6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

45 men working 9 hours per day dig 40 m deep. How many extra men should be put to dig to a depth of 56 m working 7 hours per day ?

A) 36	B) 61
C) 48	D) 54

Answer & Explanation Answer: A) 36

Explanation:

(45 x 9)/40 = (M x 7)/56 => M = 81

=> 81 – 45 = 36

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Filed Under: Time and Work
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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6 10199

Q:

A drink vendor has 368 liters of Maaza, 80 liters of Pepsi and 144 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required ?

A) 47	B) 46
C) 37	D) 35

Answer & Explanation Answer: C) 37

Explanation:

The number of liters in each can = HCF of 80, 144 and 368 = 16 liters.
Number of cans of Maaza = 368/16 = 23
Number of cans of Pepsi = 80/16 = 5
Number of cans of Sprite = 144/16 = 9
The total number of cans required = 23 + 5 + 9 = 37 cans.

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Filed Under: HCF and LCM
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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31 10195

Q:

A train is traveling at 48 kmph . It crosses another train having half of its length , traveling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. What is the length of the platform ?

A) 500	B) 400
C) 360	D) 480

Answer & Explanation Answer: B) 400

Explanation:

Speed of train 1 = 48 kmph
Let the length of train 1 = 2x meter

Speed of train 2 = 42 kmph
Length of train 2 = x meter (because it is half of train 1's length)

Distance = 2x + x = 3x
Relative speed= 48+42 = 90 kmph = (90*5/18) m/s = 25 m/s

Time = 12 s

Distance/time = speed

=>3x/12 = 25 $\Rightarrow$ (25*12)/3

Length of the first train = 2x = 200 meter
Time taken to cross the platform= 45 s

Speed of train 1 = 48 kmph = 480/36 = 40/3 m/s

Distance = 200 + y [where y is the length of the platform]

x =100m => 200+y = 45* 40/3
$\Rightarrow$ y = 400m

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Filed Under: Problems on Trains

13 10193

Q:

Running 3/4th of his usual rate, a man is 15min late. Find his usual time in hours ?

A) 2/3 hrs	B) 3/4 hrs
C) 1/3 hrs	D) 1/4 hrs

Answer & Explanation Answer: B) 3/4 hrs

Explanation:

Walking at 3/4th of usual rate implies that time taken would be 4/3th of the usual time. In other words, the time taken is 1/3rd more than his usual time

so 1/3rd of the usual time = 15min
or usual time = 3 x 15 = 45min = 45/60 hrs = 3/4 hrs.

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Filed Under: Time and Distance
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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5 10172

Q:

If x is chosen at random from the set {1,2,3,4} and y is to be chosen at random from the set {5,6,7}, what is the probability that xy will be even?

A) 1/2	B) 2/3
C) 3/4	D) 4/3

Answer & Explanation Answer: B) 2/3

Explanation:

S ={(1,5),(1,6),(1,7),(2,5),(2,6),(2,7),(3,5),(3,6),(3,7),(4,5),(4,6),(4,7)}
Total element n(S)=12

xy will be even when even x or y or both will be even.
Events of x, y being even is E.
E ={(1,6),(2,5),(2,6),(2,7),(3,6),(4,5),(4,6),(4,7)}
n(E) = 8

P(E)=n(E)n(S)=812 = 4/3

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Filed Under: Probability

15 10169

Q:

Divide Rs.6500 among A,B and C so that after spending 90% , 75% and 60% of their respective saving were in the ratio of 3: 5: 6

Answer

A's spending 90% $\inline \therefore$ saving = 10%

B's spending 75% $\therefore$ saving = 25%

C's spending 60% $\inline \therefore$ saving = 40%

Let us suppose A, B and C saves Rs. 3.5 and 6 respectively.

$\inline \therefore$ 10% of A's saving = Rs.3

100% of A's saving = $\inline \frac{3}{10}\times 100$ = Rs. 30

25% of B's saving = Rs. 5

100% of B's saving = $\inline \frac{5}{25}\times 100$ = Rs. 20

40% of C's saving = Rs.6

100% of C's saving = $\inline \frac{6}{40}\times 100$ = Rs. 15

Divide Rs. 6500 in the ratio of 30 : 20 : 15 as

A's Share = $\inline \frac{30}{65}\times 6500$ = Rs. 3000

B's Share = $\inline \frac{20}{65}\times 6500$ = Rs. 2000

C's Share = $\inline \frac{15}{65}\times 6500$ = Rs. 1500

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Subject: Ratios and Proportions
Job Role: Bank PO

66 10169

Q:

X can complete the work in 10 days, Y can do the same in 15 days. If they are hired for 5 days to do the work together, what is the work that left unfinished?

A) 1/3	B) 2/3
C) 1/6	D) 5/6

Answer & Explanation Answer: C) 1/6

Explanation:

Given X can do in 10 days

=> 1 day work of X = 1/10

Y can do in 15 days

=> 1 day work of Y = 1/15

1day work of (X + Y) = 1/10 + 1/15 = 1/6

Given they are hired for 5 days

=> 5 days work of (X + Y) = 5 x 1/6 = 5/6

Therefore, Unfinished work = 1 - 5/6 = 1/6

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Filed Under: Time and Work
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11 10161

Q:

A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?

A) 22	B) 44
C) 66	D) 88

Quantitative Aptitude - Arithmetic Ability Questions

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