^{3} + \log \sqrt{10^{3}}}{\log (10 \times 3 \times 2^{2})}$

$= \frac{\log (3^{3})^{\frac{1}{2}} + \log 2^{3} + \log {(10^{3})}^{\frac{1}{2}}}{\log (10 \times 3 \times 2^{2})}$

$= \frac{\frac{1}{2} \log 3^{3} + 3 \log 2 + \frac{1}{2} \log 10^{3}}{\log 10 + \log 3 + \log 2^{2}}$

$= \frac{\frac{3}{2} (\log 3 + 2 \log 2 + \log 10)}{\log 3 + 2 \log 2 + \log 10}$ = $\frac{3}{2}$

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Filed Under: Logarithms
Exam Prep: CAT , Bank Exams , AIEEE
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27 5911

Q:

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

A) 25% increase	B) 50% increase
C) 50% decrease	D) 75% decrease

Answer & Explanation Answer: B) 50% increase

Explanation:

Let original length = x and original breadth = y.

Original area = xy.

New length = x/2 and New breadth = 3y.

New area = (x/2 * 3y) = (3/2 )xy

Therefore, Increase % = [(1/2)xy * (1/xy) * 100] % = 50%

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Filed Under: Volume and Surface Area

0 5909

Q:

P can do a piece of work in 5 less days than Q. If both of them can do the same work in $11 \frac{1}{9}$ days, in how many days will Q alone do the same work ?

A) 24 days	B) 25 days
C) 20 days	D) 19 days

Answer & Explanation Answer: B) 25 days

Explanation:

Let Q complete that work in 'L' days

=> $\frac{1}{L} + \frac{1}{L - 5} = \frac{9}{100}$

=> $9 L^{2} - 245 L + 500 = 0$

L = 25 days.

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Filed Under: Time and Work
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

11 5902

Q:

$[\sqrt[3]{250047} + (56)^{2}] \div 7 = ?$

A) 547	B) 475
C) 455	D) None of these

Answer & Explanation Answer: D) None of these

Explanation:

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

9 5901

Quantitative Aptitude - Arithmetic Ability Questions

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