# Alphabet Test Questions

A) BMS | B) LBT |

C) IJF | D) PID |

Explanation:

$L\stackrel{+3}{\to}B\stackrel{-1}{\to}T$

$I\stackrel{+3}{\to}J\stackrel{-1}{\to}F$

$P\stackrel{+2}{\to}I\stackrel{-1}{\to}D$

$B\stackrel{+3}{\to}\stackrel{-1}{\to}S$

Therefore, PID is not in the form of other patterns.

A) X | B) W |

C) I | D) H |

Explanation:

In the given alphabet, last but one letter of alphabet is Y.

10th letter to the left of Y is O

8th letter to the right of O is W

A) 3 | B) 4 |

C) 5 | D) 6 |

Explanation:

Looking into the alphabets there are six such pairs namely ON, HONE, ST, TRAPHO, TRAPHON, RAP.

1. ON - NO

2. HONE - EFGH

3. ST - ST

4. TRAPHO - OPQRST

5. TRAPHON - NOPQRST

6. RAP - PQR

A) Actuate | B) Accumulate |

C) Acquit | D) Achieve |

Explanation:

First letters are common. Second letters are:b, c, c, c, c. One of the four words having c is the last word. Let us see the third letters now ,there are: t, c, q, h. Clearly t is the last. Hence Actuate is the last word.

A) ZH | B) IB |

C) NR | D) QH |

Explanation:

The first letter follows +1, +2, +3, +4, ....

The second letter follows +2, +3, +4, +5,....

A) M | B) X |

C) O | D) I |

Explanation:

Specified letters from the left are N and O , and the letter from the right is I.

With these letters , according to the conditions given in the question , one Word ONION can be formed. Clearly , first letter of this word is O.

A) R | B) I |

C) J | D) S |

Explanation:

Find out the positions of both the letters from the left and divide the sum of the positions of both the letters from the left by 2. Here 13+23=36. Now divide 36 by 2 , i.e 18. Hence R is the required letter.