6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A company requires 12,100 strength. Present employees are 400 ladies and 6400 gents. To reach the target how many ladies required to maintain the same ratio ?

A) 400	B) 600
C) 900	D) 700

Answer & Explanation Answer: C) 900

Explanation:

6,400 gents, 2400 ladies in that company.
So total 8,800employees.
for 8,800 employees, we want 2400 ladies.
for 12,100employees we want how many ladies ?
=> (12,100/8,800) x 2400 = 3300.
So we want 3300 - 2400 = 900 more ladies.

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Filed Under: Ratios and Proportions
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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11 8184

Q:

The average monthly salary of 24 employees in an organisation is Rs. 1500. If the manager's salary is added, then the average salary increases by Rs. 400. What is the manager's monthly salary ?

A) Rs. 8840	B) Rs. 11,500
C) Rs. 12,800	D) Rs. 9450

Answer & Explanation Answer: B) Rs. 11,500

Explanation:

Manager's monthly salary

= Rs. (1900 x 25 - 1500 x 24) = Rs. 11,500

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Filed Under: Average
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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11 8177

Q:

6 pumps of kirlosker can fill a tank in 7 days and 2 similar pumps of USHA can fill the same tank in 18 days. what is the ratio of the efficiency of a kirlosker pump and a USHA pump?

A) 6:7	B) 7:6
C) 7:54	D) None of these

Answer & Explanation Answer: A) 6:7

Explanation:

The number of days required by a single kirlosker pump to fill the tank = 6 x 7 =42 days and the number of days required by a single USHA pump to fill the same tank = 2 x 18 =36 days.

Now , since efficiency is inversely proportional to the number of days. Hence,

$\frac{E f f i c i e n c y o f o n e K - p u m p}{E f f i c i e n c y o f U - p u m p} = \frac{36}{42} = \frac{6}{7}$

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Filed Under: Ratios and Proportions

7 8161

Q:

Every year before the festive season, a brand store increases the price of the product by 42% and then introduce two successive discount of 10% and 11% respectively. What is percentage loss and percentage gain ?

A) 3.25% loss	B) 13.742% loss
C) 3.25% gain	D) 13.742% gain

Answer & Explanation Answer: D) 13.742% gain

Explanation:

Let CP = 100,
42 % increase => SP = 142
10 % discount in SP => ((142 x 10)/100) = 14.2
So 1st SP = (142 - 14.2) = 127.8, again 12 % discount in 1st SP ((127.8 x 11)/100) = 14.058
2nd SP = (127.8 - 14.058) = 113.742,
So finally CP = 100, SP = 113.742, => gain = 13.742%.

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Filed Under: Profit and Loss
Exam Prep: Bank Exams , CAT , GATE , GRE
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11 8142

Q:

The present ages of Kavitha, Rajitha and Haritha are in the ratio of 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

A) 16,36,28	B) 16,28,36
C) 20,35,45	D) 12,21,27

Answer & Explanation Answer: B) 16,28,36

Explanation:

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Filed Under: Problems on Ages
Exam Prep: Bank Exams

33 8140

Q:

Two letters are randomly chosen from the word TIME. Find the probability that the letters are T and M?

A) 1/4	B) 1/6
C) 1/8	D) 4

Answer & Explanation Answer: B) 1/6

Explanation:

Required probability is given by P(E) = $\frac{n (E)}{n (S)} = \frac{1}{4 C_{2}} = \frac{1}{6}$

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Filed Under: Probability
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20 8129

Q:

An amount of money was lent for 3 years. What will be the difference between the simple and the compound interest earned on it at the same rate?
I. The rate of interest was 8 p.c.p.a.
II. The total amount of simple interest was Rs. 1200

A) I alone sufficient while II alone not sufficient to answer	B) alone sufficient while I alone not sufficient to answer
C) Both I and II are not sufficient to answer	D) Both I and II are necessary to answer

Answer & Explanation Answer: D) Both I and II are necessary to answer

Explanation:

Given: T = 3 years.
I. gives: R = 8% p.a.
II. gives: S.I. = Rs. 1200.
Thus, P = Rs. 5000, R = 8% p.a. and T = 3 years.
Difference between C.I. and S.I. may be obtained.
So, the correct answer is (D).

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

0 8122

Q:

A jar was full with honey. A person used to draw out 20% of the honey from the jar and replaced it with sugar solution. He has repeated the same process 4 times and thus there was only 512 gm of honey left in the jar, the rest part of the jar was filled with the sugar solution. The initial amount of honey in the jar was:

A) 1.25 kg	B) 1 kg
C) 1.5 kg	D) None of these

Answer & Explanation Answer: A) 1.25 kg

Explanation:

Let the initial amount of honey in the jar was k, then

$512 = k {(1 - \frac{1}{5})}^{4} o r 512 = k {(\frac{4}{5})}^{4}$

=> $k = \frac{512 \times 625}{256}$

=> k = 1250

Hence initially the honey in the jar = 1.25 kg

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Filed Under: Alligation or Mixture
Exam Prep: CAT , Bank Exams , AIEEE
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23 8113

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