6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

What is the total surface area of a right circular cone of height 14 cm and base radius 7 cm?

A) 344.35 sq.cm	B) 462 sq.cm
C) 498.35 sq.cm	D) None of these

Answer & Explanation Answer: C) 498.35 sq.cm

Explanation:

h = 14 cm, r = 7 cm.

So, l = $[\sqrt{7^{2} + 14^{2}}] = \sqrt{245} = 7 \sqrt{5} c m$

Total surface area = $πrl + {πr}^{2}$ = $\frac{22}{7} \times 7 \times 7 \sqrt{5} + \frac{22}{7} \times 7 \times 7$

= $154 (\sqrt{5} + 1)$

= (3.236 x 154) sq.cm

= 498.35 sq.cm

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Filed Under: Volume and Surface Area

6 16465

Q:

A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey ?

A) 5 kmph	B) 7 kmph
C) 3 kmph	D) 4 kmph

Answer & Explanation Answer: D) 4 kmph

Explanation:

Speed of Man = 4.5 kmph
Speed of stream = 1.5 kmph
Speed in DownStream = 6 kmph
Speed in UpStream = 3 kmph
Average Speed = (2 x 6 x 3)/9 = 4 kmph.

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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16 16463

Q:

The difference of $\frac{1}{8}$ and its reciprocal is equal to :

A) 1/8	B) 4/3
C) 15/16	D) 105/304

Answer & Explanation Answer: D) 105/304

Explanation:

Required difference = 19/16 - 16/19 = 105/304..

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Filed Under: Simplification

43 16417

Q:

16 children are to be divided into two groups A and B of 10 and 6 children. The average percent marks obtained by the children of group A is 75 and the average percent marks of all the 16 children is 76. What is the average percent marks of children of group B ?

A) 233/3	B) 243/4
C) 254/5	D) 345/7

Answer & Explanation Answer: A) 233/3

Explanation:

Required average = [(76 * 16) - (75 * 10)] / 6 = (1216 - 750)/6 = 466/3 = 233 /3.

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Filed Under: Average

13 16416

Q:

What will be the compound interest on a sum of Rs.25,000 after 3 years at the rate of 12 p.c.p.a?

A) Rs.10123.20	B) Rs.12100
C) Rs.12552	D) Rs.12665

Answer & Explanation Answer: A) Rs.10123.20

Explanation:

Amount

= Rs.(25000x(1+12/100)³

= Rs.(25000x28/25x28/25x28/25)

= Rs. 35123.20.

C.I = Rs(35123.20 -25000)

= Rs.10123.20

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Filed Under: Compound Interest
Exam Prep: GRE

17 16406

Q:

If the rate increases by 2%, the simple interest received on a sum of money increases by Rs. 108. If the time period is increased by 2 years, the simple interest on the same sum increases by Rs.180. The sum is ?

A) Rs. 540	B) Rs. 415
C) Rs. 404	D) Data is not sufficient

Answer & Explanation Answer: D) Data is not sufficient

Explanation:

Let the sum be Rs. p, rate be R% p.a. and time be T years.

Then,

$(\frac{P \times T \times (R + 2)}{100}) - (\frac{P \times T \times R}{100}) = 108 \Rightarrow 2 P T = 10800 . . . . . . (1)$

And,

$(\frac{P \times R \times (T + 2)}{100}) - (\frac{P \times R \times T}{100}) = 180 \Rightarrow 2 P R = 18000 . . . . . . (2)$

Clearly, from (1) and (2), we cannot find the value of p
So, the data is not sufficient.

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Filed Under: Simple Interest
Exam Prep: GRE , GATE , CAT , Bank Exams
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11 16373

Q:

What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad ?

A) 844	B) 814
C) 840	D) 820

Answer & Explanation Answer: B) 814

Explanation:

Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) sq.cm

Required number of tiles =1517 x 902/(41 x 41) = 814.

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Filed Under: Area
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8 16372

Q:

Excluding stoppages, the average speed of a bus is 60 km/hr and including stoppages, the average speed of the bus is 40 km/hr. For how many minutes does the bus stop per hour ?

A) 2 hrs	B) 20 min
C) 40 min	D) 30 min

Answer & Explanation Answer: B) 20 min

Explanation:

In 1hr, the bus covers 60 km without stoppages and 40 km with stoppages.

Stoppage time = time take to travel (60 - 40) km i.e 20 km at 60 km/hr.

stoppage time = 20/60 hrs = 20 min.

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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12 16345

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