Quantitative Aptitude - Arithmetic Ability Questions

Q:

The TrueDiscount on a certain sum of money due 3 years hence is Rs.250 and SimpeInterest on the same sum for same time and same rate is Rs375. Find sum and rate%?

A) (16 + 4/3)% B) (16 +1/3)%
C) (16 + 5/3)% D) (16 + 2/3)%
 
Answer & Explanation Answer: D) (16 + 2/3)%

Explanation:

sum = [(S.I x T.D)/(S.I-T.D)] = Rs. [(375 x 250)/(375-250)] = Rs.750 

Rate = (100 x 375)/(750 x 3) =1623 %

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Q:

A,B,C,D,E,F,G and H are sitting around a circular table facing the centre but not necessarily in the same order. G sits third to the right of C. E is second to the right of G and 4th to the right of H. B is fourth to the right of C. D is not an immediate neighbour of E. A and C are immediate neighbours.

 Which of the following is/are correct ?

A) F is third to the left of B B) F is second to the right of B
C) B is an immediate neighbour of D D) All of the above
 
Answer & Explanation Answer: B) F is second to the right of B

Explanation:

From the given information, the circular arrangement is

EXP.

Here F is second to the right of B and the remaning all are wrong.

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Filed Under: Permutations and Combinations
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Q:

In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by

A) 5.4 m B) 4.5 m
C) 5 m D) 6 m
 
Answer & Explanation Answer: D) 6 m

Explanation:

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Filed Under: Races and Games

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Q:

Evaluate : 3.392-2.6123.39-2.69?

A) 3 B) 4
C) 6 D) 1
 
Answer & Explanation Answer: C) 6

Explanation:

 

It is in the form of a2-b2a-b = a+ba-ba-b = a+b

 

Here a = 3.39   b = 2.61 

 

 = 3.39 + 2.61 = 6.

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Filed Under: Decimal Fractions
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6 5423
Q:

One lady has 2 children, one of her child is boy, what is the probability of having both are boys ?

A) 1/3 B) 1/2
C) 2/3 D) 2/5
 
Answer & Explanation Answer: A) 1/3

Explanation:

In a family with 2 children there are four possibilities:
1) the first child is a boy and the second child is a boy (bb)
2) the first child is a boy and the second child is a girl (bg)
3) the first child is a girl and the second child is a boy (gb)
4) the first child is a girl and the second child is a girl (gg)

But already given that one child is boy. So we have three possibilities of (bb)(bg)(gb).
n(E)= both are boys=BB=1
n(S)= 3
Required probability P = n(E)/n(S) = 1/3.

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Filed Under: Probability
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10 5418
Q:

The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and 15 as remainder. What is the smaller number  ?

A) 270 B) 1270
C) 350 D) 720
 
Answer & Explanation Answer: A) 270

Explanation:

Let the smallest number be x.
Then larger number = (x + 1365)
x + 1365 = 6x + 15
= 5x = 1350
x = 270
Smaller number = 270.

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Filed Under: Problems on Numbers
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Q:

The average score of boys in an examination in a school is 81 and that of the girls is 83 and the average score of the school is 81.8. Then what will be ratio between the number of girls to the number of boys, in the examination?

A) 3:2 B) 2:3
C) 4:3 D) 3:4
 
Answer & Explanation Answer: B) 2:3

Explanation:

Let the number of boys = b

Let the number of girls = g

From the given data,

 

81b + 83g = 81.8(b + g)

81.8b - 81b = 83g - 81.8g

0.8b = 1.2g

b/g = 1.2/0.8 = 12/8 = 3/2

=> g : b = 2 : 3

 

Hence, ratio between the number of girls to the number of boys = 2 : 3.

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Filed Under: Average
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Q:

In an exhibition, Almond bought a painting for Rs. 20000. He later sold it to Olive for Rs. 23000. Olive sold it to Sarah for double the profit percentage that Almond earned. At what price should Sarah sell this painting to earn 8% profit ?

A) Rs. 34,410 B) Rs. 31,184
C) Rs. 29,999 D) Rs. 32,292
 
Answer & Explanation Answer: D) Rs. 32,292

Explanation:

Almond Selling price = CP(1 + P%/100)

=> CP = 20000, SP = 23000

=> 23000 = 20000 (1 + P/100)

=> P% = 100(23000/20000 - 1) = 15

Then, Olive's P% = 30%

SP for Olive = CP for Sarah = 23000(1 + 30/100) = 29900

Now Sarah wants to earn profit of 8%

=> Sp for Sarah = 29900(1 + 8/100)

= Rs. 32,292.

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Filed Under: Profit and Loss
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