Quantitative Aptitude - Arithmetic Ability Questions

Manager's monthly salary Rs. (1600 * 21 - 1500 * 20) = Rs. 3600.

6)4456(742
42
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25
24
-------
16
12
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4
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Required number = (6-4) = 2.

Ratio of times taken by A and B = 100 : 130 = 10 : 13.
Suppose B takes x days to do the work.

Then, 10 : 13 :: 23 : x     =>     x = ( 23 x 13/10 )     =>     x = 299 /10.

A's 1 day's work = 1/23 ;
B's 1 day's work = 10/299 .

(A + B)'s 1 day's work = ( 1/23 + 10/299 ) = 23/299 = 113 .

Therefore, A and B together can complete the work in 13 days. 

Let the two parts be Rs. x and Rs. (1301 - x).

 x1+41007=1301-x1+41009

 x1301-x=1+41002=2625*2526

=> 625x=676(1301-x) 

1301x=676 x 1301x=676.
So,the parts are rs.676 and rs.(1301-676)i.e rs.676 and rs.625

The mathematical formula for calculating compound interest depends on several factors. These factors include the amount of money deposited called the principal, the annual interest rate (in decimal form), the number of times the money is compounded per year, and the number of years the money is left in the bank.

 FV=p1+rnnt

FV = Future value of the Deposit

p = Principal or Amount of Money deposited

r = Annual Interest Rate (in decimal form )

n = No of times compounded per year

t = time in years

FV=40001+0.0644(5)= 5387.42

Let 4 girls be one unit and now there are 6 units in all.

They can be arranged in 6! ways.

In each of these arrangements 4 girls can be arranged in 4! ways. 

Total number of arrangements in which girls are always together = 6! x 4!= 720 x 24 = 17280

Average =   (76 + 65 + 82 + 67 + 85 )/ 5 = 375/5   =  75.

Given that 

6 men and 8 boys can do a piece of work in 10 days 

26 men and 48 boys can do the same in 2 days

As the work done is equal,

10(6M + 8B) = 2(26M + 48B)

60M + 80B = 52M + 96B

=> M = 2B

=> B = M/2 ……(1)

Now Put (1) in 15M + 20B

=> 15M + 10M = 25M

Now, 6M + 8B in 10 days

=> (6M + 4M) 10 = 100M

Then D(25M) = 100M

=> D = 4 days.