Quantitative Aptitude - Arithmetic Ability Questions

Q:

A $1000 face value Series S50 compound interest Canada Savings Bond (CSB) was presented to a credit union branch for redemption.What amount did the owner receive if the redemption was requested on:January 17, 2001?

A) 1206 B) 1306
C) 1406 D) 1506
 
Answer & Explanation Answer: B) 1306

Explanation:

I  = ptr

Therefore, the total amount the owner received on January 17, 2001 was

$1295.57 + $10.47 = $1306.04

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Filed Under: Compound Interest
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Q:

The ratio of the speed of a boat downstream and speed of the stream is 9:1. If the speed of the current is 3 km per hr, find the distance travelled by the boat upstream in 5 hours.

A) 100 km B) 98 km
C) 109 km D) 105 km
 
Answer & Explanation Answer: D) 105 km

Explanation:

Let the speed of boat in still water is ‘x’ km/hr & that of stream is ‘y’ km/hr.
Then, ATQ
(x+y)/y = 9/1 9y = x + y
x = 8y
y = 3 km/hr
So, x = 24 km/hr
Upstream speed = 24-3 = 21 km/hr
Hence, distance travelled upstream in 5 hours = 21*5 = 105 km.

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Filed Under: Boats and Streams
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9 5740
Q:

Present ages of Deepa and Hyma are in the ratio of 5:6 respectively. After four years, this ratio becomes 6: 7. What is the difference between their present ages?

A) 6 yrs B) 4 yrs
C) 8 yrs D) 2 yrs
 
Answer & Explanation Answer: B) 4 yrs

Explanation:

Let the present age of Deepa = 5p

Let the present age of Hyma = 6p

After four years their ratio = 6 : 7

=> 5p + 46p + 4 = 67

=> 35p + 28 = 36p + 24

=> p = 4

Therefore, the difference between their ages = 24 - 20 = 4 years.

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Filed Under: Problems on Ages
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12 5734
Q:

72 ÷ 52 × 3272 ÷ 52 of 32 ÷ 5.25

A) 3/5 B) 3/6
C) 3/7 D) 3/8
 
Answer & Explanation Answer: C) 3/7

Explanation:

75x321415 ÷ 52510094 ÷ 5251009002100= 37

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Filed Under: Simplification
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1 5732
Q:

When John arrives in New York,he has eight stops to see, but he has time only to visit six of them.In how many different ways can he arrange his schedule in New York?

A) 20610 B) 24000
C) 20160 D) 21000
 
Answer & Explanation Answer: C) 20160

Explanation:

He can arrange his schedule in 8P6 = 20160 ways

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1 5731
Q:

Goldenrod and No Hope are in a horse race with 6 contestants. How many different arrangements of finishes are there if No Hope always finishes before Goldenrod and if all of the horses finish the race?

A) 720 B) 360
C) 120 D) 640
 
Answer & Explanation Answer: B) 360

Explanation:

Two horses A and B, in a race of 6 horses... A has to finish before B

 

if A finishes 1... B could be in any of other 5 positions in 5 ways and other horses finish in 4! Ways, so total ways 5*4!

 

if A finishes 2... B could be in any of the last 4 positions in 4 ways. But the other positions could be filled in 4! ways, so the total ways 4*4!

 

if A finishes 3rd... B could be in any of last 3 positions in 3 ways, but the other positions could be filled in 4! ways, so total ways 3*4!

 

if A finishes 4th... B could be in any of last 2 positions in 2 ways, but the other positions could be filled in 4! ways, so total ways... 2 * 4! 

 

if A finishes 5th .. B has to be 6th and the top 4 positions could be filled in 4! ways..

 

A cannot finish 6th, since he has to be ahead of B

 

Therefore total number of ways = 5*4! + 4*4! + 3*4! + 2*4! + 4! = 120 + 96 + 72 + 48 + 24 = 360

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Q:

Solve this inequality 3b - 7 < 32?

A) b = 13 B) b < 13
C) b > = 13 D) b < = 13
 
Answer & Explanation Answer: B) b < 13

Explanation:

The given 3b - 7 < 32 can be solved as

3b - 7 < 32

3b < 39

b < 13.

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Filed Under: Simplification
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12 5727
Q:

The least number of complete years in which a sum of money put out at 20% C.I. will be more than doubled is  ?

A) 3 years B) 4 years
C) 2.5 years D) 2 years
 
Answer & Explanation Answer: B) 4 years

Explanation:

P1+20100n > 2P 

 

 

 

Now, (6/5 x 6/5 x 6/5 x 6/5) > 2.

 

 

 

So, n = 4 years.

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Filed Under: Compound Interest
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