6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

What is the sum which earned interest?
I. The total simple interest was Rs. 7000 after 7 years.
II. The total of sum and simple interest was double of the sum after 5 years.

A) I alone sufficient while II alone not sufficient to answer	B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer	D) Both I and II are necessary to answer

Answer & Explanation Answer: D) Both I and II are necessary to answer

Explanation:

Let the sum be Rs. x.

I gives, S.I. = Rs. 7000 and T = 7 years.

II gives, Sum + S.I. for 5 years = 2 x Sum Sum = S.I. for 5 years.

Now, S.I. for 7 years = Rs. 7000.

therefore, S.I. for 1 year = Rs. 1000.

Thus, I and II both are needed to get the answer.

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Filed Under: Simple Interest
Exam Prep: GRE
Job Role: Bank PO

3 11339

Q:

A cylindrical rod of iron, whose height is equal to its radius, is melted and cast into spherical balls whose radius is half the radius of the rod. Find the number of balls.

A) 3	B) 4
C) 5	D) 6

Answer & Explanation Answer: D) 6

Explanation:

Volume of rod = ${πr}^{2} h$ = ${πr}^{2} \times r$ = ${πr}^{3}$

Volume of one spherical ball =r/2

Volume of the spherical ball = $\frac{\frac{4}{3} {πr}^{3}}{8}$

Number of balls=Volumeof rod/volumeof one ball

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams
Job Role: Bank PO

15 11328

Q:

Raghu earns 25% on an investment but loses 10% on another investment. If the ratio of the two investment is 3:5. What is the gain or loss on two investments taken together ?

A) 1.251 %	B) 3.125 %
C) 7.21 %	D) 9.451 %

Answer & Explanation Answer: B) 3.125 %

Explanation:

Taking the 2 investments to be 3x and 5x respectively
Total income of Raghu = (3x) x 1.25 + (5x) x 0.9 = 8.25
Therefore, Gain% = 0.25/8 x 100 = 3.125 %.

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

11 11325

Q:

What was the day of the week on 28th May, 2006?

A) Thursday	B) Friday
C) Saturday	D) Sunday

Answer & Explanation Answer: D) Sunday

Explanation:

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Filed Under: Calendar

16 11317

Q:

On what dates of April, 2001 did Wednesday fall ?

A) 1st, 8th, 15th, 22nd, 29th	B) 2nd, 9th, 16th, 23rd, 30th
C) 3rd, 10th, 17th, 24th	D) 4th, 11th, 18th, 25th

Answer & Explanation Answer: D) 4th, 11th, 18th, 25th

Explanation:

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Filed Under: Calendar

10 11310

Q:

The marked price of an article is increased by 25% and the selling price is increased by 16.66%, then the amount of profit doubles. If the original marked price be Rs. 400 which is greater than the corresponding cost price by 33.33%, what is the increased selling price?

A) Rs. 380	B) Rs. 420
C) Rs. 460	D) Rs. 440

Answer & Explanation Answer: B) Rs. 420

Explanation:

As given in the question, Marked price is 25% more than the Cost price.

=> C.P of the article = $\frac{3}{4} x 400 = 300$

Now,

Let the original S.P of the article be Rs. P

Now the new S.P = P + $\frac{(16.666 + 13.333)}{300} x P$

=> S.P = $\frac{7 P}{6}$

According to the question,

$\frac{7 P}{6} - 300 = 2 (P - 300)$

=> 5P = 1800

=> P = Rs. 360

Hence, the increased S.P = 360 x 7/6 = Rs. 420.

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , IT Trainer

11 11302

Q:

A house owner wants to get his house painted. He is told that this would require 45 kg of paint allowing 6% wasting. And if the paint is available in 4 kg tins only, the number of tins required for painting the house is ?

A) 12	B) 13
C) 11	D) 10

Answer & Explanation Answer: A) 12

Explanation:

Given 45 kg for painting

And 6% 0f 45 for wasting => 6x45/100 = 2.7 kg

Now total paint required = 45+2.7 = 47.7 kgs

But tins are available in only 4kgs

Then, no. of tins req = 47.7/4 = 11.4 => 12 tins

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

14 11287

Q:

66 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be:

A) 84	B) 90
C) 168	D) 336

Answer & Explanation Answer: A) 84

Explanation:

Let the length of the wire be h.

Radius r =1/2 mm = 1/20 cm

${πr}^{2} h = 66$

=> h= (66 x 20 x 20) x (7/22) = 8400cm = 84m

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Filed Under: Volume and Surface Area

5 11283

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