Quantitative Aptitude - Arithmetic Ability Questions

a. P's investment = (80000 x 6 + 60000 x 6) = 840000 for 1 month.

b & c. Q's investment = 80% of Rs. 60000 for 8 months.

= Rs.(48000 x 8) for 1 month = 384000 for 1 month

P : Q = 840000 : 384000 = 35 : 16.

But, the total profit is not given, so data is inadequate.

Annual salary of Arun = 7,68,000 Rs.
Monthly salary = 7,68,000/12 = Rs. 64,000
Spending on children = Rs. 12,000
Rest = 52,000
1/13th of the rest = 52,000/13 = Rs. 4,000 is spent on food.
Rs. 8,000 is spent in mutual funds.
Monthly savings = 64,000 - (12,000+4,000+8,000) = Rs. 40,000.

Let the distance he covered each way = d kms

According to the question,

d/45 - d/50 = 1

=> d = 450 kms.

Hence, the total distance he covered in his way = d + d = 2 d = 2 x 450 = 900 kms.

If a number ends with 5, 0 then the number will be divisible by 5
Here only 5 is present, end place will be fixed by 5 so, 

n(S) = C252 = 1326

 Let  A = event of getting both red cards

and B = event of getting both queens

then A∩B = event of getting two red queens

n(A) = C226 = 325,   n(B) = C24 = 6

 n(A∩B)=C22=1

 ∴ PA=3251326, PB = 61326

 PA∩B=11326

∴P ( both red or both queens) = PA∪B

= PA+PB-PA∩B=3251326+1221-11326=55221

Let 'Y' be the youngest player.

The last song can be sung by any of the remaining 3 players. The first 3 players can sing the song in (3!) ways.

The required number of ways = 3(3!) = 4320.

P(4,3)= P34= 24

Total numbers in die=6

P(multiple of 2)=1/2

P(multiple of 5)=1/6

P(multiple of 2 or 5)=2/3