Quantitative Aptitude - Arithmetic Ability Questions

Q:

From a deck of 52 cards, a 7 card hand is dealt.How many distinct hands are there if the hand must contain 2 spades and 3 diamonds ?

A) 7250100 B) 7690030
C) 7250000 D) 3454290
 
Answer & Explanation Answer: A) 7250100

Explanation:

There are 13 spades,we must include 2: 13C2

 

There are 13 diamonds,we must include 3: 13C3

 

Since we can't have more than 2 spades and 3 diamonds,the remaining 2 cards must be pulled out from the 26 remaining clubs and hearts : 26C2

 

Therefore,13C2*13C3*26C2 = 7250100

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Q:

Ajay and his wife Reshmi appear in an interview for two vaccancies in the same post. The Probability of Ajay's selection is 1/7 and that of his wife Reshmi's selection is 1/5. What is the probability that only one of them will be selected?

A) 5/7 B) 1/5
C) 2/7 D) 2/35
 
Answer & Explanation Answer: C) 2/7

Explanation:

P( only one of them will be selected) = p[(E and not F) or (F and not E)] 

 = PEFFE 

 

PEPF+PFPE

 

 =17×45+15×67=27

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Filed Under: Probability
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Q:

When 52416 is divided by 312, the quotient is 168. what will be the quotient when 52.416 is divided by 0.0168?

A) 3.12 B) 312
C) 3120 D) None of these
 
Answer & Explanation Answer: C) 3120

Explanation:

Given, 52416312=168 52416168=312 

 

Now , 52.4160.0168=5241616.8=52416168×10 =312×10=3120

 

 

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Filed Under: Decimal Fractions

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Q:

Consider 5 independent Bernoulli’s trials each with probability of success p. If the probability of at least one failure is greater than or equal to 31/32 , then p lies in the interval ?

A) [1, 32] B) (0, 1)
C) [1, 1/2] D) (1, 1/2]
 
Answer & Explanation Answer: C) [1, 1/2]

Explanation:

Probability of atleast one failure
= 1 - no failure > 31/32
= 1 - P5 > 31/32
=  P5<1/32
= p < 1/2
Also p > 0
Hence p lies in [0,1/2].

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Q:

Application of Inverse Proportion

If 20 persons can do a piece of work in 7 days then calculate the number of persons require to complete the work in 28 days

Answer

Number of persons * days = work  


20 * 7 = 140 man- days 


 


Now,  x * 28  = 140 men- days


=> x =5         


Therefore in second case the required number of person is 5.


 


Second method:


Since work is constant, therefore  M1 x D1= M2 x D2


20 x 7 = M2 x 28


=> M2 = 5 


 

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Subject: Time and Work

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Q:

How many arrangements of the word TRIGONAL can be made if only two vowels and three consonants are used?

A) 6300 B) 3600
C) 6400 D) 7200
 
Answer & Explanation Answer: B) 3600

Explanation:

First we need to choose two vowels 3C2 and then three consonants 5C3. Now that we have 5 letters required to make the word,arrange them in 5! ways.

 

So,3C2*5C3*5! = 3600

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Q:

Salaries of Karthik, Arun and Akhil were in the ratio 4 : 5 : 6 respectively. If their salaries were increased by 50 per cent, 60 per cent and 50 per cent respectively, what will be the new ratio of the salaries of Akhil, Arun and Karthik ?

A) 6 : 8 : 9 B) 8 : 6 : 9
C) 9 : 8 : 6 D) 6 : 5 : 4
 
Answer & Explanation Answer: C) 9 : 8 : 6

Explanation:

Given the salaries are in the ratio of 4 : 5 : 6

 

Now the salaries are increased by 50%, 60% and 50% respectively

 

The New ratio of salaries will be

 

4 x (150/100) : 5 x (160/100) : 6 x (150/100)

 

= 6 : 8 : 9

 

The new ratio of salaries of Akhil, Arun and Karthik is 9 : 8 : 6

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Filed Under: Ratios and Proportions
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Q:

There are 1650 students in a college. The difference between the number of boys and girls in the college is 400. What is the percentage of girls in the college ?

A) 49 B) 34
C) 43 D) 38
 
Answer & Explanation Answer: D) 38

Explanation:

Let no. of boys be 'B' and no. of girls be 'G'

Here from given data,

B + G = 1650 .....(1)

B - G = 400 .....(2)

From (1) & (2), we get

2B = 2050

=> B = 1025

=> G = 1650 - 1025 = 625

Hence, the % of girls = 625 x 100/1650

=> 38% (approx).

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Filed Under: Percentage
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