6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ?

A) 21.4 and 42.8	B) 25.2 and 50.4
C) 31.4208 and 62.8416	D) 33.12 and 66.24

Answer & Explanation Answer: C) 31.4208 and 62.8416

Explanation:

Birds speeds in mtrs/sec is 'x' and '2x' .
While flying from Engine to end, relative speed = (x+10) m/sec
from end to engine, flying speed = (2x - 10) mtr/sec
so
1000/(x+10) + 1000/(2x-10) = 187.5 secs
solving it, we get
so x = 8.728 m/sec and 2x= 17.456 m/sec

x = 31.4208 km/hr and 2x = 62.8416 km/hr.

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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11 10134

Q:

The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 9000, brokerage being $\frac{1}{4}$ % is :

A) Rs.108.25	B) Rs.112.20
C) Rs.124.75	D) Rs.125.25

Answer & Explanation Answer: C) Rs.124.75

Explanation:

For an income of Rs.756, investment = Rs.9000

For an income of Rs. $\frac{21}{2}$ , investment = $R s . (\frac{9000}{756} * \frac{21}{2})$ = Rs.125

For a Rs.100 stock, investment = Rs.125.

Market value of Rs. 100 stock = $R s . (125 - \frac{1}{4})$ = Rs. 124.75

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Filed Under: Stocks and Shares

4 10132

Q:

$17 \frac{4}{7} + 13 \frac{2}{12} - ? = 11 \frac{2}{3}$

A) 16	B) 17
C) 18	D) 19

Answer & Explanation Answer: D) 19

Explanation:

$17 \frac{4}{7} + 13 \frac{2}{12} - ? = 11 \frac{2}{3}$

$\frac{123}{7} + \frac{158}{12} - ? = \frac{35}{3}$

=> $? = \frac{123}{7} + \frac{158}{12} - \frac{35}{3}$

=> ? = $\frac{1476 + 1106 - 980}{84}$

=> ? = 19.07

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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

13 10123

Q:

A is 50% more efficient than B. They together start the work and 7/12th of work is left after 8 days. Find in what time B alone will complete the whole work.

A) 36 days	B) 44 days
C) 50 days	D) 40 days

Answer & Explanation Answer:

Explanation:

Ratio of efficiency of A to B is 3 : 2

Let, In 8 days they complete = (3 + 2) × 8 = 40 units

So, total work = 40 × 12/5 units

Time taken by B alone to complete whole work = 40 × 12/5 ×2 = 48 days

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Filed Under: Time and Work
Exam Prep: AIEEE , Bank Exams , CAT

5 10107

Q:

In how many years, Rs. 200 will produce the same interest @ 5 % as Rs. 900 produce in 2 years @ 3 ½ % ?

A) 5.2 yrs	B) 7 yrs
C) 7.9 yrs	D) 6.3 yrs

Answer & Explanation Answer: D) 6.3 yrs

Explanation:

P = Rs. 900, R = 3 ½ % = 7/2 %, T = 2 years.

Therefore,

S.I. = PTR/100

S.I. = Rs. (900 x 7/2 x 2/100) = Rs. 63

Now, P = Rs. 200, S.I. = Rs. 63, R = 5 %

Time = ((100 x 63) / (200 x 5) ) years = 6.3 years.

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Filed Under: Simple Interest
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6 10091

Q:

A loan shark made a loan of $100 to be repaid with $120 at the end of one month. What was the annual interest rate?

A) 210%	B) 220%
C) 230%	D) 240%

Answer & Explanation Answer: D) 240%

Explanation:

r=I/PT

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

5 10088

Q:

Find the principal if the interest compounded at the rate of 10% per annum for two years is Rs. 420 ?

A) Rs. 2000	B) Rs. 2100
C) Rs. 1900	D) Rs. 2150

Answer & Explanation Answer: A) Rs. 2000

Explanation:

Given,
Compound rate, R = 10% per annum
Time = 2 years
C.I = Rs. 420
Let P be the required principal.
A = (P+C.I)
Amount, A = $P {(1 + (\frac{r}{100}))}^{n}$

(P+C.I) = $P {[1 + (\frac{10}{100})]}^{2}$

(P+420) = P[11/10][11/10]

P-1.21P = -420

0.21P = 420

Hence, P = 420/0.21 = Rs. 2000

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Filed Under: Compound Interest
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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7 10086

Q:

There are five cards lying on the table in one row. Five numbers from among 1 to 100 have to be written on them, one number per card, such that the difference between the numbers on any two adjacent cards is not divisible by 4. The remainder when each of the 5 numbers is divided by 4 is written down on another card (the 6th card) in order. How many sequences can be written down on the 6th card ?

A) 4 x 3^4	B) 3^4
C) 4^3	D) 3 x 4^3

Answer & Explanation Answer: A) 4 x 3^4

Explanation:

The remainder on the first card can be 0,1,2 or 3 i.e 4 possibilities.
The remainder of the number on the next card when divided by 4 can have 3 possible values (except the one occurred earlier).

For each value on the card the remainder can have 3 possible values.

The total number of possible sequences is: 4*3^4

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Filed Under: Permutations and Combinations

3 10079

Quantitative Aptitude - Arithmetic Ability Questions

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