Quantitative Aptitude - Arithmetic Ability Questions

Q:

3x + y = 19  and x + 3y = 1. Find the value of 2x + 2y

A) 20 B) 18
C) 11 D) 10
 
Answer & Explanation Answer: D) 10

Explanation:

To solve a pair of simultaneous equations such as those given we can add or subtract them.

Adding we get 4x + 4y = 20

Therefore 2x + 2y = 10

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Filed Under: Numbers
Exam Prep: GRE

10 10207
Q:

R enter into a partnership in the ratio 2 : 3 : 5 . After 2 months, P increases his share 20% and Q by 10%. If the total profit at the end of one year is Rs 1,90,500, what amount will 'R' receive at the end of year as share in profit ?

A) Rs. 90500 B) Rs. 87500
C) Rs. 88900 D) Rs. 90000
 
Answer & Explanation Answer: D) Rs. 90000

Explanation:

Ratio of investments for 1 year

=> (P : Q : R) = (2x2 + 2.4x10) : (3x2 + 3.3x10) : (5x12)

=> (P : Q : R) = 28 : 39 : 60

Now R share = 190500 x 60/127 = Rs. 90000.

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Filed Under: Partnership
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

10 10169
Q:

A man goes down stream with a boat to some destination and returns upstream to his original place in 5 hours. If the speed of the boat in still water and the strean are 10km/hr and 14km/hr respectively, the distance of the destination from the string place is 

A) 16 km B) 18 km
C) 21 km D) 25 km
 
Answer & Explanation Answer: C) 21 km

Explanation:

Let the distance covered be D km. 

 D10+4+ D10-4 = 5

 D14+D6=5

 10D = 42 x 5 = 210

 

=> D = 21 km

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

32 10166
Q:

Three maths classes: A, B and C take an algebra test. The average score of class A is 83. The average score of class B is 76. The average score of class C is 85. The average score of class A and B is 79 and average score of class B and C is 81. What is the average score of classes A, B, C ?

A) 81 B) 78
C) 80.5 D) 81.5
 
Answer & Explanation Answer: D) 81.5

Explanation:

Let the number of students in classes A, B and C be P, Q and R respectively.
Then, total score of A = 83P, total score of B = 76Q, total score of C = 85R.
Also given that,
(83P + 76Q) / (P + Q) = 79
=>4P = 3Q.
(76Q + 85R)/(Q + R) = 81
=>4R = 5Q,
=>Q = 4P/3 and R = 5P/3
Therefore, average score of A, B, C = ( 83P + 76Q + 85R ) / (P + Q + R) = 978/12 = 81.5

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Filed Under: Average
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12 10159
Q:

The certain worth of a certain sum due sometime hence is Rs. 1600 and the true discount is

Rs. 160. The banker's gain is:

A) 15 B) 16
C) 14 D) 13
 
Answer & Explanation Answer: B) 16

Explanation:

B.G. =(T.D.)^2/P.W.

      = Rs. (160*160)/1600 = Rs. 16.

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Filed Under: Banker's Discount

1 10155
Q:

Mr. Gupta borrowed a sum of money on compound interest. What will be the amount to
be repaid if he is repaying the entire amount at the end of 2 years?
I. The rate of interest is 5 p.c.p.a.
II. Simple interest fetched on the same amount in one year is Rs. 600.
III. The amount borrowed is 10 times the simple interest in 2 years.

A) .I only B) III only
C) I or II D) II and Either I or III only
 
Answer & Explanation Answer: D) II and Either I or III only

Explanation:

   I. gives, Rate = 5% p.a.

 

 II. gives, S.I. for 1 year = Rs. 600.

 

III. gives, sum = 10 x (S.I. for 2 years).

 


 Now I, and II give the sum.


 For this sum, C.I. and hence amount can be obtained.


 Thus, III is redundant.


 Again, II gives S.I. for 2 years = Rs. (600 x 2) = Rs. 1200.


 Now, from III, Sum = Rs. (10 x 1200) = Rs . 12000.


Thus,Rate =100*12002*12000 =5%


Thus, C.I. for 2 years and therefore, amount can be obtained.


Thus, I is redundant.



Hence, I or III redundan
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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

5 10154
Q:

When all the students in a school are made to stand in rows of 54, 30 such rows are formed. If the students are made to stand in rows of 45, how many such rows will be formed ?

A) 22 B) 36
C) 32 D) 26
 
Answer & Explanation Answer: B) 36

Explanation:

Total number of students = 54 x 30
When arranged in rows of 45, number of rows formed are,
54x3045 = 36.

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Filed Under: Average
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Job Role: Bank PO , Bank Clerk

10 10152
Q:

A single reservoir supplies the petrol to the whole city, while the reservoir is fed by a single pipeline filling the reservoir with the stream of uniform volume. When the reservoir is full and if 40,000 liters of petrol is used daily, the suply fails in 90 days.If 32,000 liters of petrol is used daily, it fails in 60 days. How much petrol can be used daily with out the supply ever failing? 

A) 64000 liters B) 56000 liters
C) 78000 liters D) 60000 liters
 
Answer & Explanation Answer: B) 56000 liters

Explanation:

Let x liter be the per day filling and v litr be the capacity of the reservoir, then 

      90x + v = 40000 * 90     -----(1)

      60x + v= 32000 * 60     ------(2)

solving eq.(1) and (2) , we get

      x = 56000

Hence , 56000 liters per day can be used without the failure of supply.

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Filed Under: Time and Work

8 10152