Quantitative Aptitude - Arithmetic Ability Questions

Let the numerator be x Then, denominator =  x + 3.

Now. (x + 4)/(x + 3) +4 = 4/5  <=> 5 (x + 4) =  4(x + 7)

=>  x = 8.

The fraction is  8/11.

Given 40% minimum passing marks for boys = 483 + 117 = 600
=> 1% = 600/40
=> 100% = 600 x 100/40 = 1500
Minimum passing marks for girls = 35% of 1500 = 35 x 1500/100 = 525.

150 men in 25 days do = 14 work  

Let 1 man in 1 day does = x  work  

Total work done by 150 men in 25 days = 150x *  25 = 14   work => x = 115000   

Therefore, 100 men in 60 days do = 100 * 60x = 6000x work = 6/15 = 2/5

Total work done =14 + 25 = 1320 

Therefore, Remaining work = 1 - 1320 = 720  

Remaining time = 130 - (25+60+10) = 35 days 

Therefore, work is done in 25 days by 150 men.

Therefore, Work is done in 35 days by 150 men.

Hence, he should employ 50 more men.

$$\begin{gathered} 23x35x34x?=3174 \\ 3174x10/3 \\ = 10580 \end{gathered}$$

Minute hand covers 5400/60 = 90°

Ratio  of speeds of A:B = 1000:900 = 100:90

Ratio of speeds of B:C = 1000:920 = 100:92

Therefore, when A moves 1000m , B moves 900 m and when B moves 900m, C moves 828m

Thus,             

Since , C moves 8 % less than B in the same time . Thus, C is the worst performer and A will win by him by 172 m

Let last digit is 2
when second last digit is 4 remaining 4 digits can be filled in 120 ways, similarly second last digit is 6 remained 4 digits can be filled in 120 ways.
so for last digit = 2, total numbers=240

Similarly for 4 and 6
When last digit = 4, total no. of ways =240
and last digit = 6, total no. of ways =240
so total of 720 even numbers are possible.