Quantitative Aptitude - Arithmetic Ability Questions

Q:

When 52416 is divided by 312, the quotient is 168. what will be the quotient when 52.416 is divided by 0.0168?

A) 3.12 B) 312
C) 3120 D) None of these
 
Answer & Explanation Answer: C) 3120

Explanation:

Given, 52416312=168 52416168=312 

 

Now , 52.4160.0168=5241616.8=52416168×10 =312×10=3120

 

 

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Filed Under: Decimal Fractions

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Q:

10 boys can complete a work in 7 days and 10 girls take 14 days to complete the work. How many days will 5 boys and 10 girls take to complete the work ?

A) 13 days B) 10 days
C) 7 days D) 16 days
 
Answer & Explanation Answer: C) 7 days

Explanation:

1 boy's 1 day work = 1/70

1 girl's 1 day work = 1/140

(5 boys + 10 girls)'s 1 day work = (5/70 + 10/140) = (1/14 + 1/14) = 1/7

 

5 boys and 10 girls will complete the work in 7 days.

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Filed Under: Time and Work
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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Q:

How many arrangements of the word TRIGONAL can be made if only two vowels and three consonants are used?

A) 6300 B) 3600
C) 6400 D) 7200
 
Answer & Explanation Answer: B) 3600

Explanation:

First we need to choose two vowels 3C2 and then three consonants 5C3. Now that we have 5 letters required to make the word,arrange them in 5! ways.

 

So,3C2*5C3*5! = 3600

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1 6491
Q:

The Number of times the digit 8 will be written when listing the integers from 1 to 1000 is :

A) 100 B) 200
C) 300 D) 400
 
Answer & Explanation Answer: C) 300

Explanation:

 Since 8 does not occur in 1000, we have to count the number of times 8 occurs when we list the integers from 1 to 999. Any number between 1 and 999 is of the form xyz, where 0x,y,z9.

 

Let us first count the numbers in which 8 occurs exactly once.

 

Since 8 can occur atone place in 3C1ways. There are 3 x 9 x 9  such numbers.

 

Next, 8 can occur in exactly two places in 3C2×9 such numbers. Lastly, 8 can occur in all three digits in one number only.

  

Hence, the number of times 8 occur is 

 1×3×92+2×3×9+3×1 = 300

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Q:

A Cricket team of 23 people all shake hands with each other exactly once. How many hand shakes occur ?

A) 142 B) 175
C) 212 D) 253
 
Answer & Explanation Answer: D) 253

Explanation:

The first person shakes hands with 22 different people, the second person also shakes hands with 22 different people, but one of those handshakes was counted in the 22 for the first person, so the second person actually shakes hands with 21 new people. The third person, 20 people, and so on...
So,
22 + 21 + 20 + 19 + 18 + 17 + 16 + 15 + 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1
= n(n+1)/2 = 22 x 23 /2 = 11 x 23 = 253.

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Filed Under: Permutations and Combinations
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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4 6485
Q:

The payment per hour for a daily-wages employee is increased by 33.33 and the working time is reduced by 33.33%. What is the percentage change in the employee's income ?

A) 11.11% decrease B) 21.11% increase
C) 11.11% increase D) 21.11% decrease
 
Answer & Explanation Answer: A) 11.11% decrease

Explanation:

If earlier he is getting Rs. 1  per hr and working for 1 hr, income = Rs. 1
Now he is getting Rs 1.3333 per hr and working for 0.66667 hrs

Then income for 0.66667 hrs = Rs. 0.8889.

If payment per hr is increased by 33.33 %  and working hours dereased by 33.33%, then 11.11 % decrease in income.

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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Q:

The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?

A) 16cm B) 18cm
C) 24cm D) .Data inadequate
 
Answer & Explanation Answer: B) 18cm

Explanation:

2(l+b)/b = 5/1 

=> 2l + 2b = 5b  

=> 3b = 2l  

=> b =(2/3) x l

 Then, Area = 216 sq.cm 

 

l x b = 216  

=> l x [(2/3)x l] =216  

=> l x l = 324 

=> l = 18 cm.

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0 6477
Q:

Application of Inverse Proportion

If 20 persons can do a piece of work in 7 days then calculate the number of persons require to complete the work in 28 days

Answer

Number of persons * days = work  


20 * 7 = 140 man- days 


 


Now,  x * 28  = 140 men- days


=> x =5         


Therefore in second case the required number of person is 5.


 


Second method:


Since work is constant, therefore  M1 x D1= M2 x D2


20 x 7 = M2 x 28


=> M2 = 5 


 

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Subject: Time and Work

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