Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If (1 - cos2A) = x, then the value of x is

A) cosecA B) sinA
C) tanA D) secA
 
Answer & Explanation Answer: B) sinA

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Q:

If x = (√5) + 1 and y = (√5) – 1, then what is the value of (x2/y2) + (y2/x2) + 4[(x/y) + (y/x)] + 6?

A) 31 B) 23√5
C) 27√5 D) 25
 
Answer & Explanation Answer: D) 25

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Q:

If sin - 4π/3 = x, then the value of x is

A) -2 B) -2/√3
C) √3/2 D) √2
 
Answer & Explanation Answer: C) √3/2

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Q:

If 4(2x - ­4) -­ 2 > 3x -­ 1 ≥ 4x - ­7, then x can take which of the following values?

A) 7 B) 6
C) 2 D) 0
 
Answer & Explanation Answer: B) 6

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Q:

If tanA -­ tanB = X, then the value of X is

A) (tanA + tanB)/(1 -­ tanAtanB) B) (tanA + tanB)/(1 + tanAtanB)
C) (tanA -­ tanB)/(1-­ tanAtanB) D) (tanA -­ tanB)/(1 + tanAtanB)
 
Answer & Explanation Answer: D) (tanA -­ tanB)/(1 + tanAtanB)

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Q:

If x = 3+13, then the value of x-12642x-1x-233 is

A) √3/6 B) 2√3/6
C) 5/6 D) 2/3
 
Answer & Explanation Answer: C) 5/6

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Q:

What is the value of √2 Sec 45 - Tan 30?

A) (2√3 - 1)/3 B) (√3 - 1)/√3
C) (2√3 - 1)/√3 D) (√3 - 1)/3
 
Answer & Explanation Answer: C) (2√3 - 1)/√3

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Q:

If cot(A/2) = x, then x is equal to

A) tanA/(1 + secA) B) 1/(secA + cotA)
C) tanA/(1 + cosecA) D) 1/(cosecA ­- cotA)
 
Answer & Explanation Answer: D) 1/(cosecA ­- cotA)

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