6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

One of the roots of the equation $x^{2} - 6 x + k = 0$ is x = 2. The other root is

A) x = -1	B) x = 4
C) x = -4	D) x = 1

Answer & Explanation Answer: B) x = 4

Explanation:

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Filed Under: Area
Exam Prep: Bank Exams

1 30080

Q:

Which of the following represents the sides of an acute angled triangle?

A) 6, 9, 16	B) 7, 8, 10
C) 5, 12, 13	D) None of these

Answer & Explanation Answer: B) 7, 8, 10

Explanation:

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Filed Under: Area
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1 30039

Q:

For the figure given below, find the angle OAB (in degrees).

A) 25	B) 50
C) 75	D) 90

Answer & Explanation Answer: C) 75

Explanation:

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Q:

Two stations P and Q are 110 km apart on a straight track. One train starts from P at 7 a.m. and travels towards Q at 20 kmph. Another train starts from Q at 8 a.m. and travels towards P at a speed of 25 kmph. At what time will they meet?

A) 10.30	B) 10
C) 8.45	D) 9.30

Answer & Explanation Answer: B) 10

Explanation:

Assume both trains meet after x hours after 7 am

Distance covered by train starting from P in x hours = 20x km

Distance covered by train starting from Q in (x-1) hours = 25(x-1)

Total distance = 110

=> 20x + 25(x-1) = 110

=> 45x = 135

=> x= 3

Means, they meet after 3 hours after 7 am, ie, they meet at 10 am

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Filed Under: Problems on Trains

42 30010

Q:

Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 9856 sq meters.

A) 56m	B) 16m
C) 14m	D) 76m

Answer & Explanation Answer: A) 56m

Explanation:

clearly the cow will graze a circular field of area 9856 sq m and radius equal to the length of the rope.

Let the length of the rope be r mts

then, ${πr}^{2} = 9856 \Rightarrow r^{2} = \frac{9856 \times 7}{22} = 3136 \Rightarrow r = 56 m$

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

31 29983

Q:

A man went downstream for 28 km in a motor boat and immediately returned. It took the man twice as long to make the return trip. If the speed of the river flow were twice as high, the trip downstream and back would take 672 minutes. Find the speed of the boat in still water and the speed of the river flow.

A) 12 km/hr, 3 km/hr	B) 9 km/hr, 3 km/hr
C) 8 km/hr, 2 km/hr	D) 9 km/hr, 6 km/hr

Answer & Explanation Answer: B) 9 km/hr, 3 km/hr

Explanation:

Let the speed of the boat = p kmph

Let the speed of the river flow = q kmph

From the given data,

$2 x \frac{28}{p + q} = \frac{28}{p - q}$

=> 56p - 56q -28p - 28q = 0

=> 28p = 84q

=> p = 3q.

Now, given that if

$\frac{28}{3 q + 2 q} + \frac{28}{3 q - 2 q} = \frac{672}{60} = > \frac{28}{5 q} + \frac{28}{q} = \frac{672}{60} = > q = 3 kmph = > x = 3 q = 9 kmph$

Hence, the speed of the boat = p kmph = 9 kmph and the speed of the river flow = q kmph = 3 kmph.

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

80 29983

Q:

A sum of money becomes 7/6 of itself in 3 years at a certain rate of simple interest. The rate per annum is ?

A) 45/7 %	B) 50/9 %
C) 51/7 %	D) 47/ 9 %

Answer & Explanation Answer: B) 50/9 %

Explanation:

Let sum = S. Then, amount = 7S/6

S.I. = 7S/6 - S = S/6; Time = 3 years.

Rate = (100 x S) / (S x 6 x 3) = 5 5/9 = 50/9 %.

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Filed Under: Simple Interest
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

27 29982

Q:

A, B and C enter into a partnership. They invest Rs. 40,000, Rs. 80,000 and Rs. 1,20,000 respectively. At the end of the first year, B withdraws Rs. 40,000, while at the end of the second year, C withdraws Rs. 80,000. In what ratio will the profit be shared at the end of 3 years ?

A) 2 : 3 : 5	B) 3 : 4 : 7
C) 5 : 6 : 4	D) 1 : 3 : 5

Answer & Explanation Answer: B) 3 : 4 : 7

Explanation:

A : B : C = (40000 x 36) : (80000 x 12 + 40000 x 24) : (120000 x 24 + 40000 x 12)

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