Quantitative Aptitude - Arithmetic Ability Questions

Q:

What was the day of the week on 17th June, 1998 ?

A) Monday B) Tuesday
C) Wednesday D) Friday
 
Answer & Explanation Answer: C) Wednesday

Explanation:

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March. April. May. June.
(31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.

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424 73170
Q:

Find out the wrong term in the following number series.

4, 16, 37, 58, 81.

A) 16 B) 37
C) 81 D) 4
 
Answer & Explanation Answer: C) 81

Explanation:

The series follows the following pattern.

 

4

 

16 = 42

 

37 = 12+62

 

58 = 32+72

 

81 52+82.

 

Here every number is based on the digits of previous number. Hence, 81 is the wrong number in the given series.

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5 73149
Q:

Cosec (90 - θ)

 

A) tan θ B) cot θ
C) sec θ D) cos θ
 
Answer & Explanation Answer: C) sec θ

Explanation:
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0 72834
Q:

(5x- 3)(x + 4) - (2x + 5)(3x - 4) = ?

 

A) -x2+10x-8 B) -x2+10x+8
C) x2+10x-8 D) x2+10x+8
 
Answer & Explanation Answer: B) -x2+10x+8

Explanation:
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3 72617
Q:

Find the odd man out?

28, 12, 4, 2, -2

A) -2 B) 2
C) 12 D) 28
 
Answer & Explanation Answer: B) 2

Explanation:

Here the given series 28, 12, 4, 2, -2 follows a pattern that

 

28 28 - 24 = 28 - 16 = 1212 - 23 = 12 - 8 = 44 - 22 = 4 - 4 = 0 (NOT 2)0 - 21 = 0 - 2 = -2

 

Hence, the odd man in the given series is 2.

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4 72530
Q:

(4x - 7)2 = ?

 

A) 4x2 - 56x + 49 B) 4x2 - 14x + 49
C) 16x2 + 14x + 49 D) 16x2 - 56x + 49
 
Answer & Explanation Answer: D) 16x2 - 56x + 49

Explanation:
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2 72391
Q:

Suppose 0 < θ < 90, then for every θ 4 sin2 θ + 1 is greater than or equal to ?

 

A) 2 B) 4 sin θ 
C) 4 cos θ  D) 4 tan θ
 
Answer & Explanation Answer: B) 4 sin θ 

Explanation:
We know that,
Arithmetic mean ≥ Geometric mean
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6 72329
Q:

If S is the midpoint of a straight line PQ and R is a point different from S, such that PR =RQ, then

 

A) ∠PRS = 90° B) ∠QRS = 90°
C) ∠PSR = 90° D) ∠QSR = 90°
 
Answer & Explanation Answer: C) ∠PSR = 90°

Explanation:
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1 72308