6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

What is the true discount on a bill of Rs.2916 due in 3 years hence at 8% C.I.?

A) Rs.600	B) Rs.601
C) Rs.602	D) Rs.603

Answer & Explanation Answer: C) Rs.602

Explanation:

PW = $\frac{A m o u n t}{{(1 + \frac{R}{100})}^{T}}$

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27 5537

Q:

It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

A) Sunday	B) Saturday
C) Friday	D) Wednesday

Answer & Explanation Answer: C) Friday

Explanation:

On 31st December, 2005 it was Saturday.

Number of Odd days from the year 2006 to the year 2009 = (1+1+2+1)=5 days.

$\therefore$ On 31st december 2009, It was Thursday

Thus, on 1st Jan, 2010 it is Friday.

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Filed Under: Calendar

6 5532

Q:

From a deck of 52 cards, a 5 card hand is dealt.How many distinct hands can be formed if there are atleast 2 queens?

A) 103336	B) 120000
C) 108336	D) 108333

Answer & Explanation Answer: C) 108336

Explanation:

The total possible cases would be a 5 card hand with no restrictions : $52 C_{5}$ 5

The unwanted cases are:

no queens(out of 48 non-queens cards we get 5) $48 C_{5}$

only 1 queen(out of 4 queens we get 1,and out of 48 non-queens we get 4) $4 C_{1} * 48 C_{4}$

Therefore, $52 C_{5} - (48 C_{5} + 4 C_{1} * 48 C_{4}) = 108336$

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Filed Under: Permutations and Combinations

2 5532

Q:

In an exhibition, Almond bought a painting for Rs. 20000. He later sold it to Olive for Rs. 23000. Olive sold it to Sarah for double the profit percentage that Almond earned. At what price should Sarah sell this painting to earn 8% profit ?

A) Rs. 34,410	B) Rs. 31,184
C) Rs. 29,999	D) Rs. 32,292

Answer & Explanation Answer: D) Rs. 32,292

Explanation:

Almond Selling price = CP(1 + P%/100)

=> CP = 20000, SP = 23000

=> 23000 = 20000 (1 + P/100)

=> P% = 100(23000/20000 - 1) = 15

Then, Olive's P% = 30%

SP for Olive = CP for Sarah = 23000(1 + 30/100) = 29900

Now Sarah wants to earn profit of 8%

=> Sp for Sarah = 29900(1 + 8/100)

= Rs. 32,292.

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Filed Under: Profit and Loss
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11 5529

Q:

Chennai express left Hyderabad for Chennai at 14 : 30 hours, travelling at a speed of 60 kmph and Charminar Express left Hyderabad for Chennai on the same day at 16 : 30 hours, travelling at a speed of 80 kmph. How far away from Hyderabad will the two trains meet?

A) 360 kms	B) 480 kms
C) 520 kms	D) 240 kms

Answer & Explanation Answer: B) 480 kms

Explanation:

Now, the distance covered by Chennai express in 2 hrs = 60 x 2 = 120 kms

Let the Charminar Express takes 't' hrs to catch Chennai express

=> 80 x t = 60 x (2 + t)

=> 80 t = 120 + 60t

=> t = 6 hrs

Therefore, the distance away from Hyderabad the two trains meet = 80 x 6 = 480 kms.

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Filed Under: Time and Distance
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10 5516

Q:

If watches bought at prices ranging from Rs. 200 to Rs. 350 are sold at prices ranging from Rs. 300 to Rs. 425. What is the greatest possible profit that might be made in selling nine watches ?

A) Rs. 1800	B) Rs. 2000
C) Rs. 2025	D) Rs. 1750

Answer & Explanation Answer: C) Rs. 2025

Explanation:

Profit would be maximum if watches are brought for Rs. 200 and sold for Rs. 425
Profit = Rs. (425 - 200) = Rs. 225
Profit of 9 watches = Rs. 225 x 9 = Rs.2,025.

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Filed Under: Profit and Loss
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5 5514

Q:

Find the sum to 200 terms of the series 2 + 5 + 7 + 6 + 12 + 7 + ....

A) 30,400	B) 30,200
C) 34,600	D) 38,400

Answer & Explanation Answer: A) 30,400

Explanation:

we can treat every two consecutive terms as one.
So, we will have a total of 100 terms of the nature:
(2 + 5) + (7 + 6) + (12 + 7).... => 7, 13, 19,....

We know the sum of n terms $\frac{n (n + 1)}{2}$

Now, a= 7, d=6 and n=100
Hence the sum of the given series is
S= 100/2 x[2 x 7 + 99 x 6]
=> 50[608]
=> 30,400.

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Filed Under: Numbers
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5 5514

Q:

A shopkeeper sells two articles at Rs.1000 each, making a profit of 30% on the first article and a loss of 20% on the second article. Find the net profit or loss that he makes ?

A) 0.85 %	B) 0.95 %
C) 1.0 %	D) 1.3 %

Answer & Explanation Answer: B) 0.95 %

Explanation:

SP of first article = 1000
Profit = 30%
CP = (SP)x[100/(100+P)] = 10000/13

SP of second article = 1000
Loss = 20%
CP = (SP)x[100/(100-L)] = 5000/4 = 1250

Total SP = 2000

Total CP = 10000/13 + 1250 = 2019.23

CP is more than SP, he makes a loss.

Loss = CP-SP = 2019.23 - 2000 = 19.23
Loss Percent = [(19.23)/(2019.23)]x100 = 0.95 %.

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Filed Under: Profit and Loss
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6 5512

Quantitative Aptitude - Arithmetic Ability Questions

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