6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In order to obtain an income of Rs. 650 from 10% stock at Rs. 96, one must make an investment of:

A) 3100	B) 6240
C) 6500	D) 9600

Answer & Explanation Answer: B) 6240

Explanation:

To obtain Rs. 10, investment = Rs. 96.

To obtain Rs. 650, investment = $R s . \frac{96 * 650}{10}$ = Rs. 6240.

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Filed Under: Stocks and Shares

21 24277

Q:

The compound interest on a sum of money for 2 years is rs.832 and the simple interest on the same sum for the same period is rs.800 .the difference between the compound interest and simple interest for 3 years

A) Rs.48	B) Rs.66.56
C) Rs.98.56	D) None of these

Answer & Explanation Answer: C) Rs.98.56

Explanation:

difference in C.I and S.I in 2years =Rs.32

S.I for 1year =Rs.400

S.I for Rs.400 for one year =Rs.32

rate=[100*32)/(400*1)%=8%

difference between in C.I and S.I for 3rd year

=S.I on Rs.832= Rs.(832*8*1)/100=Rs.66.56

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

43 24277

Q:

If Feb 12th,1986 falls on Wednesday then Jan 1st,1987 falls on which day?

A) Wednesday	B) Tuesday
C) Thursday	D) Friday

Answer & Explanation Answer: C) Thursday

Explanation:

First,we count the number of odd days for the left over days in the given period.

Here,given period is 12.2.1986 to 1.1.1987

Feb Mar Apr May June July Aug Sept Oct Nov Dec Jan

16 31 30 31 30 31 31 30 31 30 31 1 (left days)

2 + 3 + 2 + 3 + 2 + 3 + 3 + 2 + 3 + 2 + 3 + 1(odd days) = 1 odd day

So,given day Wednesday + 1 = Thursday is the required result.

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Filed Under: Calendar

146 24251

Q:

The cash difference between the selling prices of an article at a profit of 4% and 6% is Rs 3. The ratio of two selling prices is

A) 51:52	B) 52:53
C) 53:54	D) 54:55

Answer & Explanation Answer: B) 52:53

Explanation:

Let the Cost price of article is Rs. x

Required ratio = (104% of x) / (106% of x)

=104/106

=52/53 = 52:53

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Filed Under: Profit and Loss

39 24246

Q:

Three taps A,B and C can fill a tank in 12,15 and 20 hours respectively. If A is open all the time and B ,C are open for one hour each alternatively, the tank will be full in:

A) 6 hrs	B) 20/3 hrs
C) 7 hrs	D) 15/2 hrs

Answer & Explanation Answer: C) 7 hrs

Explanation:

$(A + B)' s 1 h o u r w o r k = (\frac{1}{12} + \frac{1}{15}) = \frac{9}{60} = \frac{3}{20}$

$(A + C)' s 1 h o u r w o r k = (\frac{1}{12} + \frac{1}{20}) = \frac{8}{60} = \frac{2}{15}$

$p a r t f i l l e d i n 2 h r s = (\frac{3}{20} + \frac{2}{15}) = \frac{17}{60}$

$p a r t f i l l e d i n 6 h r s = (3 * \frac{17}{60}) = \frac{17}{20}$

$r e m a i n i n g p a r t = (1 - \frac{17}{20}) = \frac{3}{20}$

Now, it is the turn of A and B (3/20) part is filled by A and B in 1 hour.

Therefore, Total time taken to fill the tank =(6+1)hrs= 7 hrs

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Filed Under: Pipes and Cistern

73 24245

Q:

Find the appropriate relation for quantity 1 and quantity 2 in the following question:

An artificial kund is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the kund at the same time during which the kund is filled by the third pipe alone. The second pipe fills the kund 5 hours faster than the first pipe and 4 hours slower than the third pipe.

Quantity 1: The time required by the first pipe?

Quantity 2: Time taken by all three pipes to fill the Kund simultaneously

A) Quantity 1 > Quantity 2	B) Quantity 1 ≥ Quantity 2
C) Quantity 1 < Quantity 2	D) Quantity 1 ≤ Quantity 2

Answer & Explanation Answer: A) Quantity 1 > Quantity 2

Explanation:

Quantity 1:
Let the first pipe alone takes x hours to fill the
tank.
⇒The second and third pipes will take (x-5) and
(x-9) hours respectively.
According to the given information:
∴ $\frac{1}{x - 9}$

⇒ (x-9)(2x-5) = x2 – 5x
⇒ 2x2 – 5x – 18x + 45 = x2 – 5x
⇒ x
2 -18x + 45 = 0
⇒ (x-15) (x-3) = 0
⇒ x = 15, 3

The first pipe can take 15 hours to fill the kund.
∵ 3 hours doesn’t satisfy the statement.
Quantity 2:
∴ Time taken by second pipe = x-5
⇒ Time taken by second pipe = 15-5 = 10hours
∴ Time taken by third pipe = x -9
⇒ Time taken by third pipe = 15- 9 = 6 hours
Now,

Net part filled in 1 hour = $\frac{1}{15} + \frac{1}{10} + \frac{1}{6}$
⇒ Net part filled in 1 hour = $\frac{4 + 6 + 10}{60}$
⇒Net part filled in 1 hour = $\frac{20}{60} = \frac{1}{3}$
∴The Kund will be full in 3/1 hours if all the pipes are opened simultaneously
Now, comparing
15 > 3
Thus, Quantity 1 > quantity 2

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE
Job Role: Bank Clerk , Bank PO

2 24226

Q:

What value should come in place of the question mark (?) in the following question?

$264 \div \sqrt{576} + 11^{2} + 12 = ?^{2}$

A) 44	B) 12
C) 15	D) 14

Answer & Explanation Answer: B) 12

Explanation:
264 / 24 + 121 + 12 = (?)^2 11 + 121 + 12 = (?)^2 144 = (?)^2 (?) = 12

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

0 24214

Q:

If the standard deviation of a population is 3, what would be the population variance?

A) 9	B) 6
C) 8	D) 15

Quantitative Aptitude - Arithmetic Ability Questions

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