6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?

A) 22	B) 44
C) 66	D) 88

Answer & Explanation Answer: D) 88

Explanation:

We have: l = 20 ft and lb = 680 sq. ft.So, b = 34 ft.

Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

3 10113

Q:

Divide Rs.6500 among A,B and C so that after spending 90% , 75% and 60% of their respective saving were in the ratio of 3: 5: 6

Answer

A's spending 90% $\inline \therefore$ saving = 10%

B's spending 75% $\therefore$ saving = 25%

C's spending 60% $\inline \therefore$ saving = 40%

Let us suppose A, B and C saves Rs. 3.5 and 6 respectively.

$\inline \therefore$ 10% of A's saving = Rs.3

100% of A's saving = $\inline \frac{3}{10}\times 100$ = Rs. 30

25% of B's saving = Rs. 5

100% of B's saving = $\inline \frac{5}{25}\times 100$ = Rs. 20

40% of C's saving = Rs.6

100% of C's saving = $\inline \frac{6}{40}\times 100$ = Rs. 15

Divide Rs. 6500 in the ratio of 30 : 20 : 15 as

A's Share = $\inline \frac{30}{65}\times 6500$ = Rs. 3000

B's Share = $\inline \frac{20}{65}\times 6500$ = Rs. 2000

C's Share = $\inline \frac{15}{65}\times 6500$ = Rs. 1500

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Subject: Ratios and Proportions
Job Role: Bank PO

66 10110

Q:

A contractor undertook to complete a piece of work in 120 Days and employed 140 men upon it. At the end of 66 days only half of the work was done,so he put on 25 extra men. By how much time did he exceed the specific time ?

A) 2 days	B) 3 days
C) 4 days	D) 5 days

Answer & Explanation Answer: A) 2 days

Explanation:

work done=total number of person x number of days;
half of work done = 140 x 66;
For half of remaining work 25 extra men are added.
Therefore, total men for half work remaining = 140 + 25 = 165;
Let 2nd half work will be completed in K days;
140 x 66 = 165 x K
K = 122;
Hence, extra days => 122-120 = 2days.

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Filed Under: Time and Work
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

12 10109

Q:

An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ?

A) 21.4 and 42.8	B) 25.2 and 50.4
C) 31.4208 and 62.8416	D) 33.12 and 66.24

Answer & Explanation Answer: C) 31.4208 and 62.8416

Explanation:

Birds speeds in mtrs/sec is 'x' and '2x' .
While flying from Engine to end, relative speed = (x+10) m/sec
from end to engine, flying speed = (2x - 10) mtr/sec
so
1000/(x+10) + 1000/(2x-10) = 187.5 secs
solving it, we get
so x = 8.728 m/sec and 2x= 17.456 m/sec

x = 31.4208 km/hr and 2x = 62.8416 km/hr.

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

11 10068

Q:

Running 3/4th of his usual rate, a man is 15min late. Find his usual time in hours ?

A) 2/3 hrs	B) 3/4 hrs
C) 1/3 hrs	D) 1/4 hrs

Answer & Explanation Answer: B) 3/4 hrs

Explanation:

Walking at 3/4th of usual rate implies that time taken would be 4/3th of the usual time. In other words, the time taken is 1/3rd more than his usual time

so 1/3rd of the usual time = 15min
or usual time = 3 x 15 = 45min = 45/60 hrs = 3/4 hrs.

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Filed Under: Time and Distance
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

5 10061

Q:

$17 \frac{4}{7} + 13 \frac{2}{12} - ? = 11 \frac{2}{3}$

A) 16	B) 17
C) 18	D) 19

Answer & Explanation Answer: D) 19

Explanation:

$17 \frac{4}{7} + 13 \frac{2}{12} - ? = 11 \frac{2}{3}$

$\frac{123}{7} + \frac{158}{12} - ? = \frac{35}{3}$

=> $? = \frac{123}{7} + \frac{158}{12} - \frac{35}{3}$

=> ? = $\frac{1476 + 1106 - 980}{84}$

=> ? = 19.07

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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

13 10058

Q:

X can complete the work in 10 days, Y can do the same in 15 days. If they are hired for 5 days to do the work together, what is the work that left unfinished?

A) 1/3	B) 2/3
C) 1/6	D) 5/6

Answer & Explanation Answer: C) 1/6

Explanation:

Given X can do in 10 days

=> 1 day work of X = 1/10

Y can do in 15 days

=> 1 day work of Y = 1/15

1day work of (X + Y) = 1/10 + 1/15 = 1/6

Given they are hired for 5 days

=> 5 days work of (X + Y) = 5 x 1/6 = 5/6

Therefore, Unfinished work = 1 - 5/6 = 1/6

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Filed Under: Time and Work
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

11 10054

Q:

The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 9000, brokerage being $\frac{1}{4}$ % is :

A) Rs.108.25	B) Rs.112.20
C) Rs.124.75	D) Rs.125.25

Answer & Explanation Answer: C) Rs.124.75

Explanation:

For an income of Rs.756, investment = Rs.9000

For an income of Rs. $\frac{21}{2}$ , investment = $R s . (\frac{9000}{756} * \frac{21}{2})$ = Rs.125

For a Rs.100 stock, investment = Rs.125.

Market value of Rs. 100 stock = $R s . (125 - \frac{1}{4})$ = Rs. 124.75

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Filed Under: Stocks and Shares

4 10051

Quantitative Aptitude - Arithmetic Ability Questions

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