Quantitative Aptitude - Arithmetic Ability Questions

Q:

It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010 ?

A) Sunday B) Friday
C) Monday D) Tuesday
 
Answer & Explanation Answer: B) Friday

Explanation:

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

On 1st Jan 2006, it was Sunday.

Thus, On 1st Jan, 2010 it is Friday.

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Filed Under: Calendar
Exam Prep: CAT , Bank Exams , AIEEE
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53 10729
Q:

Two consecutive discounts x% and y% is equivalent to the discount

A) (x-y+xy100)% B) (x+y+xy100)%
C) (x-y-xy100)% D) (x+y-xy100)%
 
Answer & Explanation Answer: D) (x+y-xy100)%

Explanation:
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Filed Under: Banker's Discount
Exam Prep: Bank Exams

1 10713
Q:

A cicketer bas a certain average for 10 innings, In the eleventh inning, he scorod 108 runs, thereby increasing his average by 6 runs. His new average is :

A) 44 runs B) 46 runs
C) 48 runs D) 49 runs
 
Answer & Explanation Answer: C) 48 runs

Explanation:

Let average for 10 innings be x. Then,

(10x + 108)/11 = x + 6 => 11x + 66 = 10x + 108  =>  x = 42.

New average = (x + 6) = 48 runs.

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Filed Under: Average

3 10699
Q:

If x is 90% of Y, what percent of x is y?

Answer

x = 90% of y = \inline \frac{9}{10}y


 


\inline \therefore \frac{x}{y}=\frac{9}{10}\Rightarrow \frac{y}{x}=\frac{10}{9} 


=> y = 1.1% of x.

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Subject: Percentage

25 10688
Q:

When the hands are in the opposite directions,they are ------- minute spaces apart,

A) 15 B) 30
C) 60 D) 0
 
Answer & Explanation Answer: B) 30

Explanation:
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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank PO

16 10687
Q:

On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ?

A) 14 B) 16
C) 12 D) 15
 
Answer & Explanation Answer: D) 15

Explanation:

Let 'K' be the total number of sweets.
Given total number of students = 112
If sweets are distributed among 112 children,
Let number of sweets each student gets = 'L'

=> K/112 = L ....(1)
But on that day students absent = 32 => remaining = 112 - 32 = 80
Then, each student gets '6' sweets extra.

=> K/80 = L + 6 ....(2)
from (1) K = 112L substitute in (2), we get
112L = 80L + 480
32L = 480
L = 15

Therefore, 15 sweets were each student originally supposed to get.

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Filed Under: Average
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10 10687
Q:

A train sets off at 3 p.m. at the speed of 70 kmph. Another train starts at 4:30 p.m. in the same direction at the rate of 85 kmph. At what time the trains will meet ?

A) 10:10 pm B) 9:50 pm
C) 11:30 pm D) 10:30 pm
 
Answer & Explanation Answer: C) 11:30 pm

Explanation:

Distance = 70 x 1 ½ = 105 km

Relative Speed = 85 – 70 = 15

Time = 105/15 = 7 hrs

4:30 + 7 hrs = 11.30 p.m.

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Filed Under: Problems on Trains
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14 10670
Q:

If 1/8 of a pencil is black, 1/2 of the remaining is white and the remaining, 3/2cm is blue. Find the total length of the pencil?

A) 8 cms B) 7 cms
C) 9 cms D) 11 cms
 
Answer & Explanation Answer: A) 8 cms

Explanation:

Let the total length of the pencil = x cms

From the given data,

'x/8' is black

Remaining part = x - x/8 = 7x/8

1/2 of 7x/8 is white

=> 7x/16 is white (Remaining part is 7x/16)

And given that the remaining part is blue and is 3 1/2 cm = 7/2 = 3.5 cm

That remaining part = 7x/16

Therefore,

7x/16 = 7/2

x = 16/2 = 8

Hence, the total length of the pencil = x = 8 cm.

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

17 10661