Quantitative Aptitude - Arithmetic Ability Questions

Q:

Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5 ?

A) 2/3 B) 1/2
C) 7/8 D) 4/5
 
Answer & Explanation Answer: B) 1/2

Explanation:

Multiples of 3 below 20 are 3, 6, 9, 12, 15, 18
Multiples of 5 below 20 are 5, 10, 15, 20
Required number of possibilities = 10
Total number of possibilities = 20
Required probability = 10/20 = 1/2.

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Filed Under: Probability
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Q:

A man wills 25% of his wealth to charity and rest to his family. What percent of the wealth willed to charity does the family get?

A) 200 B) 33.3
C) 300 D) 25
 
Answer & Explanation Answer: C) 300

Explanation:
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Filed Under: Percentage
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Q:

Due to increase of 33.33% in the price of apples, a customer can purchase 4 apples less for Rs 16. What is the original price (in paise) of an apple?

A) 100 B) 125
C) 150 D) 400/3
 
Answer & Explanation Answer: A) 100

Explanation:
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Q:

If you write down all the numbers from 1 to 100, then how many times do you write 4 ?

A) 11 B) 20
C) 17 D) 14
 
Answer & Explanation Answer: B) 20

Explanation:

4, 14, 24, 34, 44, 54, 64, 74, 84, 94 => has 11 number of (4's)
40, 41, 42, 43, 45, 46, 47, 48, 49 => has 9 number of (4's)
So, totally (11 + 9 = 20) number of 4's in 1 to 100.

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Q:

A train 150 m long is running with a speed of 68 km/h. In what time will it pass a man who is running at 8 km/ h in the same direction in which the train is going?

A) 8 sec B) 8.5 sec
C) 9 sec D) 9.5 sec
 
Answer & Explanation Answer: C) 9 sec

Explanation:

Relative speed = 68-8 = 60 km/hr = 60 X 5 / 18 m/s = 50/3 m/s

Total distance = 150 m

Time taken to pass a man running in same direction = 150 X 3/50 = 9 seconds

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Filed Under: Problems on Trains
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Q:

12% of 70,000 is

A) 8400 B) 7200
C) 6000 D) 5600
 
Answer & Explanation Answer: A) 8400

Explanation:

12% of 70,000

=> 12 x 70,000/100

=> 8400

 

Hence, 12% of 70,000 = 8,400

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Q:

For S = $21,000, payments (R) of $1500 at the end of each 6-month periodi= 10% compounded semi-annually. Find the minimum number of payments to accumulate 21,000.

A) 10 B) 11
C) 12 D) 13
 
Answer & Explanation Answer: B) 11

Explanation:

S=R[(1+i)^n-1)/i]

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Q:

The series of differences between consecutive prime numbers is represented as Cp1, Cp2, Cp3, .... Cpn , Whare Cp1 is the difference between the second and the first prime number. Find the sum of series when n = 23, given that the 23rd prime number is 83 ? 

A) 87 B) 81
C) 83 D) 85
 
Answer & Explanation Answer: A) 87

Explanation:

Cp1 = p2 - p1 ,
Cp2 = p3 - p2
..
..
..
Cp23 = p24 - p23
Sum of series = (p2-p1) + (p3-p2) + .....(p23-p22) + (p24-p23)
All terms get cancelled, except p1 = 2 and p24 = 89
So Sum = -p1 + p24
Sum of series = -2 + 89 = 87

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Filed Under: Problems on Numbers
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