Quantitative Aptitude - Arithmetic Ability Questions

Let F and C denotes the temparature in Fahrenheit anid Celcsius respectively.

Then, (F - 32) /(212 - 32) = (C - 0)/(100 - 0),  if c = 35, then F = 95.

area of the plot = 120m x 60m = 7200 sq.m
area of plot excluding gravel = 117m x 57m = 6669 sq.m
area of gravel = 7200 sq.m - 6669 sq.m = 531 sq.m
cost of building it = 531 sq.m x 65 ps = 34515 ps
In Rs. = 34515/100 = Rs. 345.15.

Work done by P and Q in the first two hours, working alternately

= First hour P + Second hour Q

⇒14+112=13

work is completed in 2 hours

Then, the total time required to complete the work by P and Q working alternately=2 x 3= 6hours

Thus, work will be completed at 3pm.

9th May, 2001 = (2000 years + Period from 1.1.2001 to 9.5.2001)

Odd days in 1600 years = 0

Odd days in 400 years = 0

Jan. Feb. March April May 

(31 + 28 + 31 + 30 + 9) = 129 days

129 days = (18 weeks + 3 day)= 3 odd day.

Total number of odd days = (0 + 0 + 3 ) = 3 odd day.

Given day is Wednesday.

Ratio of girls and boys = 100% : 75% = 4:3

Difference is 1 unit = 35

So, 3 units = 35 x 3 = 105

If 20% absent, that’s mean 80% present.

So, present boys = 80% of 105 = 80×105100 = 84

Number of square units in 13 by 9 is given by the area it forms with length and breadth as 13 & 9

Area = 13 x 9 = 117

Hence, number of square units in 13 by 9 is 117 sq.units.

 Let AB be the lighthouse and C and D be the positions of the ships.

Then, AB = 100m, ∠ACB = 30°and∠ADB =45°

ABAC=tan30°=13=>AC=AB*3=1003m

 ABAD=tan45°=1=>AD=AB=100m

CD=(AC+AD)=1003+100m=1003+1=100*2.73=273m

0.75 = 75/100 = 3/4