Quantitative Aptitude - Arithmetic Ability Questions

Q:

Use continuity to evaluate the limit.

limx128+x8+x

 

A) 1 B) 2
C) 4 D) 0
 
Answer & Explanation Answer: A) 1

Explanation:

Since, we have that,

The numerator and denominator is (8+x), which is a polynomial is continuous for all the real numbers i.e. for all x belonging to .

Thus, the limit exists and is given by,

limx128+x8+x = 8+128+12= 1.

 

 

 

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0 54481
Q:

The length of a diagonal in cms of a rectangle of length 5 cm and width 6 cm is

 

A) 61 B) ±61
C) 11 D) ±11
 
Answer & Explanation Answer: A) 61

Explanation:
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3 54432
Q:

If p & q = p2 + 4pq - q2 then find the value of (3 & 6) + (4 & 5).

 

A) 98 B) 106
C) 116 D) 126
 
Answer & Explanation Answer: C) 116

Explanation:
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1 54428
Q:

Find the odd man out?

61, 66, 83, 121, 185

A) 185 B) 121
C) 83 D) 66
 
Answer & Explanation Answer: B) 121

Explanation:

Given number series is 61, 66, 83, 121, 185

Here the given series follows a pattern that,

 

6161 + 22 + 1 = 6666 + 42 + 1 = 8383 + 62 + 1 = 120 (not 121)120 + 82 + 1 = 185

 

 

Hence, the odd man in the given series is 121.

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3 54337
Q:

What will come in place of the question mark in the series below?

2, 17, 89, 359, 1079, ?

A) 2137 B) 2121
C) 2377 D) 2159
 
Answer & Explanation Answer: D) 2159

Explanation:

Ans. 
17 = 2 x 6 + 5
89 = 17 x 5 + 4
359 = 89 x 4 + 3
1079 = 359 x 3 + 2
? = 1079 x 2 + 1, i.e. ? = 2159

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3 54260
Q:

In the following question, select the odd letter/letters from the given alternatives.

 

A)   RMHC     B)    XSNI      
C)   YTOJ       D)    ZVQL  
 
Answer & Explanation Answer: D)    ZVQL  

Explanation:
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1 54231
Q:

If a2 + 1a2 = 3, then a3 + 1a3 = ?

 

A) 3√5 B) 2√5
C) 2√3 D) 3√3
 
Answer & Explanation Answer: B) 2√5

Explanation:
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0 54121
Q:

When 0.232323.... is converted into a fraction , then the result is 

 

A) 1/5 B) 2/9
C) 23/99 D) 23/100
 
Answer & Explanation Answer: C) 23/99

Explanation:

0.232323...=0.23 =2399

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