Quantitative Aptitude - Arithmetic Ability Questions

Q:

A man saves Rs. 200 in each of the first three months of his service. In each of the subsequent months his saving increases by Rs. 40 more than the saving of immediately previous month. His total saving from the start of service will be Rs. 11040 after ?

A) 19 months B) 21 months
C) 18 months D) 20 months
 
Answer & Explanation Answer: B) 21 months

Explanation:

Total savings = 200 + 200 + 200 + 240 + 280 + ... to n months = 11040

= 120 + 80 + 160 + 40 + 200 + 240 + ....n terms
= 40 + 80 + 120 + 160 + 200 + 240 + ...n terms
= n/2[2a + (n-1)d] + 80 + 40 = 11040
= n/2[240 + (n-1)40] = 10920
= n[6+n-1] = 546
= n[n+5] = 546
n = 21

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10 11059
Q:

In what time would a cistern be filled by three pipes which diameters are 2 cm, 3 cm and 4 cm running together, when the largest alone can fill it is 58 minutes? The amount of water flowing in each pipe is proportional to the square of its diameter.

A) 26 min B) 32 min
C) 36 min D) 42 min
 
Answer & Explanation Answer: B) 32 min

Explanation:

Given that the diameters of the three pipes are 2 cm, 3 cm and 4 cm

From the given data,

Amount of water from three pipes is 4 units, 9 units and 16 units.

Let the capacity of cistern be 'p' units.

∴ p/58 = 16

⇒ p = 928 units.

 

In 1 minute, quantity to be filled by 3 pipes = 29 units

∴ Total time required = 928/29 = 32 minutes.

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Filed Under: Pipes and Cistern
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11 11044
Q:

The circumference of a circle, whose area is 24.64 sq.m

A) 14.64 B) 16.36
C) 17.60 D) 18.40
 
Answer & Explanation Answer: C) 17.60

Explanation:

πr2 =26.64

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Filed Under: Area
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11 11033
Q:

A and B can fill the tank in 60 min and 90 min. There is a leak at 3/4th of the height. If leak is opened alone, it takes 36 min to empty till 3/4th the height. Find the time taken to fill the tank if all of the taps and the leak are opened simultaneously.

A) 39 B) 27
C) 37 D) 33
 
Answer & Explanation Answer: A) 39

Explanation:
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Filed Under: Pipes and Cistern
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50 11030
Q:

Two trains are running at 60 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 6 seconds. What is the length of the fast train ?

A. 6623 mts

B. 6632 mts

C.6345 mts

D. 6354 mts

A) Option A B) Option B
C) Option C D) Option D
 
Answer & Explanation Answer: A) Option A

Explanation:

As Trains are moving in same direction,

Relative Speed = 60-20 = 40 kmph

--> 40×518=1009 m/sec

 

Length of Train= Speed * Time

 

Length = 1009×6

2003=6623 mts 

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Filed Under: Problems on Trains
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12 11019
Q:

A train for Fathehpur leaves for every 2 hrs 30 min from Agra station. An announcement was made that train left 37 mins ago and next train comes at 17:00hrs. At what time was the announcement made ? 

A) 15:07 hrs B) 15:20 hrs
C) 15:05 hrs D) 15:00 hrs
 
Answer & Explanation Answer: A) 15:07 hrs

Explanation:

Next train comes at 17:00 hrs.
So, last train will be = 17:00hrs - 2:30hrs
= 14:30hrs
Announcement made after 37 min of the last train.
S0, 14:30hrs + 00:37 min
= 15:07 hrs.

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10 11013
Q:

A vertical toy 18 cm long casts a shadow 8 cm long on the ground. At the same time a pole casts a shadow 48 m. long on the ground. Then find the height of the pole ?

A) 1080 cm B) 180 m
C) 108 m D) 118 cm
 
Answer & Explanation Answer: C) 108 m

Explanation:

We know the rule that,

 

At particular time for all object , ratio of height and shadow are same.

 

Let the height of the pole be 'H'

 

Then

 188=H48

 

=> H = 108 m.

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Filed Under: Height and Distance
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19 11008
Q:

If the HCF of 210 and 55 is expressible in the form of 210 x 5 + 55P, then value of P = ?

A) -23 B) 27
C) 16 D) -19
 
Answer & Explanation Answer: D) -19

Explanation:

HCF of 210 and 55 is 5

Now, 210x5 + 55P = 5

=> 1050 + 55P = 5

=> 55P = -1045

=> P = -1045/55

=> P = -19.

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Filed Under: HCF and LCM
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28 11006