Quantitative Aptitude - Arithmetic Ability Questions

Let x be the investment of Lasya in 5% and y be in 4%

x(5)(n)/100 = y(4)(n)/100

=> x/y = 4/5

x : y = 4 : 5

I. gives, Rate = 5% p.a.

II. gives, S.I. for 1 year = Rs. 600.

III. gives, sum = 10 x (S.I. for 2 years).

Now I, and II give the sum.

For this sum, C.I. and hence amount can be obtained.

Thus, III is redundant.

Again, II gives S.I. for 2 years = Rs. (600 x 2) = Rs. 1200.

Now, from III, Sum = Rs. (10 x 1200) = Rs . 12000.

Thus, Rate =

100 x 1200

= 5% p.a.

2 x 12000

Thus, C.I. for 2 years and therefore, amount can be obtained.

Thus, I is redundant.

Hence, I or III redundant.

B.G = S.I On T.D

      = Rs. (120 * 15 * 1/2 * 1/100)

      = Rs.9

B.D - T.D = Rs.9

B.D = Rs.(120 +9) = Rs.129

P(heart cards)=13/52

P(diamond cards)=13/52

P(heart or diamond)=13/52+13/52=1/2

Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.
P + Q = 8 ----- (1)
(10Q + P) - (10P + Q) = 54
9(Q - P) = 54
(Q - P) = 6 ----- (2)
Solve (1) and (2) P = 1 and Q = 7
The required number is = 17

The 7 letters word 'POVERTY' be arranged in 7P7 ways = 7! = 5040 ways.

Total engineers = 4800

Number of female engineers = 3/8 x 4800 = 1800

Then, number of male engineers = 4800 - 1800 = 3000

Now, required is female engineers is what percentage of the number of male engineers

=> 1800 is what % of 3000

=> p x 3000/100 = 1800

=> 30p = 1800

p = 60%

Hence, female engineers is 60 percentage of the number of male engineers.