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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

A man invested an amount at the rate of 10% p.a. on compound interest and after two years he again invested half of the initial amount. If man got Rs. 457.2 Rs. as interest after three years, find the amount received by man after three years, if he invested same amount on simple interest at rate of 15% p.a.? 

A)  1740 Rs.  B)  1760 Rs. 
C)  1720 Rs.  D)  1780 Rs. 
 
Answer & Explanation Answer: A)  1740 Rs. 

Explanation:

Let man invested Rs. A And, after two years amount invested = (A +

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Filed Under: Simple Interest
Exam Prep: AIEEE , Bank Exams , CAT

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Q:

Find the principal which yields $25,000 when invested at 3% annually for 20 years.

A) 13841.89 B) 14821
C) 13468 D) 57389
 
Answer & Explanation Answer: A) 13841.89

Explanation:

P=F1+in

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

1 4238
Q:

What is the Formula for Volume?

Answer

 The formula to find the volume is given by just multiplying Length, Breadth and Height of that object. 


 Thus, V = L x B X H  



Volume Formulae :   


1. Volume of Cube of side 's' = s x s x s = s3  cubic units.   


2. Volume of Cylinder = πR2h cubic units.  


[Where R is Radius and h is height]

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Subject: Volume and Surface Area Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

13 4238
Q:

1.52 x 0.0225 = ?

A) 0.0375 B) 0.3375
C) 3.275 D) 32.75
 
Answer & Explanation Answer: B) 0.3375

Explanation:
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Filed Under: Square Roots and Cube Roots

14 4238
Q:

Consider a regular hexagon ABCDEF. Two towers are situated at B and C. The angle of elevation from A to the top of the tower at B is 30 deg, and the angle of elevation to the top of the tower at C is 45 deg. What is the ratio of the height of towers at B and C?

A) 1:√3 B) 1:3
C) 1:2 D) 1:2√3
 
Answer & Explanation Answer: B) 1:3

Explanation:

Let the side of regular hexagon be ‘a’

Let height of the tower 1 be h1 and tower 2 be h2

Height of tower 1 = h1 = (distance between A and B)* (tan 30o)= a.1/√3

Distance between A and C = 2*√3.a/2= √3a

Height of tower 2 = h2 = (distance between A and C)* (tan 45o) = √3a.1 = √3a

Ratio of height of towers at B and C respectively =a/√3/√3a = 1/3.

 

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Filed Under: Simplification
Exam Prep: Bank Exams

3 4237
Q:

Which of the following relation is CORRECT?

 

I. (√15 + √7) < (2√22)

II. (√17 + √5) < (√20 + √2)

 

A) Only I B) Only II
C) Neither I nor II D) Both I and II
 
Answer & Explanation Answer: A) Only I

Explanation:
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Filed Under: Square Roots and Cube Roots
Exam Prep: Bank Exams

0 4236
Q:

∆XYZ is right angled at Y. If m∠Z = 60°, then find the value of (cotX - 1/3).

A) (3√3-1)/3 B) (2√3-√6)/2√2
C) -5/3 D) (2-√3)/2√3
 
Answer & Explanation Answer: A) (3√3-1)/3

Explanation:
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Filed Under: Area
Exam Prep: Bank Exams

0 4223
Q:

Arun is a cashew merchant in Telangana. He has cashews in sealed wooden boxes of 10kg each. The price of the cashew increases by Rs.20 per kg for every year, but at the same time, 10% of the cashews are eaten by rodents every year. If the price of a 1 kg of fresh cashew is Rs.120, what is the change in his profits if he sells a sealed box after one year of storage, rather than selling it fresh ? (In Rs.)

A) Rs. 60 B) Rs. 54
C) Rs. 80 D) Rs. 75
 
Answer & Explanation Answer: A) Rs. 60

Explanation:

Price of 1kg fresh cashew = Rs.120
Therefore, price of 10kg = Rs.120 x 10 = Rs.1200

10% of 10kg which eaten by rodents = 10 x 10/100 = 1kg.

So, End of Year he had 10kg - 1kg = 9kg

So, he sells that 9kg with Rs.20 per kg profit = 9 x 140 = 1260.

He buy 10kg wooden box with cashew for Rs.1200 and sell that for Rs. 1260

So, profit = 1260 - 1200 = Rs.60 more money he get.

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

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