Quantitative Aptitude - Arithmetic Ability Questions

Q:

In a charity show tickets numbered consecutively from 101 through 350 are placed in a box. What is the probability that a ticket selected at random (blindly) will have a number with a hundredth digit of 2?

A) 0.25 B) 0.5
C) 0.75 D) 0.40
 
Answer & Explanation Answer: D) 0.40

Explanation:

250 numbers between 101 and 350 i.e. n(S)=250

n(E)=100th digits of 2 = 299−199 = 100

P(E)= n(E)/n(S) = 100/250 = 0.40

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Filed Under: Probability

3 9862
Q:

A Shepherd had n goats in the year 2000. In 2001 the no.of goats increased by 40% . In 2002 the no. of goats declined to 70%. In 2003 the no. of  goats grew by 30%. In 2004, he sold 10% goats, then he had only 34,398 goats. The percentage increase of the no.of goats in this duration was:

A) 14.66% B) 16.66%
C) 20% D) 33.33%
 
Answer & Explanation Answer: A) 14.66%

Explanation:

There is no need to use the no of goats i.e (34,398). let initially thete be 1000 goats then 

 

  1000 -----> 1400 -----> 980 -----> 1274 ----->1146.6

 

Thus the % increase = (1146.6-1000)/100 x 100= 14.66%

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Filed Under: Percentage
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7 9843
Q:

Find the cube root of 287496

 

A) 64 B) 46
C) 56 D) 66
 
Answer & Explanation Answer: D) 66

Explanation:
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Filed Under: Square Roots and Cube Roots
Exam Prep: Bank Exams

1 9834
Q:

A jogger running at 9 km/hr along side a railway track is 260 m ahead of the engine of a 140 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger ?

A) 25 sec B) 40 sec
C) 38 sec D) 32 sec
 
Answer & Explanation Answer: B) 40 sec

Explanation:

Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 x 5/18 = 10 m/sec.

Distance to be covered = 260 + 140 = 400 m.

Time taken = 400/10 = 40 sec.

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Filed Under: Problems on Trains
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5 9827
Q:

The average of a non-zero number and its square is 11 times the number. The number is ?

A) 22 B) 21
C) 11 D) 17
 
Answer & Explanation Answer: A) 22

Explanation:

Let the number be 'x'.

 

 

 

x+x22 = 11x
x2= 22x
=> x = 22.

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Filed Under: Average
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8 9814
Q:

Pooja, Shipra and Mounika are three sisters .Pooja and Shipra are twins. The ratio of sum of the ages of Pooja and Shipra is same as that of Mounika alone. Three years earlier the ratio of age of  Pooja and Mounika was 2:7 . what will be the age of Shipra 3 years hence?

A) 21 years B) 16 years
C) 8 years D) 12 years
 
Answer & Explanation Answer: C) 8 years

Explanation:

Since Pooja and Shipra are twins so their ages be same. Let their ages be x and age of Mounika be y , then 

           x+x = y    -------(1) 

 and   x-3y-3=277x-2y=15 

 

Now, from  equation (1), 

         7x - 4x = 15  =>  x = 5

So the age of Shipra 3 years hence will be 5+3 = 8 years

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Filed Under: Ratios and Proportions

12 9811
Q:

There are eight boxes of chocolates, each box containing distinct number of chocolates from 1 to 8. In how many ways four of these boxes can be given to four persons (one boxes to each) such that the first person gets more chocolates than each of the three, the second person gets more chocolates than the third as well as the fourth persons and the third person gets more chocolates than fourth person? 

A) 70 B) 40
C) 72 D) 80
 
Answer & Explanation Answer: A) 70

Explanation:

All the boxes contain distinct number of chocolates.
For each combination of 4 out of 8 boxes, the box with the greatest number has to be given to the first person, the box with the second highest to the second person and so on.

 

The number of ways of giving 4 boxes to the 4 person is: 8C4= 70

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5 9810
Q:

If a trader sold two cars each at Rs. 325475 and gains 12% on the first and loses 12% on the second, then his profit or loss percent on the whole is ?

A) 1.44% loss B) 14.4% loss
C) 0% D) 14.4% profit
 
Answer & Explanation Answer: A) 1.44% loss

Explanation:

SP of each car is Rs. 325475, he gains 12% on first car and losses 12% on second car.
In this case, there will be loss and percentage of loss is given by

= [(profit%)(loss%)]/100 = (12)(12)/100 % = 1.44%

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Filed Under: Profit and Loss
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2 9803