Quantitative Aptitude - Arithmetic Ability Questions

Q:

 In the following question, select the odd letter/letters from the given alternatives.

 

A) CHM B) GLQ
C) KPV D) NSX
 
Answer & Explanation Answer: C) KPV

Explanation:
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Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 29112
Q:

From  a container of wine, a thief has stolen 15 liters of wine and replaced it with same quantity of water.He again repeated the same process. Thus in three attempts the ratio of wine and water became 343:169. The  initial amount of wine in the container was:

A) 75 liters B) 100 liters
C) 150 liters D) 120 liters
 
Answer & Explanation Answer: D) 120 liters

Explanation:

Wine (left)Water (added)=343169

 

It means   Wine (left)Wine(initial amount)=343512   343+169 = 512

 

Thus ,       

343x=512x1-15K3

 

 343512=783=1-15k3

 

=> K = 120

Thus the initial amount of wine was 120 liters.

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Filed Under: Alligation or Mixture

40 29042
Q:

∆DEF is right angled at E. If m∠F = 45°, then find the value of (tanD - √3/2).

 

A) -√3/2 B) -1/2√3
C) (2-√3)/2 D) (3√3-1)/3
 
Answer & Explanation Answer: C) (2-√3)/2

Explanation:
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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

0 29004
Q:

A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?

A) 10/21 B) 11/21
C) 1/2 D) 2/7
 
Answer & Explanation Answer: A) 10/21

Explanation:

Total number of balls = (2 + 3 + 2) = 7.

 

Let S be the sample space.

 

Then, n(S) = Number of ways of drawing 2 balls out of 7 =7C2 = 21

 

Let E = Event of drawing 2 balls, none of which is blue.

 

n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls =5C2 = 10

 

Therefore, P(E) = n(E)/n(S) = 10/ 21.

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Filed Under: Probability

37 28948
Q:

The diameter of the driving wheel of a bus is 140 cm. How many revolution, per minute must the wheel make in order to keep a speed of 66 kmph ?

A) 150 B) 250
C) 350 D) 550
 
Answer & Explanation Answer: B) 250

Explanation:

Circumference = No.of revolutions * Distance covered

 

Distance to be covered in 1 min. = (66 X1000)/60 m = 1100 m.
Circumference of the wheel = 2 x (22/7) x 0.70 m = 4.4 m.
Number of revolutions per min. =(1100/4.4) = 250.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

47 28928
Q:

A bag contains 50 tickets numbered 1,2,3,4......50 of which five are drawn at random and arranged in ascending order of magnitude.Find the probability that third drawn ticket is equal to 30.

A) 551/15134 B) 1/2
C) 552/15379 D) 1/9
 
Answer & Explanation Answer: A) 551/15134

Explanation:

Total number of elementary events = 50C5
Given,third ticket =30

 

 

 

=> first and second should come from tickets numbered 1 to 29 = 29C2 ways and remaining two in 20C2 ways.

 

 

 

Therfore,favourable number of events = 29C2*20C2

 

 

 

Hence,required probability = 29C2*20C2/50C5 =551 / 15134

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Filed Under: Probability

72 28842
Q:

The banker's discount on a bill due 6 months hence at 6% is Rs. 18.54. What is the true discount?

A) Rs. 24 B) Rs. 12
C) Rs. 36 D) Rs. 18
 
Answer & Explanation Answer: D) Rs. 18

Explanation:
T= 6 months = 1/2 year

R = 6%

TD= BD×100100+TR=18.54×100100+12×6=Rs.18
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Filed Under: Banker's Discount

3 28833
Q:

A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares?

A) 315 B) 385
C) 415 D) 485
 
Answer & Explanation Answer: A) 315

Explanation:

Let the areas of the two parts be x and (700-x) hectares

therefore, x-700-x=15x+700-x2

 2x-700=70

 x=385

So, the two parts are 385 and 315.

 Hence, Area of the smaller = 315 hectares

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

18 28810