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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

For S = $21,000, payments (R) of $1500 at the end of each 6-month periodi= 10% compounded semi-annually. Find the minimum number of payments to accumulate 21,000.

A) 10 B) 11
C) 12 D) 13
 
Answer & Explanation Answer: B) 11

Explanation:

S=R[(1+i)^n-1)/i]

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Filed Under: Compound Interest
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0 4523
Q:

What is the square root of (√5 + 2)/(√5 – 2)?

 

A) √5 – √4   B) √5 + 2  
C) 5 + √2   D) 7
 
Answer & Explanation Answer: B) √5 + 2  

Explanation:
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Filed Under: Square Roots and Cube Roots
Exam Prep: Bank Exams

1 4515
Q:

The series of differences between consecutive prime numbers is represented as Cp1, Cp2, Cp3, .... Cpn , Whare Cp1 is the difference between the second and the first prime number. Find the sum of series when n = 23, given that the 23rd prime number is 83 ? 

A) 87 B) 81
C) 83 D) 85
 
Answer & Explanation Answer: A) 87

Explanation:

Cp1 = p2 - p1 ,
Cp2 = p3 - p2
..
..
..
Cp23 = p24 - p23
Sum of series = (p2-p1) + (p3-p2) + .....(p23-p22) + (p24-p23)
All terms get cancelled, except p1 = 2 and p24 = 89
So Sum = -p1 + p24
Sum of series = -2 + 89 = 87

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Filed Under: Problems on Numbers
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4 4512
Q:

The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is:

A) 3years B) 2years
C) 4years D) 6years
 
Answer & Explanation Answer: B) 2years

Explanation:

Amount = Rs. (30000 + 4347) = Rs. 34347.

Let the time be n years.

Then, 30000*(1+7/100)^n=34347

n= 2 years

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Filed Under: Compound Interest
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0 4510
Q:

Due to increase of 33.33% in the price of apples, a customer can purchase 4 apples less for Rs 16. What is the original price (in paise) of an apple?

A) 100 B) 125
C) 150 D) 400/3
 
Answer & Explanation Answer: A) 100

Explanation:
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Filed Under: Percentage
Exam Prep: Bank Exams

10 4505
Q:

12% of 70,000 is

A) 8400 B) 7200
C) 6000 D) 5600
 
Answer & Explanation Answer: A) 8400

Explanation:

12% of 70,000

=> 12 x 70,000/100

=> 8400

 

Hence, 12% of 70,000 = 8,400

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Filed Under: Percentage
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3 4502
Q:

There are four consecutive even integers. Sum of the reciprocals of the first two number is (11/60). Find the reciprocal of third largest number of the series.

A) 1/12 B) 2/14
C) 1/14 D) 2/13
 
Answer & Explanation Answer: C) 1/14

Explanation:

Ans. C.
Let 4 consecutive even numbers are x, x+ 2, x+ 4, x+ 6
According to the question -
1/x + 1/x+2 = 11/60
x+2+x/ x(x+2) = 11/60
2(x+1)/x^2 + 2x = 11/60
120x + 120 = 11x 2 + 22x
11x 2 - 98x – 120 = 0
So ,
X = -24/22 , 10
X = -12/11 , 10
So, the numbers will be 10,12,14,16.
Hence,
Third largest number = 14
Reciprocal of third number = 1/14

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Filed Under: Numbers
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2 4499
Q:

Find the remainder when 629 is divided by 5 ?

A) 0 B) 1
C) 3 D) 5
 
Answer & Explanation Answer: B) 1

Explanation:

All powers of 6 has 6 in units place so answer will definitely be 1.

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Filed Under: Numbers
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