Exams Questions and Answers

Q:

Find the missing number in series 1 4 27

A) 125	B) 625
C) 404	D) 256

Answer & Explanation Answer: D) 256

Explanation:

It follows the rule that

1

2x2

3x3x3

4x4x4x4

5x5x5x5x5

So the missing number is 4x4x4x4 = 256.

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Filed Under: Number Series
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Q:

A train covered k km at 40 kmph and another 2k km at 20 kmph. Find the average speed of the train in covering the entire 3k km ?

A) 28 kmph	B) 24 kmph
C) 26 kmph	D) 32 kmph

Answer & Explanation Answer: B) 24 kmph

Explanation:

Total time taken = k/40 + 2k/20 hours

= 5k/40 = k/8 hours

Average speed = 3k/(k/8) = 24 kmph.

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Filed Under: Problems on Trains
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6 8344

Q:

In what time will Rs.1000 become Rs.1331 at 10% per annum compounded annually?

A) 2years	B) 3years
C) 4years	D) 5years

Answer & Explanation Answer: B) 3years

Explanation:

Principal = Rs.1000;

Amount = Rs.1331;

Rate = Rs.10%p.a.

Let the time be n years.Then

[1000(1+10/100)Λn;]

= 1331.

= (1331/1000)

= (11/10)³

Therefore n = 3 years.

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Filed Under: Compound Interest
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3 8341

Q:

Hemavathi gets 3 marks for each right sum and loses 2 marks for each wrong sum. He attempts 35 sums and obtains 60 marks. The number of sums attempted correctly is ?

A) 23	B) 24
C) 25	D) 26

Answer & Explanation Answer: D) 26

Explanation:

Let, Hema attempted 'k' sum correctly, then

k x 3 -2 x(35-k) = 60
5k = 130
k = 26

so 26 correct sums.

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Filed Under: Simplification
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9 8338

Q:

$i f \log \frac{a}{b} + \log \frac{b}{a} = \log (a + b), t h e n$

A) a + b = 1	B) a - b = 1
C) a = b	D) ab=1

Answer & Explanation Answer: A) a + b = 1

Explanation:

$i f \log \frac{a}{b} + \log \frac{b}{a} = \log (a + b), t h e n$

$\log (a + b) = \log (\frac{a}{b} \times \frac{b}{a}) = \log 1$

so, a+b=1

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Filed Under: Logarithms
Exam Prep: Bank Exams
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40 8337

Q:

In what time will Rs. 3300 becomes Rs. 3399 at 6% per annum interest compounded half-yearly ?

A) Quarter months	B) Half year
C) 2 years	D) 1 year

Answer & Explanation Answer: B) Half year

Explanation:

3300 ----- 3% ↑ (1st time interval, 99) → 3399.

Here, time interval is given as half-yearly i.e. 6 months.

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Filed Under: Compound Interest
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Q:

A word arrangement machine, When given an input line of words, rearranges it in every step following a certain rule. Following is an illustration of an input line of words and various steps of rearrangement.

Input: gone are take enough brought station
Step 1: take gone are enough brought station
Step 2: take are gone enough brought station
Step 3: take are station gone enough brought
Step 4: take are station brought gone enough
And Step 4 is the last step for this input. Now, find out an appropriate step in the following question following the above rule.

Question:
Input: car on star quick demand fat
What will be the third step for this input ?

A) star car demand quick on fat	B) star quick car demand on fat
C) star car quick demand on fat	D) none of these

Answer & Explanation Answer: C) star car quick demand on fat

Explanation:

Obsrving the given arrangement, we find the following pattern:
If we arrange the words in the given input in the alphabetical order and then label them as 1,2,3,4,5,6, then the last step contains the words in the order 6,1,5,2,4,3. However, the position of only one word is alteredat each step.
Input:car on star quick demand fat
Step1: star car on quick demand fat
Step2: star car quick on demand fat
Step3: star car quick demand on fat

Hence, the answer is C

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Filed Under: Sequential Output Tracing
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Q:

Mr. Karthik drives to work at an average speed of 48 km/hr. Time taken to cover the first 60% of the distance is 20 minutes more than the time taken to cover the remaining distance. Then how far is his office ?

A) 40 km	B) 50 km
C) 70 km	D) 80 km

Answer & Explanation Answer: D) 80 km

Explanation:

Let the total distance be 'x' km.

Time taken to cover remaining 40% of x distance is $t 1 = \frac{40 \times x}{100 \times 48}$

But given time taken to cover first 60% of x distance is $t 2 = t 1 + \frac{20}{60} h r s$

$t 2 = \frac{60 \times x}{100 \times 48}$

$∴ \frac{60 \times x}{100 \times 48} = \frac{40 \times x}{100 \times 48} + \frac{20}{60}$

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