0
Q:

Kramer borrowed $4000 from George at an interest rate of 7% compounded semiannually. The loan is to be repaid by three payments. The first payment, $1000, is due two years after the date of the loan. The second and third payments are due three and five years, respectively, after the initial loan. Calculate the amounts of the second and third payments if the second payment is to be twice the size of the third payment.

A) 1389 B) 1359
C) 1379 D) 1339.33

Answer:   D) 1339.33



Explanation:

Given:j=7% compounded semiannually making m=2 and i = j/m= 7%/2 = 3.5%
Let x represent the third payment. Then the second payment must be 2x.
PV1,PV2, andPV3 represent the present values of the first, second, and third payments.

Since the sum of the present values of all payments equals the original loan, then
PV1 + PV2  +PV3  =$4000 -------(1)

PV1   =FV/(1 + i)^n  =$1000/(1.035)^4=  $871.44

At first, we may be stumped as to how to proceed for
PV2 and PV3. Let’s think about the third payment of x dollars. We can compute the present value of just $1 from the x dollars

pv=1/(1.035)^10=0.7089188

PV2   =2x * 0.7089188 = 1.6270013x
PV3   =x * 0.7089188=0.7089188x
Now substitute these values into equation ➀ and solve for x.
$871.442 + 1.6270013x + 0.7089188x  =$4000

2.3359201x  =$3128.558

x=$1339.326
Kramer’s second payment will be 2($1339.326)  =$2678.65, and the third payment will be $1339.33

Q:

A certain sum is invested for 2 years in scheme M at 20% p.a. compound interest (compounded annually), Same sum is also invested for the same period in scheme N at k% p.a. simple interest. The interest earned from scheme M is twice of that earned from scheme N. What is the value of k?

A) 7 B) 11
C) 9 D) 13
 
Answer & Explanation Answer: B) 11

Explanation:

Interest earned in scheme M =   

P1 + 201002  - 1  = 11P25

Interest earned in scheme N =  

P x k x 2100 = Pk50

 

Now, from the given data,

 

11P25 = 2 x Pk50

k = 11

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0 57
Q:

A sum is equally invested in two different schemes on CI at the rate of 15% and 20% for two years. If interest gained from the sum invested at 20% is Rs. 528.75 more than the sum invested at 15%, find the total sum?

A) Rs. 7000 B) Rs. 4500
C) Rs. 9000 D) Rs. 8200
 
Answer & Explanation Answer: C) Rs. 9000

Explanation:

Let Rs. K invested in each scheme

Two years C.I on 20% = 20 + 20 + 20x20/100 = 44%

Two years C.I on 15% = 15 + 15 + 15x15/100 = 32.25%

Now,

(P x 44/100) - (P x 32.25/100) = 528.75

=> 11.75 P = 52875

=> P = Rs. 4500

 

Hence, total invested money = P + P = 4500 + 4500 = Rs. 9000.

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7 1116
Q:

What is the interest rate per annum, if a sum of money invested at compound interest amount to Rs. 2400 in 3 years and in 4 years to Rs. 2,520?

A) 3.5% B) 4%
C) 5% D) 6.5%
 
Answer & Explanation Answer: C) 5%

Explanation:

Let 'R%' be the rate of interest

From the given data,

25202400 = 1 + R10041 + R10031 + R100 = 6360R = 5

 

Hence, the rate of interest R = 5% per annum.

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4 814
Q:

A sum of Rs. 8,000 is deposited for 3 years at 5% per annum compound interest (compounded annually). The difference of interest for 3 years and 2 years will be

 

A) Rs. 387 B) Rs. 441
C) Rs. 469 D) Rs. 503
 
Answer & Explanation Answer: B) Rs. 441

Explanation:

Given principal amount = Rs. 8000

Time = 3yrs

Rate = 5%

C.I for 3 yrs = 8000 x 105100 x 105100 x 105100 - 8000= Rs. 1261

 

Now, C.I for 2 yrs = 8000 x 105100 x 105100= Rs. 820 

 

Hence, the required difference in C.I is 1261 - 820 = Rs. 441

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4 810
Q:

Simple interest on a certain sum at 7% per annum for 4 years is Rs. 2415. What will be the compound interest on the same principal at 4% per annum in two years?

A) Rs. 704 B) Rs. 854
C) Rs. 893 D) Rs. 914
 
Answer & Explanation Answer: A) Rs. 704

Explanation:

We know that,

S.I. = PTR100 P = S.I x 100T x RAnd also,C.I = P1 + R100n- 1

From given data, P = Rs. 8625

Now, C.I  = 86251+41002-1= 862526252-1= 8625676625-1= 8625 x 51625C.I = Rs. 703.80

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3 1142
Q:

Find the compound interest on Rs. 6,500 for 4 years if the rate of interest is 10% p.a. for the first 2 years and 20% per annum for the next 2 years? 

A) Rs. 3845 B) Rs. 4826
C) Rs. 5142 D) Rs. 4415
 
Answer & Explanation Answer: B) Rs. 4826

Explanation:

We know the formula for calculating

The compound interest C = P1 + r100n - 1 where P = amount, r = rate of interest, n = time

Here P = 5000, r1 = 10, r2 = 20

Then C = 65001 + 101002 x 1 + 201002 - 1= 6500 x 18562500= 65 x 185625

C = Rs. 4826.

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10 1073
Q:

What is the difference between the compound interests on Rs. 5000 for 11⁄2 years at 4% per annum compounded yearly and half-yearly?

A) Rs. 1.80 B) Rs. 2.04
C) Rs. 3.18 D) Rs. 4.15
 
Answer & Explanation Answer: B) Rs. 2.04

Explanation:

Compound Interest for 1 12 years when interest is compounded yearly = Rs.(5304 - 5000)


Amount after 112 years when interest is compounded half-yearly 


Compound Interest for 1 12 years when interest is compounded half-yearly = Rs.(5306.04 - 5000)


Difference in the compound interests = (5306.04 - 5000) - (5304 - 5000)= 5306.04 - 5304 = Rs. 2.04

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6 1128
Q:

The difference between simple interest and compound interest of a certain sum of money at 20% per annum for 2 years is Rs. 56. Then the sum is :

A) Rs. 3680 B) Rs. 2650
C) Rs. 1400 D) Rs. 1170
 
Answer & Explanation Answer: C) Rs. 1400

Explanation:

We know thatThe Difference between Compound Interest and Simple Interest for n years at R rate of interest is given by C.In - S.In = PR100n

Here n = 2 years, R = 20%, C.I - S.I = 56

56 = P201002=> P = 56 x 52=> P = 56 x 25=> P = Rs. 1400

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13 1143