6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A booster pump can be used for filling as well as for emptying a tank. The capacity of the tank is 2400 $m^{3}$ . The emptying capacity of the tank is 10 $m^{3}$ per minute higher than its filling capacity and the pump needs 8 minutes lesser to empty the tank than it needs to fill it. What is the filling capacity of the pump?

A) 50 m^3/min	B) 60 m^3/min
C) 72 m^3/min	D) None of these

Answer & Explanation Answer: A) 50 m^3/min

Explanation:

Let the filling capacity of the pump be x $m^{3}$ /min.

Then, emptying capacity of the pump=(x+10) $m^{3}$ /min.

so, $\frac{2400}{x} - \frac{2400}{x + 10} = 8 \Leftrightarrow x^{2} + 10 x - 3000 = 0$

$\Rightarrow (x - 50) + (x + 60) = 0 \Leftrightarrow x = 50$

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Filed Under: Pipes and Cistern
Exam Prep: CAT , Bank Exams , AIEEE
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38 22244

Q:

A number is increased by 20% and then decreased by 20%, the final value of the number is ?

A) increase by 2%	B) decrease by 3%
C) decrease by 4%	D) increase by 5%

Answer & Explanation Answer: C) decrease by 4%

Explanation:

Here, x = 20 and y = - 20
Therefore, the net % change in value
= $x + y + \frac{x y}{100}$ %
= $20 + (- 20) + \frac{20 \times - 20}{100}$ % or - 4%

Since the sign is negative, there is a decrease in value by 4%.

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Filed Under: Percentage
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
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34 22190

Q:

An employee may claim Rs. 7.00 for each km when he travels by taxi and Rs. 6.00 for each km if he drives his own car. If in one week he claimed Rs. 595 for traveling 90 km. How many kms did he travel by taxi ?

A) 55 kms	B) 35 kms
C) 25 kms	D) 65 kms

Answer & Explanation Answer: A) 55 kms

Explanation:

Let x and y be the respective km's travelled by man via taxi and by his own car.
Given x + y = 90 => x = 90 - y
But according to the question,
7x + 6y = 595
7(90-y) + 6y = 595
=> 630 - 7y + 6y = 595
=> y = 630 - 595 = 35
=> x = 90 - 35 = 55
Therefore, the distance travelled by taxi is 55 kms.

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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24 22165

Q:

The interest on a certain deposit at 4.5% p.a. is Rs. 202.50 in one year. How much will the additional interest in one year be on the same deposit at 5% p.a. ?

A) Rs. 22.5	B) Rs. 2.5
C) Rs. 202	D) Rs. 25

Answer & Explanation Answer: A) Rs. 22.5

Explanation:

We know that I = PTR/100
=> P = 20250/4.5 = 4500
Now, new Interest at 5% = 4500x1x5/100 = 225
Now the additional amount = 225 - 202.5 = Rs. 22.5

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Filed Under: Simple Interest
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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18 22143

Q:

In a competitive exam, the number of passed students was four times the number of failed students. If there had been 35 fewer appeared students and 9 more had failed, the ratio of passed and failed students would have been 2 : 1, then the total number of students appered for the exam ?

A) 175	B) 165
C) 155	D) 145

Answer & Explanation Answer: C) 155

Explanation:

Let the number of failed students be x

=> Number of passed students = 4x

So total number of students was 5x

From the given data,

If total number of students be 5x – 35

=> 4x-35-9/x+9 = 2/1

=> 4x – 44 = 2(x + 9)

=> 4x – 2x = 18 + 44

=> x = 31

Total number = 31×5

= 155

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Filed Under: Ratios and Proportions
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43 22140

Q:

The difference between simple and compound interest compounded annually on a certain sum of money for 2 years at 4% per annum is re.1. the sum is

A) 625	B) 630
C) 640	D) 650

Answer & Explanation Answer: A) 625

Explanation:

sum=Rs.x

C.I=[x(1+4/100)^2-x]=(676/625x-x)=51/625

S.I=(x*4*2)/100=2x/25

x=625

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

15 22099

Q:

Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is:

A) 60 gallons	B) 100 gallons
C) 120 gallons	D) 180 gallons

Answer & Explanation Answer: C) 120 gallons

Explanation:

Work done by the waste pipe in 1 minute = $\frac{1}{15} - (\frac{1}{20} + \frac{1}{24}) = \frac{1}{15} - \frac{11}{120} = - \frac{1}{40}$ [-ve sign means emptying]

Volume of $\frac{1}{40}$ part = 3 gallons

Volume of whole = (3 x 40) gallons = 120 gallons.

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Filed Under: Pipes and Cistern
Exam Prep: AIEEE , Bank Exams , CAT
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37 22089

Q:

A sweet seller sells 3/5th part of sweets at a profit of 10% and remaining at a loss of 5%. If the total profit is Rs 1500, then what is the total cost price of sweets ?

A) Rs.37,500	B) Rs.36,400
C) Rs.37,415	D) Rs.36,500

Answer & Explanation Answer: A) Rs.37,500

Explanation:

Assume A be the cost price.

Therefore,
$(\frac{3}{5} \times A \times \frac{10}{100}) - (\frac{2}{5} \times A \times \frac{5}{100}) = 1500$

=> A = Rs 37,500.

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Filed Under: Profit and Loss
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30 22087

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