Quantitative Aptitude - Arithmetic Ability Questions

By replacing the “?” with “x”

(12.5×14÷8.75) x (100/100) + 42 = 50 + X

(125*140)/875 + 42 = 50 + X

140/7 + 42 = 50 + X

20 + 42 = 50 + X

62 = 50 + X

X = 62 - 50

X = 12

Commission up to 10000 = 10000x9100 = 900 

Again after 10000, 

              Commission    :   Bonus 

                           9       :   3 

                         3x        :   x

 Therefore,   Bonus = 1380-900×14 = Rs. 120

45/100×400+√?=56/100 ×750 -40/100 ×350

180 + √? = 420 - 140 180 + √? = 280 √? = 280 - 180 √? = 100 ? = 1002 ? = 10000

Weight of the teacher = (35.4 x 25 - 35 x 24) kg = 45 kg.

At 3 O'clock, Minute hand is at 12 while the Hour hand is at 3. Again the minute hand has to sweep through ( 30 x 5 ) ie 150° for reaching the figure 5 to show 25 mins. 

Simultaneously the Hour hand will also rotate for 25 mins. Thus starting from the mark, 3 the hour hand will cover an angle = (25 x 30) / 60 = 12.5° 

Hence, Angle between Hour and the Minute hand = ( 60 - 12.5 ) = 47.5°

Let 4A = 6B = 1OC = k. Then, A = k/4, B = k/6,  and C =k/10 .

A : B :C = k/4 : k/6 : k/10 = 15 : 10 : 6.

Hence, C's share (4650 *  6/31) = Rs, 900.

We know that 

$$\begin{gathered} 40% = 40100 = 25 \\ ⇒25 x 244 x ? = 48 \\ ? = 48 x 5 x 42 x 24 = 20 \end{gathered}$$