Quantitative Aptitude - Arithmetic Ability Questions

Q:

The area of an equilateral triangle is 49√3 cm2. Find its side (in cm).

 

A) 7 B) 14
C) 28 D) 42
 
Answer & Explanation Answer: B) 14

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: Bank Exams

0 28573
Q:

There are four hotels in a town. If 3 men check into the hotels in a day then what is the probability that each checks into a different hotel?

A) 1/2 B) 3/4
C) 4/7 D) 3/8
 
Answer & Explanation Answer: D) 3/8

Explanation:

Total cases of checking in the hotels = 4 x 4 x 4 = 64 ways.

Cases when 3 men are checking in different hotels = 4×3×2 = 24 ways.

Required probability =24/64  = 3/8

Report Error

View Answer Report Error Discuss

Filed Under: Probability

46 28525
Q:

 If the circumference of a circle is 88 cm, then what must be its area (in cm2)?

 

A) 1232   B) 616  
C) 704   D) 1408
 
Answer & Explanation Answer: B) 616  

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: Bank Exams

3 28522
Q:

Direction: What should come in the place of question mark (?) in the following number series?

2, 3, 6, 15, 45, ?

A) 90 B) 135
C) 157.5 D) 200
 
Answer & Explanation Answer: C) 157.5

Explanation:

The pattern followed is *1.5 , * 2 , *2.5 , *3 , *3.5

Report Error

View Answer Report Error Discuss

Filed Under: Numbers
Exam Prep: AIEEE , Bank Exams , GATE

0 28522
Q:

A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 more is lent but at the rate twice the former. At the end of the year, Rs. 33.50 is earned as interest from both the loans. What was the original rate of interest?

A) 3.46% B) 4.5%
C) 5% D) 6%
 
Answer & Explanation Answer: A) 3.46%

Explanation:

Let the original rate be R%. Then, new rate = (2R)%.

 

Note: Here, original rate is for 1 year(s); the new rate is for only 4 months i.e.1/3 year(s).

 725*R*1100+362.50*2R*1100*3=33.50

 

=> (2175 + 725) R = 33.50 x 100 x 3

 

=>  (2175 + 725) R = 10050

 

=>  (2900)R = 10050

 

 => R=100502900=3.46

 

Original rate = 3.46%

Report Error

View Answer Report Error Discuss

Filed Under: Simple Interest
Exam Prep: GRE

37 28496
Q:

If the length of a certain rectangle is decreased by 4 cm and the width is increased by 3 cm, a square with the same area as the original rectangle would result. Find the perimeter of the original rectangle.

A) 20 B) 30
C) 40 D) 50
 
Answer & Explanation Answer: D) 50

Explanation:

Let x and y be the length and breadth of the rectangle respectively.
Then, x - 4 = y + 3 or x - y = 7 ----(i)
Area of the rectangle =xy; Area of the square = (x - 4) (y + 3)
(x - 4) (y + 3) =xy <=> 3x - 4y = 12 ----(ii)
Solving (i) and (ii), we get x = 16 and y = 9.
Perimeter of the rectangle = 2 (x + y) = [2 (16 + 9)] cm = 50 cm.

Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

21 28493
Q:

A bag contains 4 red and 3 black balls. A second bag contains 2 red and 4 black balls. One bag is selected at random. From the selected bag, one ball is drawn. Find the probability that the ball drawn is red.

A) 23/42 B) 19/42
C) 7/32 D) 16/39
 
Answer & Explanation Answer: B) 19/42

Explanation:

A red ball can be drawn in two mutually exclusive ways

 (i) Selecting bag I and then drawing a red ball from it.

 

(ii) Selecting bag II and then drawing a red ball from it.

 

Let E1, E2 and A denote the events defined as follows:

E1 = selecting bag I,

E2 = selecting bag II

A = drawing a red ball

Since one of the two bags is selected randomly, therefore 

P(E1) = 1/2  and  P(E2) = 1/2

Now, PAE1 = Probability of drawing a red ball when the first bag has been selected = 4/7

  PAE2  = Probability of drawing a red ball when the second bag has been selected = 2/6

 Using the law of total probability, we have 

 P(red ball) = P(A) = PE1×PAE1+PE2×PAE2 

 

                          = 12×47+12×26=1942

Report Error

View Answer Report Error Discuss

Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

64 28449
Q:

The year next to 2005 will have the same calendar as that of the year 2005?

A) 2016 B) 2022
C) 2011 D) None
 
Answer & Explanation Answer: C) 2011

Explanation:

NOTE :

Repetition of leap year ===> Add +28 to the Given Year.

Repetition of non leap year

Step 1 : Add +11 to the Given Year. If Result is a leap year, Go to step 2.

Step 2:  Add +6 to the Given Year.

 

Solution : 

Given Year is 2005, Which is a non leap year.

Step 1 : Add +11 to the given year (i.e 2005 + 11) = 2016, Which is a leap year. 

Step 2 : Add +6 to the given year (i.e 2005 + 6) = 2011

Therfore, The calendar for the year 2005 will be same for the year 2011

Report Error

View Answer Report Error Discuss

Filed Under: Calendar

96 28422