6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Simplyfiy : $[3 \frac{1}{4} \div \{1 \frac{1}{4} - \frac{1}{2} (2 \frac{1}{2} - (\frac{1}{4} + \frac{1}{6}))\}]$

A) 78	B) 88
C) 98	D) 108

Answer & Explanation Answer: A) 78

Explanation:

Given exp = $[\frac{13}{4} \div \{\frac{5}{4} - \frac{1}{2} (\frac{5}{2} - \frac{3 - 2}{12})\}]$ = $[\frac{13}{4} \div \{\frac{5}{4} - \frac{1}{2} (\frac{5}{2} - \frac{1}{12})\}]$

= $[\frac{13}{4} \div \{\frac{5}{4} - \frac{1}{2} (\frac{30 - 1}{12})\}]$ = $[\frac{13}{4} \div \{\frac{5}{4} - \frac{29}{24}\}]$

= $[\frac{13}{4} \div \frac{30 - 29}{24}]$ =78

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Filed Under: Simplification

4 6450

Q:

What is the missing number in 5, 14, 42, 107, 233, ?

A) 316	B) 384
C) 450	D) 479

Answer & Explanation Answer: C) 450

Explanation:

Given Series is 5, 14, 42, 107, 233, _?

5, 14, 42, 107, 233, _?

Differences is 9, 28, 65, 126

9 = 2^3 + 1

28 = 3^3 + 1

65 = 4^3 + 1

126 = 5^3 + 1

Now, next difference must be 6^3 + 1 = 217

Hence, next number in the given series = 233 + 217 = 450.

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Filed Under: Odd Man Out
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4 6444

Q:

The true discount on a certain sum of money due 3 year hence is Rs.100 and the S.I. on the same sum for the same time and at the same rate is Rs.120. Find the sum and the rate percent.

A) (6 + 2/3)%	B) (5+ 2/3)%
C) (2+ 2/3)%	D) (4+ 2/3)%

Answer & Explanation Answer: A) (6 + 2/3)%

Explanation:

Sum ⇒ Amount

A = (SI x TD)/(SI - TD)

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Filed Under: True Discount
Exam Prep: Bank Exams
Job Role: Bank PO

3 6427

Q:

The average age of a group of 10 students is 15 years. When 5 more students join the group, the average age increase by 1 year. The average age of the new student is?

Answer

Total age of 10 students = 150 years

Total age of 15 students = 240 years

Total age of 5 new students = 240 - 150 = 90 years

$\therefore$ Average age of 5 new students = 90/5 = 18 years.

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Subject: Problems on Ages

5 6422

Q:

A passenger train is moving at a speed of 120 km/hr. If the length of the train is 101 meters, how long will it take to cross a railway platform 154 meters long ?

A) 6.24 sec	B) 6.58 sec
C) 7.325 sec	D) 7.65 sec

Answer & Explanation Answer: D) 7.65 sec

Explanation:

Here total distance = 154 + 101 = 255 mts
Given speed = 120 kmph = 120x5/18 m/sec
Hence, Time = d/s = 255x18/120x5 = 7.65 sec

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Filed Under: Problems on Trains
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8 6418

Q:

In an election between two candidates 70% of the voters cast their votes, out of which 2% of the votes were declared invalid. A candidate got 7203 votes which was 60% of the total valid votes. Find the total number of voters enrolled in that election.

A) 18050	B) 17500
C) 17000	D) 7203

Answer & Explanation Answer: B) 17500

Explanation:

Let total number of votes enrolled = x
No. of voted cast = 70% of x = 0.7x
Valid votes = 98% of 0.7x
⇒ 60% of total valid votes = 7203 = 60% of 98% of 0.7x
⇒ 0.6 X 0.98 X 0.7x = 7203
⇒ x = 7203 / (0.6 X 0.98 X 0.7)
⇒ x = 17500

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Filed Under: Percentage
Exam Prep: Bank Exams

1 6403

Q:

In a triangle ABC, angle 'a' is the smallest one & A+7B = 112. Find the range of value 'c' ?

A) 138 to 164	B) 125 to 147
C) 148 to 158	D) 152 to 164

Answer & Explanation Answer: D) 152 to 164

Explanation:

A+7B=112

it is clear that A = 14, then it becomes A>=B, but A is smallest angle) given
so, range of A is 0.0001 to 13.9999 ( I am taking upto 4 decimal places)
so, range of B becomes 14 to 16 ( after rounding off to 4 decimal places)
so, range of C becomes 152 to 164 ( after rounding off to 4 decimal places)

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Filed Under: Numbers
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8 6402

Q:

Prasanna invested certain amount in three different schemes X, Y and Z with the rate of interest 10% p.a, 12% p.a and 15% p.a respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme Z was 150% of the amount invested in Scheme X and 240% of the amount invested in Scheme Y, what was the amount invested in Scheme Y by Prasanna ?

A) Rs.6000	B) Rs.4500
C) Rs.7500	D) Rs.5000

Answer & Explanation Answer: D) Rs.5000

Explanation:

Let a, b and c be the amounts invested in schemes X, Y and Z respectively. Then,

As we know:

Simple interest (S.I.) = PTR/100

(a × 10 × 1/100) + (b × 12 × 1/100) + (c × 15 × 1/100) = 3200

= 10a + 12b + 15c = 320000 .........(1)

Now, c = 240% of b = 12b/5 .........(2)

And, c = 150% of a = 3a/2 => a = 2/3 c = (2 × 12)b/(3 × 5) = 8b/5 .......(3)

From (1), (2) and (3), we have

16b + 12b + 36b = 320000 => 64b = 320000 => b = 5000

∴ Sum invested in Scheme Y = Rs.5000.

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Filed Under: Percentage
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9 6383

Quantitative Aptitude - Arithmetic Ability Questions

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