Quantitative Aptitude - Arithmetic Ability Questions

Q:

A vertical toy 18 cm long casts a shadow 8 cm long on the ground. At the same time a pole casts a shadow 48 m. long on the ground. Then find the height of the pole ?

A) 1080 cm B) 180 m
C) 108 m D) 118 cm
 
Answer & Explanation Answer: C) 108 m

Explanation:

We know the rule that,

 

At particular time for all object , ratio of height and shadow are same.

 

Let the height of the pole be 'H'

 

Then

 188=H48

 

=> H = 108 m.

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Filed Under: Height and Distance
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19 11122
Q:

A and B can fill the tank in 60 min and 90 min. There is a leak at 3/4th of the height. If leak is opened alone, it takes 36 min to empty till 3/4th the height. Find the time taken to fill the tank if all of the taps and the leak are opened simultaneously.

A) 39 B) 27
C) 37 D) 33
 
Answer & Explanation Answer: A) 39

Explanation:
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Filed Under: Pipes and Cistern
Exam Prep: Bank Exams
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50 11120
Q:

In what time would a cistern be filled by three pipes which diameters are 2 cm, 3 cm and 4 cm running together, when the largest alone can fill it is 58 minutes? The amount of water flowing in each pipe is proportional to the square of its diameter.

A) 26 min B) 32 min
C) 36 min D) 42 min
 
Answer & Explanation Answer: B) 32 min

Explanation:

Given that the diameters of the three pipes are 2 cm, 3 cm and 4 cm

From the given data,

Amount of water from three pipes is 4 units, 9 units and 16 units.

Let the capacity of cistern be 'p' units.

∴ p/58 = 16

⇒ p = 928 units.

 

In 1 minute, quantity to be filled by 3 pipes = 29 units

∴ Total time required = 928/29 = 32 minutes.

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Filed Under: Pipes and Cistern
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11 11110
Q:

The circumference of a circle, whose area is 24.64 sq.m

A) 14.64 B) 16.36
C) 17.60 D) 18.40
 
Answer & Explanation Answer: C) 17.60

Explanation:

πr2 =26.64

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

11 11103
Q:

If the HCF of 210 and 55 is expressible in the form of 210 x 5 + 55P, then value of P = ?

A) -23 B) 27
C) 16 D) -19
 
Answer & Explanation Answer: D) -19

Explanation:

HCF of 210 and 55 is 5

Now, 210x5 + 55P = 5

=> 1050 + 55P = 5

=> 55P = -1045

=> P = -1045/55

=> P = -19.

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Filed Under: HCF and LCM
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28 11100
Q:

The area of a square is 1024 sq.cm. What is the ratio of the length to the breadth of a rectangle whose length is twice the side of the square and breadth is 12 cm less than the side of this square ?

A) 14:9 B) 13:12
C) 16:5 D) 17:13
 
Answer & Explanation Answer: C) 16:5

Explanation:

Area of a square SxS = 1024 => S = 32 cm
Length of the rectangle = 32x2 cm = 64 cm
Breadth of the rectangle = 32 - 12 = 20 cm
Required ratio = 64 : 20 = 16 : 5

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Filed Under: Area
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5 11087
Q:

Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case ?

A) 1020 B) 1040
C) 1060 D) 1022
 
Answer & Explanation Answer: D) 1022

Explanation:

Lowest 4-digit number is 1000.
LCM of 3, 4 and 5 is 60.
Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 - 40) = 1020.
Now, add the remainder 2 that's required. Thus, the answer is 1022.

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Filed Under: Problems on Numbers
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11 11077
Q:

Divide Rs.118000 among three persons A, B and C such that the ratio of the shares of A and B is 3:4 and that of B:C is 5:6 ?

A) A = 48000 B = 40000 C = 30000 B) A = 30000 B = 40000 C = 48000
C) A = 30000 B = 48000 C = 40000 D) A = 40000 B = 48000 C = 30000
 
Answer & Explanation Answer: B) A = 30000 B = 40000 C = 48000

Explanation:

Compound ratio of A:B:C
A:B = 3:4
B:C = 5:6
----------
A:B:C = 15:20:24

We can divide Rs.118000 in this ratio.

Share of A = 15/59 x 118000 = 30000

Share of B = 20/59 x 118000 = 40000

Share of C = 24/59 x 118000 = 48000

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Filed Under: Partnership
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4 11067