Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

A 12 m long wire is cut into two pieces, one of which is bent into a circle and the other into a square enclosing the circle. What is the radius of the circle?

A) 12/π+4 B) 6/π+4
C) 3/π+4 D) 6/π+2√2
 
Answer & Explanation Answer: B) 6/π+4

Explanation:
As it is clear that 2r = a where a is the side of the square and
R is the radius of circle
It is given that 2πr + 4a = 12
a = 12/(π+4)
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Q:

What is the value of {(sin 4x + sin 4y) [(tan 2x – 2y)]}/(sin 4x – sin 4y)?

A) tan 2 (2x + 2y) B) tan2
C) cot (x – y) D) tan (2x + 2y)
 
Answer & Explanation Answer: D) tan (2x + 2y)

Explanation:
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Q:

If cosec ­4π/3 = x, then the value of x is

A) √2 B) 2/√3
C) √2 D) -1/√3
 
Answer & Explanation Answer: B) 2/√3

Explanation:
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Q:

PQR is right angled at Q. If sinP = 12/13, then what is the value of tanR?

A) 5/13 B) 13/5
C) 13/12 D) 5/12
 
Answer & Explanation Answer: D) 5/12

Explanation:
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Q:

A complete factorisation of x4 + 64 is

A) (x2 + 8)2 B) (x2 + 8)(x2 - 8)
C) (x2 - 4x + 8)(x2 -4x - 8) D) (x2 + 4x + 8)(x2 - 4x + 8)
 
Answer & Explanation Answer: D) (x2 + 4x + 8)(x2 - 4x + 8)

Explanation:
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Q:

In the question given below, two equations are provided. Solve the equations and establish the relationship between x and y

I. 2x2-13x-189=0 II. 2y2-3y-189=0

A) x>y B)  x≥y
C)  x<y D) x≤y
 
Answer & Explanation Answer:

Explanation:

I. 2x2 - 13x - 189 = 0 2x2 - 27x + 14x - 189 = 0 x(2x - 27) + 7(2x - 27) = 0 x = -7, 27/2

II. 2y2 - 3y - 189 = 0 2y2 - 21y + 18y - 189 = 0 y(2y - 21) + 9(2y - 21) = 0 y = -9, 21/2

When x, as well as y, have both positive and negative values then no relationship can be established between them because if we consider x to be positive then the negative value of y will be lesser than x. If we consider x to be negative then positive value of y will be greater than x.

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Q:

In each question two equations numbered I and II are given,you haveto solve both the equation and choose the correctanswer.

I. 5x2+ 28x = -15II. 3y2+ 11y + 6 = 0

A) X > Y B) X ≥ Y
C) X < Y D) X ≤ Y
 
Answer & Explanation Answer:

Explanation:

5x^2+ 28x = -15x = (-3/5, -5)

II. 3y^2+ 11y + 6 = 0y = (-3, -2/3)

So Relationship cannot be established

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Q:

ΔABC is right angled at B. If m∠A = 45°, then find the value of (cosecC + 1/√3).

A) (3√2+1)/3 B) (2+√3)/2
C) 5/√3 D) (√6+1)/√3
 
Answer & Explanation Answer: D) (√6+1)/√3

Explanation:
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