6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In the following question, select the odd letter/letters from the given alternatives.

A) ABDG	B) PQSV
C) JKMQ	D) NOQT

Answer & Explanation Answer: C) JKMQ

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

5 73492

Q:

Find the value of

199992 x 200008 = ?

A) 39999799936	B) 39999999836
C) 39999999936	D) 39999999926

Answer & Explanation Answer: C) 39999999936

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

0 73398

Q:

The average of five consecutive odd numbers is 61. What is the difference between the highest and lowest numbers :

A) 4	B) 8
C) 12	D) 16

Answer & Explanation Answer: B) 8

Explanation:

Let the numbers be x, x + 2, x + 4, x + 6 and x + 8.

Then [x + (x + 2) + (x + 4) + (x + 6) + (x + 8) ] / 5 = 61.

or 5x + 20 = 305 or x = 57.

So, required difference = (57 + 8) - 57 = 8

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Filed Under: Average

237 73210

Q:

If log 2 = 0.3010 and log 3 = 0.4771, the values of log₅ 512 is

A) 2.875	B) 3.875
C) 4.875	D) 5.875

Answer & Explanation Answer: B) 3.875

Explanation:

ANS: log₅512 = log512/log5 = $\frac{\log 2^{9}}{\log (10 / 2)}$ = $\frac{9 \log 2}{\log 10 - \log 2}$ = $\frac{9 * 0.3010}{1 - 0.3010}$ =2.709/0.699 =2709/699 =3.876

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Filed Under: Logarithms
Exam Prep: Bank Exams
Job Role: Bank PO

211 73151

Q:

Consider the following for real numbers α, β, γ and δ ?

1) sec α = 1/4

2) tan β = 20

3) cosec γ = 1/2

4) cos δ = 2

How many of the above statements are not possible?

A) one	B) two
C) three	D) four

Answer & Explanation Answer: C) three

Explanation:

Sec of any number can never be less than 1

tan can take any value from -∞ to + ∞

cosec of any number can never be less than 1

cos of any number can never be greater than 1

so option 1,3,4 are not possible

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Filed Under: Simplification
Exam Prep: Bank Exams

1 73047

Q:

What will be the day of the week 15th August, 2010?

A) Sunday	B) Saturday
C) Wednesday	D) Monday

Answer & Explanation Answer: A) Sunday

Explanation:

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 = 4 odd days.

Jan. Feb. Mar. Apr. May. Jun. Jul. Aug.

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days = (32 weeks + 3 days) = 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 = 0 odd days.

Given day is Sunday

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Filed Under: Calendar

550 72950

Q:

What was the day of the week on 17th June, 1998 ?

A) Monday	B) Tuesday
C) Wednesday	D) Friday

Answer & Explanation Answer: C) Wednesday

Explanation:

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March. April. May. June.
(31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.

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Filed Under: Calendar
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO

423 71868

Q:

What approximate value will come in place of the question mark(?) in the below question?

(47% of 1442 - 36% of 1412) + 63 = ?

A) 4	B) 5
C) 3	D) 6

Quantitative Aptitude - Arithmetic Ability Questions

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