Quantitative Aptitude - Arithmetic Ability Questions

Let B's capital be Rs. x. 

Then,3500×127x=23

=> 14x = 126000 

=> x = 9000.

A leap year has 52 weeks and two days
Total number of cases = 7
Number of favourable cases = 1
i.e., {Friday, Saturday}

Required Probability = 1/7

 Draw BE // CD

Then, CE = AB = 1.6 m,

BE = AC =

 $$\begin{gathered} DEtan30 \\ => DE = tan30 x 203 \\ => DE = 13x203 = 20 \end{gathered}$$

Therefore, CD = CE + DE = (1.6 + 20) m = 21.6 m.

We cannot find out the answer because the number of days of the current month is not given.

C alone can finish the work in 40 days.
As given C does half as much work as A and B together
=> (A + B) can do it in 20 days
(A + B)s 1 days wok = 1/20.
A's 1 days work : B's 1 days Work = 1/2 : 1 = 1:2(given)
A's 1 day’s work = (1/20) x (1/3) = (1/60) [Divide 1/20 in the raio 1:2]
B's 1 days work = (1/20) x (2/3) = 1/30
(A+B+C)'s 1 day's work = (1/60) + (1/30) + (1/40) = 9/120 = 3/40

All the three together will finish it in 40/3 = 13 and 1/3 days.

Let the breadth of the wall be x metres. 

Then, Height = 5x metres and Length = 40x metres.  

x * 5x * 40x = 12.8   

=>x3 =12.8/200 = 128/2000 =64/1000  

=> x = 4/10 m  

=> x = (4/10)*100 = 40 cm

Let the cost of Production = Rs. P

Then, as per question,

⇒125100×115100×110100×P=1265

=> P=800